Converting time string to integer (****) in Labview 5.1

So i'm very new to labview, learning as i go, but as the title says, i
need to convert a time string to an ineger so that it can be placed in
an integer array which will be compiled then writen to file at a
specified end ( by user ) I just want 4 digits **** to indicate
military time. And unfortuanly i'm stuck with labview 5.1. Any help would be greatly appreciated.

I believe the diagram I have attached may have been possible in LV 5.1.
Try to wire this up and see if it works.
The icons may have changed a little between LV 5.1 and 6.1.
Ben
Message Edited by Ben on 10-15-2005 02:49 PM
Ben Rayner
I am currently active on.. MainStream Preppers
Rayner's Ridge is under construction
Attachments:
Mitary Time.JPG ‏19 KB

Similar Messages

  • Time to HHMM integer in Labview 7

    I know i asked this a while ago but for labview 5, well now we have labview 7, and i can't find the function that was posted for me to try in 5. I'm trying to get the current time in just HHMM format but as an integer so that i can add it to an existing integer array. I tried playing woith the date format and the string to number fucntions and i just can't get it work.

    Since you won't be able to open the 7.1 VI, the way to find your old posts is click on your name on the left and then select the Find All Posts... link. The function Ben used can be found in the Time & Dialog palette. To find VIs in palettes, you can use the search button which should appear on the top of the palette when you open any palette.
    To learn more about LabVIEW, I suggest you try searching this site and google for LabVIEW tutorials. Here and here are a couple you can start with. You can also contact your local NI office and join one of their courses.
    In addition, I suggest you read the LabVIEW style guide and the LabVIEW user manual (Help>>Search the LabVIEW Bookshelf).
    Try to take over the world!

  • Converting time string to millisecs

    Hiya
    I have a string representing time, that i read from a file 06:30:04.271 (hr:min:sec.millisec). What would be the best way to convert this to milliseconds.
    I can also add the date if necessary: 2003-12-31
    I need to manipulate about 20,000 dates :-), so the solution needs to be efficient..
    anyideas would be much appreciated
    thnx heaps
    Osiris

    try
    SimpleDateFormat to make a Date object.
    Then Date.getTime() which will return the number of milliseconds since January 1, 1970, 00:00:00 GMT represented by this Date object.
    ciao
    jamie

  • Converting a string to integer error

    I have this code
    temp = token.nextToken().toString();
    numero = Integer.parseInt(temp);
    Is is giving me a numberFormatExeption error Knowing that temp is a string
    can anyone help

    Add the following print statement and tell us exactly what it prints out. (You will probably know what the error is once you see what it prints.=
    temp = token.nextToken().toString();
    System.out.println("temp = \"" + temp + "\"");
    numero = Integer.parseInt(temp);

  • Convert string to integer

    package onjava;
    import java.io.*;
    import java.net.*;
    import java.util.*;
    import org.apache.soap.*;
    import org.apache.soap.rpc.*;
    import java.lang.*;
    import java.sql.*;
    import javax.servlet.*;
    import javax.servlet.http.*;
    public class CalcClient extends HttpServlet {
      public void doGet(HttpServletRequest request, HttpServletResponse response)
    throws IOException, ServletException
    response.setContentType("text/html");
    PrintWriter out = response.getWriter();
    out.println("<!DOCTYPE HTML PUBLIC \"-//W3C//DTD HTML 4.01 Transitional//EN\"");
    out.println("\"http://www.w3.org/TR/html4/loose.dtd\">");
    out.println("<html>");
    out.println("<head>");
    out.println("<meta http-equiv=\"Content-Type\" content=\"text/html; charset=iso-8859-1\">");
    out.println("<title>Substraction using SOAP</title>");
    out.println("</head>");
        URL url = new URL ("http://localhost/soap/servlet/rpcrouter");
    Integer p1=request.getParameter("param1");
    Integer p2=request.getParameter("param2");
    In the above statement i have to convert the string to integer because that has to be passed in my program as an argument to a function so please let me know how to do that
        // Build the call.
        Call call = new Call();
        call.setTargetObjectURI("urn:onjavaserver");
        call.setMethodName("subtract");
        call.setEncodingStyleURI(Constants.NS_URI_SOAP_ENC);
        Vector params = new Vector();
        params.addElement(new Parameter("p1", Integer.class, p1, null));
        params.addElement(new Parameter("p2", Integer.class, p2, null));
        call.setParams (params);
        // make the call: note that the action URI is empty because the
        // XML-SOAP rpc router does not need this. This may change in the
        // future.
        Response resp = call.invoke(url, "" );
        // Check the response.
        if ( resp.generatedFault() ) {
          Fault fault = resp.getFault ();
         out.println("The call failed: ");
         out.println("Fault Code   = " + fault.getFaultCode());
         out.println("Fault String = " + fault.getFaultString());
        else {
          Parameter result = resp.getReturnValue();
          out.println(result.getValue());
    out.println("</body>");
    out.println("</html>");

    Two possibilities: Try either java.lang.Integer.valueOf() or java.text.NumberFormat and its parse method.
    Either one will do what you want. I think Integer will be the simpler of the two.
    The code you have is obviously not correct, because getParameter returns a String:
    Integer p1=request.getParameter("param1");Do it like this:
    Integer p1=Integer.valueOf(request.getParameter("param1"));%

  • Converting a string to an integer - NumberFormatException

    Hello,
    I have 2 string arrays, one that olds names and one that holds id numbers. They are both stored in a file as Strings. I then read this file into my program and put split the strings up into an array.
    I then try to convert the id to integer inside my program like so:
    public void make_array(String[] car_info) {
                    // put in arraylist and change variable type to correct ones
                    final int ID_INDEX = 0;
                    final int TYPE = 1;
                    int cust_id = 22;
                    String type;
                    //convert to correct variable types
                    try {
                            //convert to string
                            cust_id = Integer.parseInt(car_info[ID_INDEX]);   
                    } catch (NumberFormatException e) { System.out.println(e); }
                    type = car_info[TYPE];
    }I then get the errors when i try this:
    java.lang.NumberFormatException: For input string: "1"
    So the id was stored as "1", but i want to convert it to an integer value. Any ideas on why this happends? Also before i try to convert i output the id from the array and it is correct, after the conversion it is 0, obviously it is not working. But i'm not sure what is wrong.
    Any ideas?

    only works when the string is a single number suchas
    "1" or "4". If you try to use it with the input
    string as a longer one like "123" or "12" itcreates
    a NumberFormatExceptionYou must be mistaken. The value must not be what you
    think it is. Do some debugging:
    String strVal = car_info[ID_INDEX].trim();
    System.out.println("This is the number to be
    parsed -->" + strVal + "<--");
    customer_id = Integer.parseInt(strVal);That is a good idea, but it seems as though the string is fine: I did:
    gary@linuxbox# cat cars
    this output:
    1,5,Renault Clio,Small Car,25,4,false
    As you can see the number 25 is a two figure number, and it looks good. I also output the number in the java program like this:
    System.out.println("the number is ------>" + twodigitnumber + "<------");This output the number: ------->25<---------- So there doesn't seem to be any wierd spacing or characters there.

  • Convert text box string into integer

    i have an html file in which i m using a text box , for entering amount i m using that text box entry at next jsp. i want to convert amount string into integer for further processing. At next jsp i m using:-
    String amount= request.getParameter("bal");
    int ammount1= Integer.parseInt(ammount);
    and in sql query i m using amount1 as:-
    ResultSet rs1 = st.executeQuery("update saving set balance = balance - amount1 where saving.account_no = '" + acc +"'");
    my problem is i m getting following error:-
    server encountered an internal error and
    exception:- numberformat exception
    please help me as soon as possible

    int ammount1= Integer.parseInt(ammount).toString();
    good to put try block too..
    try
    int ammount1 = Integer.parseInt(ammount).toString();
    catch(NumberFormatException e)
    ...}

  • Convert from String to Int

    Hi,
    I have a question.
    How do I convert from String to Integer?
    Here is my code:
    try{
    String s="000111010101001101101010";
    int q=Integer.parseInt(s);
    answerStr = String.valueOf(q);
    catch (NumberFormatException e)
    answerStr="Error";
    but, everytime when i run the code, i always get the ERROR.
    is the value that i got, cannot be converted to int?
    i've done the same thing in c, and its working fine.
    thanks..

    6kyAngel wrote:
    actually it convert the string value into decimal value.In fact what it does is convert the (binary) string into an integer value. It's the String representation of integer quantities that have a base (two, ten, hex etc): the quantities themselves don't have a base.
    To take an integer quantity (in the form of an int) and convert it to a binary String, use the handy toString() method in the Integer class - like your other conversion, use the one that takes a radix argument.

  • Time String to Timestamp Conversion Problem

    Hi,
    I attempted to convert time string to timestamp but I failed. What is the wrong with it? I need a timestamp to create waveforms.
    Egemen
    Solved!
    Go to Solution.
    Attachments:
    Time String to Timestamp.png ‏18 KB

    You are right Gogineni, when I got the error, I was using %S in the format string for Format Date/Time String function and %3u in the format string for Scan From String.
    I found the solution in this thread - use %S%3u in both places.
    Help the forum when you get help. Click the "Solution?" icon on the reply that answers your
    question. Give "Kudos" to replies that help.

  • Problem converting U8 array to date-time string

    Hi All,
    How can I convert U8 array (time_t data type from C dll) to date time string?
    A dll function that I am calling has a structure of string, integer and time_t as one of the parameters. Instead of passing cluster, I pass an array of U8 of the size that the structure should be. All the members of the strcuture and parsed correctly except the date/time.
    Function Parameter:
    typedef struct {
    Int AlarmState ;
    Int AlarmGrade ;
    TCHAR AlarmMessage [100] ;
    time_t AlarmTimeStamp ;
    } WV_ALARM_INFO ;
    Total size = 4 + 4 + 100 + 4 = 112
    Using Call Library Function, I set the parameter type to Array of U8 and size 112.
    After the array is populated when the function is called, I have done the following to interpret date and time.
    1) Using Extract Zero Terminated String.VI I converted U8 array (of size 4) to string.
    2) Type casted string to integer (I32).
    3) Swap bytes
    4) Swap Words
    5) Format Date/Time String.
    Please see the attached screenshot for visual display of the above.
    Ideas on why the year is incorrect?
    Mimansa
    Attachments:
    Time.JPG ‏102 KB

    Hi Mimansa,
    Is it only the year that is incorrect? Also, where did you find that ABC\0 VI that you use 3 times? Did you make it or is it in a labview library somewhere?
    Thanks,
    Laura

  • How to Convert Time Stamp to String for Filename use

    I'm writing an Labview application in which I would like to convert pull time stamp infor from Time Stamp VI and convert to string so I can use to append as part of filename.
    The fomat that I want may look something like basefilename081208_1300.  This would represent a file name that has elements consisting of the date 08/12/08 and 13:00 hours zulu.
    Paul 

    Hello:
    Use the Format Date/Time String VI, and use as the format string the following: %d%m%y_%H%M
     This way you'll get the date string you want. 
    Then concatenate the output to other strings you need to name your file.
    I've attached an screenshot.
    Hope this helps.
    Robst.
    Robst - CLD
    Using LabVIEW since version 7.0
    Attachments:
    datetime string.JPG ‏20 KB

  • Convert Time Stamp to String

    What is the most efficienct way to convert a Time Stamp Control to a MM/DD/YYYY string? I am going to use its output as date parameters to a WHERE clause to a SQL Server query.
    Solved!
    Go to Solution.

    Eric1977 wrote:
    Jeff,
    I just did it like this. Do you forsee any problems?
    Well, what is the output? Do you foresee a problem? The LabVIEW Help is quite clear on the format. The very first sentence of the Help file for the Format Date Time String provide a link to the codes: http://zone.ni.com/reference/en-XX/help/371361H-01​/glang/codes_for_time_format_str/

  • When I run this VI "Waveform Time to Date Time String" in LabView 7.0 it will not pass decimals of seconds.

    When I run this VI "Waveform Time to Date Time String" in LabView 7.0 it will not pass decimals of seconds. From decimals of inputline. If i disconnect the input to the subVI "Get Date/Time string vi" it will work propperly, it also doses if I reconnect it. I use LabViev 7.0.
    So the problem i solved, but i dosent understund why it works in this way. Does it indicate other problems which will make my researchprogram unrelaible ?
    Attachments:
    Waveform_Time_to_Date_Time_String.vi ‏18 KB

    Hello.
    I checked your vi and it fails as you state.
    It runs fine if: 1 Convert number to timestamp OR
    2 Wire a constant to want seconds?
    In labview 7.1, no problems.
    I think is a job for NI engeniers.
    Hope it helps
    Alipio
    "Qod natura non dat, Salmantica non praestat"

  • Converting String to integer?

    I looked on the sun forums and only found a lot of things that convert integers to Strings. Nothing to do the opposite.
    Does anyone know how I can convert a String to an int?

    coopkev2 wrote:
    an "A" from a "B"?? I don't understand what you are saying... I want to convert "100" to 100.
    Edit-- I'll be back soon.Read "A" as "Integer" and "B" as "String".
    In this case: read the [java.lang.Integer API|http://java.sun.com/javase/6/docs/api/java/lang/Integer.html] if there is a method which takes a String and returns an Integer or int.

  • Problem in converting the String to Date with time zone GMT

    Hi,
    When I tried to convert the string 12/05/2009 to Date, the time zone is set to BST.On the other hand, for the date 12/12/2009, the time zone is set to GMT. What should I do to get the time zone as GMT all the time.?
    SimpleDateFormat formatter = new SimpleDateFormat("dd/MM/yyyy");
    String dateString = "12/05/2009";
    System.out.println(myDate.toString());

    I think you are all missing the point. java.util.Date objects always alway always store the date as the number of milliseconds since 1/1/1970 UTC so the only TimeZone they have its the implicit UTC. When you use the Date.toString() method the toString() method gets the default time zone from your environment and formats the data accordingly. This means that the same Date object will, by default, produce a different result for France and Australia and the US.
    So, if you have the date "12/5/2009" as a String then to convert it to a java.util.Date you must specify what TimeZone is implied. If it is your system time zone then you can just create a SimpleDateFormat object with the correct format and then use the parse() method to create the java.util.Date object and this will automatically be converted to UTC. If the date String represents some other time zone then you must explicitly set the time zone of the SimpleDateFormat object before parsing the string.
    The same approach applies when converting a java.util.Date object to a String. If you want anything other than your system time zone then you must explicitly tell the SimpleDateFormat what time zone you want the result formatted for.

Maybe you are looking for