Code problem - field value derived from drop down values

Question

I have a drop down with about 6 choices. The user can enter their own amount for "quantity" in the drop down if they don't want to use one of the 6 choices. The code below I've attached to another field on another page of the form. (1) I can enter my own value it displays fine. (2) If I pick the #6 option on the drop down, it displays "3000" as required. The other 5 choices however, display 1, 2, 3, 4, or 5 instead of the actual value - "100", "500" etc....
Seems to work for one of the 6 choices, but none of the rest.....
if (form1.orderPage1.stdLayout.quantity.rawValue == "1") {
this.rawValue = "1000";
if (form1.orderPage1.stdLayout.quantity.rawValue == "2") {
this.rawValue = "500";
if (form1.orderPage1.stdLayout.quantity.rawValue == "3") {
this.rawValue = "250";
if (form1.orderPage1.stdLayout.quantity.rawValue == "4") {
this.rawValue = "2000";
if (form1.orderPage1.stdLayout.quantity.rawValue == "5") {
this.rawValue = "2500";
if (form1.orderPage1.stdLayout.quantity.rawValue == "6") {
this.rawValue = "3000";
}else{
this.rawValue = form1.orderPage1.stdLayout.quantity.rawValue;
Need to learn more about "else" in Adobe JS....
As always, any help is greatly appreciated!
Mike Foster

Answer 1

Have you read your code? If your quantity value is between "1" and "5" the result value is being set correctly; then for the test for a value of "6", since your quantity value is not "6" you setting the value to the quantity value. Modify your original code to print some flow information to the JavaScirpt console and you see what is happening, be sure to open Acrobat to see the results in the JavaScript console:
/* original code */
console.show();
console.clear();
console.println("Original");
if (quantity.rawValue == "1") {
console.println(1);
this.rawValue = 1000;
if (quantity.rawValue == "2") {
console.println(2);
this.rawValue = 500;
if (quantity.rawValue == "3") {
console.println(3);
this.rawValue = 250;
if (quantity.rawValue == "4") {
console.println(4);
this.rawValue = 2000;
if (quantity.rawValue == "5") {
console.println(5);
this.rawValue = 2500;
if (quantity.rawValue == "6") {
console.println(6);
this.rawValue = 3000;
} else { // since quantity != "6" do this
console.println("Other");
this.rawValue = quantity.rawValue;
There are many ways to solve your problem. First you can nest the "if" statements, so the "else" clause is applies to all the previous "if" statements:
/* using nested if statements */
console.show();
console.clear();
console.println("Nested if then else");
if (quantity.rawValue == "1") {
console.println("1");
this.rawValue = 1000;
} else {
if (quantity.rawValue == "2") {
console.println("2");
this.rawValue = 500;
} else {
if (quantity.rawValue == "3") {
console.println("3");
this.rawValue = 250;
else {
if (quantity.rawValue == "4") {
console.println("4");
this.rawValue = 2000;
} else {
if (quantity.rawValue == "5") {
console.println("5");
this.rawValue = 2500;
} else {
if (quantity.rawValue == "6") {
console.println("6");
this.rawValue = 3000;
} else { // if none of the above
console.println("Other");
this.rawValue = quantity.rawValue;
Next you could not use an else statement at all, just do a final test for any values outside the range of "1" - "6".
/* quantity not in range */
console.show();
console.clear();
console.println("if quantity < 1 or > 6");
this.rawValue = null; // empty result field
if (quantity.rawValue == "1") {
console.println("1");
this.rawValue = 1000;
if (quantity.rawValue == "2") {
console.println("2");
this.rawValue = 500;
if (quantity.rawValue == "3") {
console.println("3");
this.rawValue = 250;
if (quantity.rawValue == "4") {
console.println("4");
this.rawValue = 2000;
if (quantity.rawValue == "5") {
console.println("5");
this.rawValue = 2500;
if (quantity.rawValue == "6") {
console.println("6");
this.rawValue = 3000;
if (quantity.rawValue < 1| quantity.rawValue > 6) { // if quantity value not between 1 and 6
console.println("Other");
this.rawValue = quantity.rawValue
And finally, you can use the "switch" statement to select an action based on the value of the quantity value and ignore the rest of the test. If no test has been selected, then perform the default action.
/* using switch on quantity value statement */
console.show();
console.clear();
switch (quantity.rawValue) {
case "1":
console.println("1");
this.rawValue = 1000;
break;
case "2":
console.println("2");
this.rawValue = 500;
break;
case "3":
console.println("3");
this.rawValue = 250;
break;
case "4":
console.println("4");
this.rawValue = 2000;
break;
case "5":
console.println("5");
this.rawValue = 2500;
break;
case "6":
console.println("6");
this.rawValue = 3000;
break;
default: // all other values
console.println("Other");
this.rawValue = quantity.rawValue
break;
} // end switch quantity