Creating an XML From a Deep Structure using XSL Transformation

Question

Hi ABAPers,
I have a requirement to use XSL Transformations on an ABAP deep type structure.
Currently i have an API that fills in this deep structure and by using CALL TRANSFORMATION ID.... i will get the BIG XML having having 100s of nodes . But actualy form the deep structure i need only some NODES (say 50)... So i tried writing an XSLT
in the transaction STRANS.. but on using this TRANSFORMATION which i wrote i am getting an error messgae like INVALID XML...
Am i going in right track or is there a good solution...
My sample transformation is as below...
<xsl:transform version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:strip-space elements="*"/>
<xsl:template match="/">
<xsl:value-of select="DATA/NODE_ELEMENTS/UUID_KEY/UUID"/>
<xsl:value-of select="DATA/NODE_ELEMENTS/SEMANTICAL_NAME"/>
<xsl:value-of select="DATA/NODE_ELEMENTS/STRUCT_CAT"/>
<xsl:value-of select="DATA/NODE_ELEMENTS/USAGE_CAT"/>
<xsl:value-of select="DATA/NODE_ELEMENTS/RESTRICTED_IND"/>
<xsl:value-of select="VALUES/DATA/NODE_ID"/>.
</xsl:template>
</xsl:transform>
Please help me in solving this issue....
Thanks,
Linda.

Answer 1

Hi Linda,
    I am replying based on your sample code.
   Try the below following suggestions.
   here 'GRPHDR' is the node where I am selecting the data.
           IGRPHDR is the name of the reference.
First calling the transformation in you program.
TYPES: BEGIN OF tl_hdr,
           msgid(20)    TYPE c,
             END OF tl_hdr.
DATA : t_hdr           TYPE STANDARD TABLE OF tl_hdr.
  GET REFERENCE OF t_hdr INTO l_result_xml-value.
    l_result_xml-name = 'IGRPHDR'.
    APPEND l_result_xml TO t_result_xml.
   TRY.
        CALL TRANSFORMATION yfi_xml_read
        SOURCE XML it_xml_data
        RESULT (t_result_xml).
      CATCH cx_root INTO l_rif_ex.
        l_var_text = l_rif_ex->get_text( ).
        l_bapiret-type = 'E'.
        l_bapiret-message = l_var_text.
        APPEND l_bapiret TO errormsgs.
        EXIT.
    ENDTRY.
in XSL transformation
   First write a block of statement to specify from which node you are taking the data.
   No matter it is a node or sub-node.
<xsl:transform xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">
  <xsl:output encoding="iso-8859-1" indent="yes" method="xml" version="1.0"/>
  <xsl:strip-space elements="*"/>
<xsl:template match="/">
      <asx:abap xmlns:asx="http://www.sap.com/abapxml" version="1.0">
      <asx:values>
        <IGRPHDR>  " reference name of internal table
          <xsl:apply-templates select="//GrpHdr"/>
        </IGRPHDR>
  </asx:values>
    </asx:abap>
</xsl:template>
Next select the data from the nodes under the nodes specified in the transformation.
here msgid is the field i am selecting for value.
<xsl:template match="GrpHdr">
    <item>
      <MSGID>  " field in the internal table t_hdr where data has to go
        <xsl:value-of select="MsgId"/>
      </MSGID>
    </item>
  </xsl:template>
reply back if further clarification is needed.
Thanks and regards,
Kannan N