Adobe - please explain how to soft proof in LR2

I have read all the messages I could find. It seems clear that LR2 has no soft proofing of my prints. And yes, I am working with a color managed screen.
So Adobe, please tell us how you intend us to soft proof our images????

>Really? "most professionals do not calibrate their monitors." I find that unbeleavable.
Me too, but I know a few working pros that simply trust their expensive monitor is good enough. Weirdly some of them will spend a long time obsessing over color (typically skin tones) but don't bother to calibrate. This just boggles my mind. Seems to work for them fine though.
>I will agree that I am getting amazing prints out of LR2
Color is great for me too. However, I identified a major, reproducible on multiple machines, resolution bug with LR 2's print module at least in the OS X version and am curious if others see it too, especially on windows.
Jao, "Loss of Sharpness Printing Actual Size from Lightroom" #15, 24 Aug 2008 11:22 pm
In short. I. Printing at native resolution by unchecking "print resolution" does not work. LR2 will still scale but to the value now shown in light grey. II. In rotated images (like a portrait format RAW on a portrait paper) LR2 calculates the resolution to send to the printer based on the wrong dimension, resulting in a far lower resolution sent to the printer than specified. LR 1.4 does not have these bugs. This also impacts the print to jpeg feature and makes the Print module in LR 2 basically useless for me as I can only trust it to do the right thing in a limited set of circumstances.

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    test@ora> -- Query 1 - using the non-equi (theta) join
    test@ora> --
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      2    select 'able' as name, 1000 as sal from dual union all
      3    select 'baker',   900 from dual union all
      4    select 'charles', 900 from dual union all
      5    select 'delta',   800 from dual union all
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      7    select 'fred',    700 from dual union all
      8    select 'george',  700 from dual union all
      9    select 'george',  700 from dual)
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    14   WHERE p1.sal >= p2.sal;
        P1_SAL P1_NAME     P2_SAL P2_NAME
          1000 able          1000 able
          1000 able           900 baker
          1000 able           900 charles
          1000 able           800 delta
          1000 able           700 eddy
          1000 able           700 fred
          1000 able           700 george
          1000 able           700 george
           900 baker          900 baker
           900 baker          900 charles
           900 baker          800 delta
           900 baker          700 eddy
           900 baker          700 fred
           900 baker          700 george
           900 baker          700 george
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           900 charles        900 charles
           900 charles        800 delta
           900 charles        700 eddy
           900 charles        700 fred
           900 charles        700 george
           900 charles        700 george
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           800 delta          700 eddy
           800 delta          700 fred
           800 delta          700 george
           800 delta          700 george
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           700 eddy           700 fred
           700 eddy           700 george
           700 eddy           700 george
           700 fred           700 eddy
           700 fred           700 fred
           700 fred           700 george
           700 fred           700 george
           700 george         700 eddy
           700 george         700 fred
           700 george         700 george
           700 george         700 george
           700 george         700 eddy
           700 george         700 fred
           700 george         700 george
           700 george         700 george
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    test@ora>This query joins PSAL with itself using a non equi-join. Take each row of PSAL p1 and see how it compares with PSAL p2. You'll see that:
    - Row 1 with sal 1000 is >= to all sal values of p2, so it occurs 8 times
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    test@ora> with psal as (
      2    select 'able' as name, 1000 as sal from dual union all
      3    select 'baker',   900 from dual union all
      4    select 'charles', 900 from dual union all
      5    select 'delta',   800 from dual union all
      6    select 'eddy',    700 from dual union all
      7    select 'fred',    700 from dual union all
      8    select 'george',  700 from dual union all
      9    select 'george',  700 from dual)
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    13         COUNT(p1.sal) as cnt_p1_sal,
    14         COUNT(DISTINCT p1.sal) as cnt_dist_p1_sal,
    15         MIN(p1.sal) as min_p1_sal,
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    18   WHERE p1.sal >= p2.sal
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           700         32         32               4        700       1000
           800          4          4               3        800       1000
           900          6          6               2        900       1000
          1000          1          1               1       1000       1000
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    test@ora>Now, if you group by p2.sal in the output of query 1, and check the number of distinct p1.sal, min of p1.sal etc. you see that for p2.sal values - 800, 900 and 1000, there are 3 or less p1.sal values associated.
    So, the last 3 rows are the ones you are interested in, essentially. As follows:
    test@ora>
    test@ora> --
    test@ora> -- Query 3 - GROUP BY and HAVING
    test@ora> --
    test@ora> with psal as (
      2    select 'able' as name, 1000 as sal from dual union all
      3    select 'baker',   900 from dual union all
      4    select 'charles', 900 from dual union all
      5    select 'delta',   800 from dual union all
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      7    select 'fred',    700 from dual union all
      8    select 'george',  700 from dual union all
      9    select 'george',  700 from dual)
    10  --
    11  SELECT p2.sal AS p2_sal,
    12         COUNT(*) as cnt,
    13         COUNT(p1.sal) as cnt_p1_sal,
    14         COUNT(DISTINCT p1.sal) as cnt_dist_p1_sal,
    15         MIN(p1.sal) as min_p1_sal,
    16         MAX(p1.sal) as max_p1_sal
    17    FROM psal p1, psal p2
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    19  GROUP BY p2.sal
    20  HAVING COUNT(DISTINCT p1.sal) <= 3;
        P2_SAL        CNT CNT_P1_SAL CNT_DIST_P1_SAL MIN_P1_SAL MAX_P1_SAL
           800          4          4               3        800       1000
           900          6          6               2        900       1000
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    test@ora>
    test@ora>That's what you are doing in that query.
    The thing is - in order to find out Top-N values, you simply need to scan that one table PSAL. So, joining it to itself is not necessary.
    A much simpler query is as follows:
    test@ora>
    test@ora>
    test@ora> --
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    test@ora> --
    test@ora> with psal as (
      2    select 'able' as name, 1000 as sal from dual union all
      3    select 'baker',   900 from dual union all
      4    select 'charles', 900 from dual union all
      5    select 'delta',   800 from dual union all
      6    select 'eddy',    700 from dual union all
      7    select 'fred',    700 from dual union all
      8    select 'george',  700 from dual union all
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    test@ora>
    test@ora>And for Top-3 distinct salaries:
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      2    select 'able' as name, 1000 as sal from dual union all
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          1000
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    test@ora>
    test@ora>You may also want to check out the RANK and DENSE_RANK analytic functions.
    RANK:
    http://download.oracle.com/docs/cd/B19306_01/server.102/b14200/functions123.htm#SQLRF00690
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    http://download.oracle.com/docs/cd/B19306_01/server.102/b14200/functions043.htm#SQLRF00633
    HTH
    isotope

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