Delete X number of lines from files

I am trying to find a way (either through an extension or
some other third-party freeware) to remove a number of lines from
the beginning of my files and replace them with alternate code.
I know that in many cases, a Search and Replace would do the
trick. But in my case, the lines that I want replaced do not
exactly match. For example, I might want to remove the first 15
lines from the beginning of each file in question; however, I might
have three lines of code in the files that each set a variable
value, with that value being different in each file. Thus, as far
as I understand it, the DW Search and Replace would not work for
me.
Even if I have can just find some way to first strip the
lines of code out without replacing it with the new code I want,
that would be fine. Adding in the new code afterwards would not be
an issue.
Any help would be very much appreciated. Thank you very much.
James

On Mon, 7 May 2007 17:14:52 +0000 (UTC), "MUSC Webmaster"
<[email protected]> wrote:
> Gary: Thanks for the suggestion; however it wasn't quite
working for me.
>After your posting, I played around for a bit with
regular expressions and the
>best that I could do was get an expression (^.*\r) that
grabbed all of the
>first line, with the "r" representing a carriage return
as opposed to a line
>feed. If I try to expand on that expression, the search
results come up with
>nothing.
Actually the linfeed is the \n in my suggestion. The ^
designates the
beginning of the string.
Are you on a Mac? I tested it and it worked correctly on my
windows
machine. Come to think of it, I have my line feeds set to
Unix because
that's what my web server uses. You can try replacing the \n
with \r or
\n\r depending on which line feed you're using:
^.*\r.*\r.*\r.*\r.*\r.*\r.*\r.*\r.*\r.*\r.*\r.*\r.*\r.*\r.*\r
or:
^.*\r\n.*\r\n.*\r\n.*\r\n.*\r\n.*\r\n.*\r\n.*\r\n.*\r\n.*\r\n.*\r\n.*\r\n.*\r\n.*\r\n.*\r\ n
One of the three should work.
Gary

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