Configuring the web.xml to run Servlets
Hi,
Can i get some help to configure my web.xml file... ?
I am trying to run servlets. Do i need to map each servlet i use or can i just create a folder and map the folder. Which web.xml file do i need to change... ? And under which directory shall i place the servlet folder.
Thanks
Hi,
which server ur using ? if its tomcat then this can help u out..
u have to change the web.xml file in ur own directory.
for example u have ur directory in tomcat/webapps/<ur directory>
then in ur directory u have to create 1 WEB-INF directory and copy the web.xml file in that. another thing u have to make 2 direcotries in WEB-INF.
one is classes - u can keep ur servlets class files + ResourceProperty file
second is lib - u can keep the library files here
and u have to register ur each and every servlet in web.xml file
take care
enjoy the coading
kedar
Similar Messages
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Hello i wanna configure the web.xml that i can use sevlets and beans, but how can i do that?
This is de directorie i have installed my webapp
C:\Tomcat 4.1\webapps\testapp
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And i wanna request my servlets with the url http://localhost:8080/testapp/servlet/LogIn
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Tnxunder your web-inf
in your web.xml file you must map
the servlets
under the <web-app> tag type
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Do we need to put the following code in the web-xml for the project to run
Hi^^^,
actually I have created a project in Eclipse WTP and I am running it from remote server. Its giving me 404 error when I tried to run it.
I know 404 error is generally due to some error in deployment descriptor.
I am going through this tutorial for creating project in eclipse WTP
this says that I need to include the following code in web-xml. Please look at the quotes below
"Web modules in J2EE has a deployment descriptor where you configure the web application and its components. This deployment descriptors is called the web.xml. According to the J2EE specification, it must be located in the WEB-INF folder. web.xml must have definitions for the Servlet and the Servlet URI mapping. Enter the following lines into web.xml:"
"Listing 2. Deployment Descriptor web.xml"
<servlet>
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<url-pattern>/snoop/*</url-pattern>
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My question is, it is necessary to include the above lines between <servlet> and </servlet-mapping> in web-xml
thanks and regards,
Prashantpksingh79 wrote:
actually I have created a project in Eclipse WTP and I am running it from remote server. Its giving me 404 error when I tried to run it.
I know 404 error is generally due to some error in deployment descriptor. what's the url you've put.
<servlet>
<servlet-name>Snoop Servlet</servlet-name>
<servlet-class>org.eclipse.wtp.tutorial.SnoopServlet</servlet-class>
</servlet> Every Servlet has to have a <servlet></Servlet> tag in the web.xml
the <servlet-name>is for the naming the servlet and the <servlet-calss>is for class file of the servlet in your case the .class file is to be in the package of tutorial,if it's not then how the container will no where the calss file is
<servlet-mapping>
<servlet-name>Snoop Servlet</servlet-name>
<url-pattern>/snoop/*</url-pattern>
</servlet-mapping>You type something in your url likk http://localhost:8080/webappname (Tomcat server),so for url mapping instead of typing the entire class file name ,you just enough have to type what you've put in the <url-mapping> tag and it has to be inside of <servlet-mapping>
I think the problem is in <url-pattern> change it like /snoop<url-pattern>
My question is, it is necessary to include the above lines between <servlet> and ></servlet->mapping> in web.xmlSo now you think whether you need something inside <servlet>and </servlet-mapping> -
Can i run a servlet without a web.xml file for servlet mapping?
Hello everyone.
The code i want to run compiles and everythink looks ok.
It produces the .class file.
I run Tomcat 4.1 and i build my Web site with Dreamweaver.
I have a form in a page and i want to send the data upon form completion to a database i already have build with MySql.
The database is up and running and the server is set-up ok.
I have changed the port in Tomcat to run on port 80.
The directory i have my site is
Tomcat41\webapps\ROOT\se
and the directory where i keep the servlet class is
Tomcat41\webapps\ROOT\se\WEB-INF\servlet
I have a web.xml file to map the servlet and placed it in
Tomcat41\webapps\ROOT\se\WEB-INF
In the Form action i write action:"/servlets/Classes/GroupRegistration"
and I RECEIVE AN 404 ERROR FROM APACHE.
Somethink is wrong .
The following is the code from the GroupRegistration.java file
and follws the web.xml file.
Please Help.
import java.sql.*;
import java.io.*;
import javax.servlet.*;
import javax.servlet.http.*;
public class GroupRegistration extends HttpServlet
Connection con;
public void doPost (HttpServletRequest req, HttpServletResponse res)
throws ServletException, java.io.IOException
handleForm(req, res);
public void init() throws ServletException {
try{
/* Loading the driver for the database */
Class.forName("com.mysql.jdbc.Driver");
Connection Con = DriverManager.getConnection("jdbc:mysql://localhost/se?user=luser&password=");
catch (ClassNotFoundException e) {
throw new UnavailableException("Couldn't load JdbcOdbcDriver");
catch (SQLException e) {
throw new UnavailableException("Couldn't get db connection");
private void handleForm(HttpServletRequest req, HttpServletResponse res)
throws ServletException {
//ServletOutputStream out = res.OutputStream();
//res.setContentType("text/html");
//Extract the form Data Here
String group = req.getParameter("GroupNo");
String Name1 = req.getParameter("Name1");
String LoginID1 = req.getParameter("LoginID1");
String Name2 = req.getParameter("Name2");
String LoginID2 = req.getParameter("LoginID2");
String Name3 = req.getParameter("Name3");
String LoginID3 = req.getParameter("LoginID3");
String Name4 = req.getParameter("Name4");
String LoginID4 = req.getParameter("LoginID4");
String URL = req.getParameter("URL");
String Title2 = req.getParameter("Title2");
String date = req.getParameter("date");
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PreparedStatement pstmt = null;
try{
pstmt = con.prepareStatement(INSERT);
pstmt.executeUpdate();
catch (SQLException e) {
throw new ServletException(e);
finally {
try {
if (pstmt != null)pstmt.close();
catch (SQLException ignored){
The web.xml file
<?xml version="1.0" encoding="ISO-8859-1"?>
<web-app xmlns="http://java.sun.com.xml/ns/j2ee"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/j2ee
http://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd" version="2.4">
<servlet>
<servlet-name>GroupRegistration</servlet-name>
<servlet-class>GroupRegistration</servlet-class>
</servlet>
<servlet-maping>
<servlet-name>GroupRegistration</servlet-name>
<url-pattern>/myGroupRegistration</url-patern>
</servlet-mapping>
</web-app>
I apreciate your time.
Thanks for any help.and the directory where i keep the servlet class is
Tomcat41\webapps\ROOT\se\WEB-INF\servletOthers have pointed out that "servlet" should be "classes", but there is another mistake that hasn't been spotted. If you want your servlet to appear in the root context, you should use:
Tomcat41\webapps\ROOT\WEB-INF\classes
If you want your servlet to appear under the /se context, then you should use:
Tomcat41\webapps\se\WEB-INF\classes
and also, in the latter case, your form action should be /se/myGroupRegistration. -
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</parameter>
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<value>8</value>
</parameter>
</ResourceParams>
- Saish
"My karma ran over your dogma." - Anon -
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hi friends,
i have been working with netbeans for webapplications so far therefore its not ever been requerd to edit the web.xml file that automatically done by IDE itself.
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regards
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Hi
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and does it have any impact on deployment?
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Hi all
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The security constrains on my web.xml look like this :
<security-constraint>
<web-resource-collection>
<web-resource-name>PricelistData</web-resource-name>
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ThanassisWell you're orion-application.xml file looks okay to me, and addition if the isUserInRole is returning proper values, it's hooked up correctly.
(By the way, a useful bean/free piece of code to do just what you're doing is the JSF-Security scope as written by Duncan Mills on Sourceforge)
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As such try changing the navigation type to redirect.
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