Add a field in a form after creating a new column in a table

Hi,
I have searched extensively in the help menus and tutorials and maybe I have missed this, but after adding a new column to a table. How do I update the form so that when data is entered into the form it is populated in the table? Is there a tutorial or explanation of the process somewhere?
Thanks,

Hi
That has to be done manually but it is simple. Create a new item of the desired type e.g. Text Item, Select List by Right clicking on the region and select Create Page Item. A wizard will start where you will select the desired type. Press next and enter the name of the item. e.g. P3_LAST_NAME. Press Next and Enter a label for the Item. Press next and choose Source Type as Database Column when asked. Press Create button.
Hope it helps.
Zulqarnain
MaxApex Hosting
http://www.maxapex.com

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Create a new column in a table that compares the value of one column with its previous value

The DDL:
DECLARE
@T TABLE
IDNO
int,
name
varchar(40),
[Date]
datetime2,
Price1
float,
Price2
float
DECLARE
@K TABLE
IDNO
int,
name
varchar(40),
[Date]
datetime2,
Price1
float,
Price2
float
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23.335,
23.347)
INSERT
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23.369)
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INSERT
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INSERT
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INSERT
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INSERT
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INSERT
INTO @K
SELECT
ROW_NUMBER()
OVER (ORDER
by IDNO)
AS RN,*
FROM
@T
SELECT
* FROM
@K
--not working:
SELECT
a.RN,a.Price2
FROM
@K a
INNER
JOIN @K
b
ON
a.RN=b.RN-1
WHERE
a.Price2>b.Price2
I need to create a view with a column (say 'Comp' below) that compares the value of each row in Price2 with the previous Price2 row, and it is greater then +1, the
same 0, and less -1.
The processed table should be:
IDNO
name
Date
Price1
Price2
Comp
22
C_V_Harris
1/2/2014 10:23:49
23.335
23.347
0
21
C_V_Harris
1/2/2014 10:05:13
23.357
23.369
1
20
C_V_Harris
1/2/2014 9:56:15
23.364
23.377
1
19
C_V_Harris
1/2/2014 9:45:26
23.351
23.367
-1
18
C_V_Harris
1/2/2014 9:43:20
23.38
23.396
1
17
C_V_Harris
1/2/2014 9:34:28
23.455
23.468
1
16
C_V_Harris
1/2/2014 9:30:37
23.474
23.486
1
15
C_V_Harris
1/2/2014 9:18:12
23.419
23.431
-1
14
C_V_Harris
1/2/2014 9:16:06
23.36
23.374
-1
How can I structure the statement to get (the most recent - order by date ) result for Comp?

Satheesh Variath, I just had to make some corrections from your script to get the correct answer:
CREATE
VIEW vw_Comp
AS
SELECT
TOP 1 t.IDNO,t.name,t.[Date],t.Price1,t.Price2,
CASE
WHEN t.Price2
> LAG(Price2,1)
OVER (PARTITION
BY name
ORDER BY IDNO)
THEN 1
WHEN t.Price2
< LAG(Price2,1)
OVER (PARTITION
BY name
ORDER BY IDNo)
THEN -1
ELSE 0
END
AS Comp
FROM
@T t
ORDER
BY DATE
DESC
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Wes

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Smile Always

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DDL-
Create table A
( A INT,
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Mudassar

Can you try this..
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Add a field in a form after creating a new column in a table

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