Column that have index

Question

I need to know what columns that have "ID%" and are NOT NULL from my user "TESTE" dont have a index. I used something like:
select owner, table_name, index_name from dba_indexes where owner='TESTE' and table_name in (
select table_name from ALL_TAB_COLUMNS where owner='TESTE' and COLUMN_NAME like 'ID%' and NULLABLE like 'N')
But this give what columns have, i need the opposite.
Tks,
Elber.
Message was edited by:
Elber

Answer 1

Although Sundar's solution may work in your particular case, it may be innacurate if more than one table could have a column with the same name. Fortunately, the fix for that also give you the table name "for free"
SELECT table_name, column_name
FROM all_tab_columns
WHERE owner='TESTE' and
      column_name LIKE 'ID%' and
      nullable LIKE 'N'
MINUS
SELECT table_name, column_name
FROM all_ind_columns
WHERE index_owner='TESTE' and
      column_name LIKE 'ID%'You could also just add table_name to the select list of Kedruwsky's solution.
One thing you may want to keep in mind is that both Sundar's and Kedruwsky's solutions, and my modification of Sundar's only check to see if the column is present in an index. It could be the fifth column in a seven column index.
Depending on what exactly you are looking for, you may want to consider the column_position field in all_ind_columns. If you modify the parts of the queries against all_indexes to include a predicate like:
column_position = 1it will eliminate only those columns that are on the leading edge of the index. Based on the ID% name, I suspect that you might be looking for primary keys. If that is true, you might want to replace the queries against all_ind_columns with a query against a join of all_constraints and all_cons_columns. Something like:
SELECT table_name, column_name
FROM all_tab_columns
WHERE owner='TESTE' and
      column_name LIKE 'ID%' and
      nullable LIKE 'N'
MINUS
SELECT table_name, column_name
FROM all_constraints c, all_cons_columns cc
WHERE c.constraint_name = cc.constraint_name and
      c.constraint_type = 'P' and
      c.owner='TESTE' and
      cc.column_name LIKE 'ID%' and
      cc.position = 1HTH
John