Detecting and converting line feeds

hello,
I want to convert the 'enters' from a text field to <br>'s in the html code later on...
I tried using a breakIterator, but this doesn't seem to work too well...
Any ideas how this is done?

hello,
I want to convert the 'enters' from a text field to
<br>'s in the html code later on...
I tried using a breakIterator, but this doesn't seem
to work too well...
Any ideas how this is done?Depends on platform... For Unices it is "\r", for windowses "\r\n" for Macs "\n" - so you have to know platform specific details. Why you can't replace platform specific linefeeds to <br>s?
Pavel

Similar Messages

  • Folder action to find and replace text and change line feeds

    I want to use a folder action to find and replace text and change Mac carriage returns to DOS line feeds inside text files.
    The text to be replaced is: "/Users/wim/Music/iTunes/iTunes Music/Music" (without the quotes)
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    I have found the following two perl commands to achieve this:
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    What I want to do is drop the exported playlists in M3U format in a folder so that the folder action will remove the right text and change the carriage returns.
    My questions are:
    Is it possible to make a folder action that executes command line commands instead of shell scripts?
    What is the correct syntax for the two commands when used in a folder action shell script? Especially, how do I escape the slashes (/) in the string to be removed?
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    Ok, I've include an applescript to run a shell command. The applesript command quoted form makes a string that will end up as a single string on the bash command line.  Depending on what you want to do, you may need multiple string on the bash command lines.  I've included some information on folder actions.
    It is easier to diagnose problems with debug information. I suggest adding log statements to your script to see what is going on.  Here is an example.
        Author: rccharles
        For testing, run in the Script Editor.
          1) Click on the Event Log tab to see the output from the log statement
          2) Click on Run
        For running shell commands see:
        http://developer.apple.com/mac/library/technotes/tn2002/tn2065.html
    on run
        -- Write a message into the event log.
        log "  --- Starting on " & ((current date) as string) & " --- "
        --  debug lines
        set desktopPath to (path to desktop) as string
        log "desktopPath = " & desktopPath
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        end try
    end run
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  • How to find a carriage return and Line feed?

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    Hi Stefano,
    So you Basically want to do content conversion at the receiver end and that is basically to get the entire data in one line.For that please go through these links below.It clearly explains your requirement.
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  • Converting strings with line feeds to a single line with identifying chars

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  • Find the LINE FEED and replace it.

    Hi
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  • Mail attachment generated in UDF in SAP PI 7.1 - Issue with line feed

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    Your ideas are really welcome!
    Best regards
    Dirk

    Hi,
    as I found this in wikipedia:
    Another common problem is the use of '\n' when communicating using an Internet protocol that mandates the use of ASCII CR+LF for ending lines. Writing '\n' to a text mode stream works correctly on Windows systems, but produces only LF on Unix, and something completely different on more exotic systems. Using "\r\n" in binary mode is slightly better, as it works on many ASCII-compatible systems, but still fails in the general case. One approach is to use binary mode and specify the numeric values of the control sequence directly, "\x0D\x0A".
    Back to my issue:
    In the UDF I am adding "\r\n" but only the "\n" seems to survive!
    In Mapping test line feeds are available and the lines are shown as expected.
    Using Notepad ++ to open the created txt file from the mail shows that LF is in the file at each end of line but CR is missing.
    CR is only at the end of the last line in the file and is not from the UDF that creates the mail or the UDF that creates the attachment lines. Seems that this is added somewhere else behind the mapping.
    This is what I found in galileo computing
    (http://www.galileocomputing.de/glossar/gp/anzeige-11241/FirstLetter-Z, SORRY, only available in german language!):
    In Parsing of XML-Documents the XML-Parser changes the end of line delimiter internally in general to a simple line feed (LF, #0A) as usual in UNIX. ..... In Windows this could result in problems with readability of  source texts (e.g. in Notepad) which can be solved by choosing the right editor.
    My target application is on Windows and not able to "choose" the right editor (PI system is on windoes OS too) !
    But Im wondering where the CR at the end of the text comes from when all the \r\n will be replaced with \n as described.
    Ideas are really welcome!
    Best regards
    Dirk
    Edited by: Meinhard Dirk on May 31, 2011 2:45 PM

  • Best way to remove last line-feed in text file

    What is the best way to remove last line-feed in text file? (so that the last line of text is the last line, not a line-feed). The best I can come up with is: echo -n "$(cat file.txt)" > newfile.txt
    (as echo -n will remove all trailing newline characters)

    What is the best way to remove last line-feed in text file? (so that the last line of text is the last line, not a line-feed). The best I can come up with is: echo -n "$(cat file.txt)" > newfile.txt
    (as echo -n will remove all trailing newline characters)
    According to my experiments, you have removed all line terminators from the file, and replaced those between lines with a space.
    That is to say, you have turned a multi-line file into one long line with no line terminator.
    If that is what you want, and your files are not very big, then your echo statement might be all you need.
    If you need to deal with larger files, you could try using the 'tr' command, and something like
    tr '
    ' ' ' <file.txt >newfile.txt
    The only problem with this is, it will most likely give you a trailing space, as the last newline is going to be converted to a space. If that is not acceptable, then something else will have to be arranged.
    However, if you really want to maintain a multi-line file, but remove just the very last line terminator, that gets a bit more complicated. This might work for you:
    perl -ne '
    chomp;
    print "
    " if $n++ != 0;
    print;
    ' file.txt >newfile.txt
    You can use cat -e to see which lines have newlines, and you should see that the last line does not have a newline, but all the others still do.
    I guess if you really did mean to remove all newline characters and replace them with a space, except for the last line, then a modification of the above perl script would do that:
    perl -ne '
    chomp;
    print " " if $n++ != 0;
    print;
    ' file.txt >newfile.txt
    Am I even close to understanding what you are asking for?

  • Losing Line-feed in XML parsing (XMLTRANSFORM) or File output (clob2file)?

    Hi all, need some help please!
    I'm using a xslt file to transferm a XML file into a txt format file. Within the XSLT file, there is a carriage-return (<xsl:text>
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    Thanks in advance!
    -Jane
    Edited by: user9084567 on Feb 1, 2010 1:45 PM
    Edited by: user9084567 on Feb 1, 2010 1:47 PM
    Edited by: user9084567 on Feb 1, 2010 1:48 PM

    A_non,
    After a few testing, I can identify the CRLF was lost in XMLTRANSFORM. I had read your other thread related to this, and try to run this sample code:
    /* Formatted on 2010/02/03 15:32 (Formatter Plus v4.8.8) */
    DECLARE --Local variables here
    v_xml XMLTYPE
    := XMLTYPE
    ('<
    offers xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:noNamespaceSchemaLocation="xsd.xsd"><
    submit type="DAM" date="2007-03-28" name="MKTPART1" mode="NORMAL"/><
    offer name="Jamestown" flag="true" version_no="1.0"><
    standing date="2007-03-29" type="WED"/><
    identifier external_id="523736560"/><
    /offer><
    /offers>'
    v_xslt XMLTYPE
    := XMLTYPE
    ('<
    xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0"> <
    xsl:output method="text"/> <
    xsl:variable name="new_line" select="''&#xA;''" /> <
    xsl:template match="/"> <
    xsl:value-of select="/offers/offer/...name"/><
    xsl:value-of select="$new_line" /><
    xsl:value-of select="/offers/submit/...date"/><
    xsl:value-of select="$new_line" /><
    xsl:value-of select="/offers/offer/standing/...date"/><
    xsl:value-of select="$new_line" /><
    xsl:value-of select="/offers/offer/standing/...type"/><
    xsl:value-of select="$new_line" /><
    /xsl:template><
    /xsl:stylesheet>'
    BEGIN -- Test statements here
    DBMS_OUTPUT.put_line (XMLTYPE.transform (v_xml, v_xslt).getstringval ());
    END;
    But come out these error:
    Error at line 2
    ORA-31011: XML parsing failed
    ORA-19202: Error occurred in XML processing
    LPX-00230: invalid character 10 (U+000A) found in a Name or Nmtoken
    Error at line 4
    ORA-06512: at "SYS.XMLTYPE", line 310
    ORA-06512: at line 2
    Can not figure out why. Try to use this <xsl:variable name="new_line" select="''& # x A ;''" /> inside my style sheet, but it seems not taking it. Not too sure what's exactly should be the quotes for "''& # x A ;''" (w/o space). If I used doub quote + two single quotes, it returns error, LPX-00601: Invalid token in: ' '; if I used single quote + double quote, it did not bring in CRLF at all.
    Any input?
    Thanks in advance.

  • What is escape character for for Carriage Return, Line Feed, Form Feed

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    uncle_alice wrote:
    jverd wrote:
    remus.dragos wrote:
    I forgot that it does not exist in Java. A good thing
    from my point of view.Running the following makes my computer beep.
    public class Bell {
    public static void main(String... args) {
    System.out.println("\u0007");
    Sure, sending a BEL character to the console rings the bell, but that has nothing to do with Java. Anyway, I think he meant Java doesn't support the \a escape sequence in string and char literals.
    >
    >
    >I forgot that it does not exist in Java. A good thing
    from my point of view.
    Running the following makes my computer beep.
    public class Bell {
    public static void main(String... args) {
    System.out.println("\u0007");
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    Ah, I thought he was saying Java doesn't support ringing the bell.

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