Built in SQL Function for Sum of Geometric Progression

Hi all,
Please let me know if there is any availble built in SQL function for
SUm of Geometric Progression.
Thanks in Advance,
Kaushik B.

and also relatively simple to write:
s = a*(1-power(r,n+1))/(1-r)
assuming you have a row with values of a,r and n (and that's the sum you need)
Jon

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    SELECT * FROM tbl where overlaps(current_time,current_time+1,current_time-1,current_time+2) = 0
    ERROR at line 1:
    ORA-06575: Package or function OVERLAPS is in an invalid state
    I do not understand why overlaps is returned as in invalid state in the query, when it was created with no errors earlier. Could anyone help me?

    Marius
    Looking at the logic you are trying to create it looks like you are looking for overlapping time periods.
    Consider two date/time ranges:
    Range 1 : T1 - T2
    Range 2 : T3 - T4
    Do they overlap?
    1) No: T1 < T4 (TRUE)  T2 > T3 (FALSE)
    T1 --- T2
               T3 --- T4
    2) Yes: T1 < T4 (TRUE)  T2 > T3 (TRUE)
    T1 ---------- T2
               T3 --- T4
    3) Yes: T1 < T4 (TRUE)  T2 > T3 (TRUE)
    T1 -------------------- T2
               T3 --- T4
    4) Yes: T1 < T4 (TRUE)  T2 > T3 (TRUE)
                   T1 ----- T2
               T3 --- T4
    5) Yes: T1 < T4 (TRUE)  T2 > T3 (TRUE)
               T1 --- T2
           T3 ------------ T4
    5) No: T1 < T4 (FALSE) T2 > T3 (TRUE)
                    T1 --- T2
           T3 --- T4Answer: Yes they overlap if:
    T1 < T4 AND T2 > T3
    So you can code the logic in your SQL as simply:
    SELECT *
    FROM tbl
    WHERE range1_start < range2_end
    AND    range_1_end > range2_startIf you go around implementing PL/SQL functions for simple logic that can be achieved in SQL alone then you cause context switching between the SQL and PL/SQL engines which degrades performance. Wherever possible stick to just SQL and only use PL/SQL if absolutely necessary.

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