Create a new line in the xml-header structure.

Question

Hi,
Can any one tell me how to create a new line in the xml-header structure.
I am doing a IDOC-XI-HTTP scenario.
Actually my mapping create this file:
<b><?xml version="1.0" encoding="utf-8"?>
<ORDERS05>
  <IDOC BEGIN="1">
    <EDI_DC40 SEGMENT="1"> </b>
The result must look like this.
<b><?xml version="1.0" encoding="utf-8"?>
<ORDERS05>
  <IDOC BEGIN="1">
    <EDI_DC40 SEGMENT="1"> </b>
Thanks and Regards,
Eren

Answer 1

Hi,
thanks for you quick answer.
I found a xsl script.
It works fine.
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" indent="yes"/>
   <xsl:template match="*">
      <xsl:param name="depth">0</xsl:param>
      <!-- New line with indenting. -->
      <xsl:if test="$depth > 0">
         <xsl:text>    </xsl:text>
      </xsl:if>
      <xsl:text>&#xA;</xsl:text>
      <xsl:element name="{name(.)}">
         <xsl:for-each select="@*">
            <xsl:attribute name="{name(.)}"><xsl:value-of select="."/></xsl:attribute>
         </xsl:for-each>
         <xsl:apply-templates>
            <xsl:with-param name="depth" select="$depth + 1"/>
         </xsl:apply-templates>
      </xsl:element>
   </xsl:template>
</xsl:stylesheet>
Best regards
Eren