AQ Sort Order

Question

HI
I am trying to subscribe to a topic with Sort Order (priority,enq_time) using oracle.jms API.Payload type is an ADT generated from jpublisher.Though the same worked with Oracle.AQ API.
1)After publishing i am updating the priority through sql using payload data.But the subscribing application is always taking enq_time when actually it should be taking priority as first criteria.It is still taking default priority as 1 for all so sorting by enqueue time i feel.
2)If on the other hand i set different priorities while publishing throgh client itself,subscibing application is picking up correctly .i.e priority first the enq_time.
Sample code:
===========
// Get topic object
Topic topic = ((AQjmsSession) aq.session).getTopic(
DB_AQ_ADMIN_NAME, // Queue owner
"message_queue"); // Queue name
// Create topic receiver
TopicReceiver subscriber = ((AQjmsSession) aq.session).createTopicReceiver
topic, // Used topic
"SUBSCRIPTION" + _subscriptionId, // Name and identification of the subscription
null,// No message selector
QUEUE_MESSAGE_CAFU.getFactory()//CustomDatumFactory for the java class that maps to the Oracle ADT
// Receive message
System.out.println("Waiting 60 seconds to receive message for subscription SUBSCRIPTION" + _subscriptionId + " ...");
AQjmsAdtMessage adtMessage = (AQjmsAdtMessage) subscriber.receive(60000);
if(adtMessage != null)
QUEUE_MESSAGE_CAFU messageData = (QUEUE_MESSAGE_CAFU) adtMessage.getAdtPayload();
System.out.println("receive() successfully");
// Print message
System.out.println("ProductId : " + messageData.getProductId());
System.out.println("StoreId : " + messageData.getStoreId());
System.out.println("ProductName: " + messageData.getProductName());
System.out.println("country : " + messageData.getCountry());
Note:QUEUE_MESSAGE_CAFU is JPublisher generated class from an oracle object type
Regards
Raju

Answer 1

Answers from Oracle for anyone interested:
1. Is there any way to determine the enqueue order of a set of messages?
Enqtime is only to the second.
(**) Yes the enqueue order is enqtime + step_no. So if you concat it appropriately you will get the right >order.
2. If using a queuebrowser starting at a message ID, will messages appear in
actual order even if msgids are not in order?
(**) The message will appear in the enqueue time order.
3. Is there any way, preferably a sql query, to determine the messageID of
the last message enqueued to an AQ?
You could write a query which would compute the max(enqueue_time + step_no) say something like:
select msgid from queue_table where expr(enqtime, stepno) = (select max(expr(enqtime, stepno)) from >queue_table); This is true but Oracle forgot to say that the order is guaranted only if the messages are enqueued in the same session!! if the messages are enqueued by different sessions the result is unpredictable (the enqueue time is OK but the step_no is completly wrong, that is we can have different message at the same time with the same step_no)