Decimal Format and Scientific Notation

Question

I am trying to print numbers in scientific notation using the Decimal Format class. What follows is a simple test program I wrote to find the bug. So far, I have not found a solution.
import java.text.*;
public class formatted {
public static void main (String Arguments[]) {
DecimalFormat form = new DecimalFormat("0.###E0");
     double numb = 123456.789;
     System.out.println("Nuber is: " +
form.format(numb));
The output of this program is... Nuber is: 123456E
The output is the same if numb is an int, float, or double. If I format the number as "#####.0" or "#####.00" the output is correct. I think that I am following the rules for formatting a number in scientific notation as the process is outlined in the documentation (provided below).
***** From Decimal Format under Scientific Notation ***
Numbers in scientific notation are expressed as the product of a mantissa and a power of ten, for
example, 1234 can be expressed as 1.234 x 10^3. The mantissa is often in the range 1.0 <= x < 10.0,
but it need not be. DecimalFormat can be instructed to format and parse scientific notation only via a
pattern; there is currently no factory method that creates a scientific notation format. In a pattern,
the exponent character immediately followed by one or more digit characters indicates scientific
notation. Example: "0.###E0" formats the number 1234 as "1.234E3".
Anyone understand how the short program is incorrectly written?
Marc

Answer 1

The problem is
format = "0.###E0"
input number = 123456.789
output = 123456E (not scientific notation!)
This is not scientific notation at all. There is no decimal point given and no value in the exponent.
I understand entirely that by adding more #'es will provide more precision. The bug I have is the output is not printed in the scientific format; other formats work.
MArc