Display rows to columns

User require a report having the following column data should be populated in column instead of row.
how can i modify or where should i modify to get the required output below. the following query is in XML file
select awd.award_id,
                    award_number,
          bond_name,
          p2b.bond_id bond_id,
          nvl(b.par_amount,0)+nvl(b.premium,0)+nvl(b.original_issue_discount,0)+nvl(b.bic,0) Total_proceeds,
          p2b.earnings_proceeds earning_procs,
          nvl(b.original_issue_discount,0)+nvl(b.bic,0) issuance_cost
          FROM   xxdl.xxdl_cd_bond_setup_new b,
                  (select bond_id,
                    effective_date,nvl(earnings_proceeds,0) earnings_proceeds
                                from (
                     select s.*,
                               row_number() over(partition by bond_id order by effective_date desc) rn
                       from XXDL.xxdl_cd_bond_schedk_p2b s
            where rn = 1) p2b,
                  gms_awards_all awd
                    WHERE b.bond_id= p2b.bond_id(+)
                    AND b.award_id = awd.award_id(+)
                    AND b.award_id = decode(:P_award_num,null,b.award_id,:P_award_num)
Actual output
award_id   award_number bond_name bond_id       Total_proceeds              issuance_cost
345     XI         ABC            null                 100           40
234     XIIA        DEF             null                 86                      100
Expected output
345     234
XI     XIIA
ABC     DEF
null       null
100           86
40             100Edited by: 893185 on Nov 9, 2011 4:14 PM

4. How do I convert rows to columns?
SQL and PL/SQL FAQ

Similar Messages

Need help in displaying Rows to Columns

Hi,
I am facing problem in displaying Rows to Columns
I am using pivot function:
select *
from
(select vendor_name
from tablea)
pivot
(count(vendor_name)
for vendor_name in ('a,b,'c'));
its working fine showing vendor_name and count
but when i want to display the output as:(How to include the Salalry column in the query?)
Name:{a b c}
Sal Total:(400,600,800}
Any help will be needful for me

Not sure what you mean:
select *
from (select deptno,sal from emp)
pivot(sum(sal) for deptno in (10,20,30))
10 20 30
8750 10875 9400
SQL> SY.

Can anybody help....SQL to display row as column and column as rows

Can anybody help in writing a SQL to display row as column and column as rows?
Thanks

check this link:
Re: Creating Views - from rows to a new column?

How to display Rows as Columns in JSF?

I am using dataTable component to get data for my Menu, i have one column in it which returns me the data, because its automatically adding <tr> and <td> tags to it, its showing data in tabular form.
I want to show output Horizontally instead of Vertically the way its showing.
Is their any way i can display Rows as Columns?
Code:
==============================================
<div class="bodyarea">
<div id="location">
<h:dataTable value="#{menuItem.breadCrumb}" var="bread" >
<f:verbatim><ol></f:verbatim>
<h:column>
<f:verbatim><li></f:verbatim>
<h:outputLink id="crumbID" value="#{bread.menuLink}">
<h:outputText id="crumpName" value="#{bread.menuLabel}"/>
</h:outputLink>
<f:verbatim></li></f:verbatim>
</h:column>
<f:verbatim></ol></f:verbatim>
</h:dataTable>
</div>
</div>
Thank you

Table is not the html element for you, in this situation.
I would use a dataList component (distributed with myfaces implementation).
dataList is able to return a list of item, and using css you will be able display in a horizontal grid. (otherwise you can use layout="grid" in dataList).
Anyway...my impression is that who made JSF was not really understanding how a html programmer like to write his code.
Why do JSF gives us only the possibility to write list of items throught tables?
Why do JSF prints error messages throught tables?
Why div is not a standard component?
This is an incredible lack...
I see also other incredible lasks...but they don't concern html ;) .

Displaying Row and Column Numbers

I see through other research on Oracle SQL Developer that I should be able to display the row and column numbers on version 1.5.4, but I don't see where to go to turn this on. Suggestions?

Suggestions?Ask in the SQL Developer forum?

How to display row to columns without using pivot keyword

hi,
could someone help me how to dispaly rows into columns without using pivot keyword and actuall my scenario is,iam having two tables with names and sample data is shown below
ID PROJECT MID MINAME TASKID TASKNAME
1     PROJ1     1     AA     100     PR1_TASK1
1     PROJ1     3     CC     102     PR1_TASK3
1     PROJ1     4     DD     103     PR1_TASK4
1     PROJ1     5     EE     104     PR1_TASK5
1     PROJ1     6     FF     105     PR1_TASK6
2     PROJ2     5     EE     114     PR2_TASK1
2     PROJ2     6     FF     115     PR2_TASK2
2     PROJ2     7     GG     116     PR2_TASK3
2     PROJ2     8     HH     117     PR2_TASK4
2     PROJ2     9     JJ     118     PR2_TASK5
2     PROJ2     10     KK     119     PR2_TASK6
2     PROJ2     1     AA     120     PR2_TASK7
The output should display project and count of tasks in particular milestone as shown below
project AA BB CC DD EE FF GG HH JJ KK
1 2 0 1 5 3 2 0 2 1 0
2 1 2 0 2 1 0 2 4 3 1
Thanks in advance ,
vvr

WITH t1 AS
(SELECT 1 ID,
         'PROJ1' PROJECT,
         1 MID,
         'AA' MINAME,
         100 TASKID,
         'PR1_TASK1' TASKNAME
    FROM DUAL
UNION
SELECT 1, 'PROJ1', 3, 'CC', 102, 'PR1_TASK3'
    FROM DUAL
UNION
SELECT 1, 'PROJ1', 4, 'DD', 103, 'PR1_TASK4'
    FROM DUAL
UNION
SELECT 1, 'PROJ1', 5, 'EE', 104, 'PR1_TASK5'
    FROM DUAL
UNION
SELECT 1, 'PROJ1', 6, 'FF', 105, 'PR1_TASK6'
    FROM DUAL
UNION
SELECT 2, 'PROJ2', 5, 'EE', 114, 'PR2_TASK1'
    FROM DUAL
UNION
SELECT 2, 'PROJ2', 6, 'FF', 115, 'PR2_TASK2'
    FROM DUAL
UNION
SELECT 2, 'PROJ2', 7, 'GG', 116, 'PR2_TASK3'
    FROM DUAL
UNION
SELECT 2, 'PROJ2', 8, 'HH', 117, 'PR2_TASK4'
    FROM DUAL
UNION
SELECT 2, 'PROJ2', 9, 'JJ', 118, 'PR1_TASK5'
    FROM DUAL
UNION
SELECT 2, 'PROJ2', 10, 'KK', 119, 'PR1_TASK6'
    FROM DUAL
UNION
SELECT 2, 'PROJ2', 1, 'AA', 120, 'PR1_TASK7' FROM DUAL)
SELECT id project,
       NVL((SELECT mid
             FROM t1
            WHERE miname = 'AA'
              AND id = t_out.id),
           0) AA,
       NVL((SELECT mid
             FROM t1
            WHERE miname = 'BB'
              AND id = t_out.id),
           0) BB,
       NVL((SELECT mid
             FROM t1
            WHERE miname = 'CC'
              AND id = t_out.id),
           0) CC,
       NVL((SELECT mid
             FROM t1
            WHERE miname = 'DD'
              AND id = t_out.id),
           0) DD,
       NVL((SELECT mid
             FROM t1
            WHERE miname = 'EE'
              AND id = t_out.id),
           0) EE,
       NVL((SELECT mid
             FROM t1
            WHERE miname = 'FF'
              AND id = t_out.id),
           0) FF,
       NVL((SELECT mid
             FROM t1
            WHERE miname = 'GG'
              AND id = t_out.id),
           0) GG,
       NVL((SELECT mid
             FROM t1
            WHERE miname = 'HH'
              AND id = t_out.id),
           0) HH,
       NVL((SELECT mid
             FROM t1
            WHERE miname = 'JJ'
              AND id = t_out.id),
           0) JJ,
       NVL((SELECT mid
             FROM t1
            WHERE miname = 'KK'
              AND id = t_out.id),
           0) KK
FROM (SELECT DISTINCT id FROM t1) t_out
PROJECT     AA     BB     CC     DD     EE     FF     GG     HH     JJ     KK
1     1     0     3     4     5     6     0     0     0     0
2     1     0     0     0     5     6     7     8     9     10As I understand, you want MID of MINAMEs displayed ? But output is not like yours.. What is exactly your requirements?

Display Rows as Columns

Hi,
Can anyone help, I have some rows that I am trying to display as columns.
The sample data is below:
create table c(
ID NUMBER,
SCHEDULE_NO NUMBER,
TERM_NO NUMBER,
FREQUENCY VARCHAR2(20),
RENTAL_AMOUNT NUMBER,
RENTAL_OS NUMBER);
INSERT INTO C VALUES(001, 1, 2, 'Monthly', 458, 3);
INSERT INTO C VALUES(001, 1, 3, 'Monthly', 268.33, 7);
INSERT INTO C VALUES(001, 1, 4, 'Monthly', 88.21, 12);
INSERT INTO C VALUES(001, 1, 5, 'Monthly', 757.42, 35);
INSERT INTO C VALUES(002, 1, 7, 'Monthly', 101.22, 3);
INSERT INTO C VALUES(002, 1, 8, 'Yearly', 55, 2);
I would like to display only 1 line per ID, e.g.
001 - Row
SCHEDULE_NO, TERM_NO, FREQUENCY, RENTAL_AMOUNT, RENTAL_OS - Columns
I will need a new column to be displayed for each line split,
e.g. 001, schedule_no1, term_no1, frequency1...
001, schedule_no2, term_no2, frequency2...
001, schedule_no3, term_no3, frequency3...
It would be like a pivot table but split for each change in line.
Thanks

This work ...
select * from (
select id,
        SCHEDULE_NO,
        TERM_NO,
        FREQUENCY,
        RENTAL_AMOUNT,
        RENTAL_OS
   from c)
pivot (max(SCHEDULE_NO) SCHEDULE_NO,
       max(TERM_NO) TERM_NO,
       max(FREQUENCY) FREQUENCY,
       max(RENTAL_AMOUNT) RENTAL_AMOUNT,
       max(RENTAL_OS) RENTAL_OS
for (SCHEDULE_NO,TERM_NO,FREQUENCY,RENTAL_AMOUNT,RENTAL_OS)
IN (
    (1, 2 , 'Monthly' , 458, 3 ) SCHEDULE_NO1,
    (1, 3 , 'Monthly' , 268.33 , 7 ) SCHEDULE_NO2,
    (1, 4 , 'Monthly' , 88.21 , 12 ) SCHEDULE_NO3,
    (1, 5 , 'Monthly' , 757.42 , 35 ) SCHEDULE_NO4,
    (1, 7 , 'Monthly' , 101.22 , 3 ) SCHEDULE_NO5,
    (1, 8 , 'Yearly' , 55     , 2 ) SCHEDULE_NO6
    )

Looking for SQL to Display Rows as Columns in a View

Hi!
I am using Oracle 10g (10.1.0.4.0) 64 bit on Red Hat Enterprise Linux AS release 3.
I have the following tables:
Table A
A_ID number (primary key)
Table B
B_ID number (primary key)
B_NAME varchar2
B_DESC varchar2
Table C
C_ID number (primary key)
B_ID number (foreign key to table B)
A_ID number (foreign key to table A)
ORDERING number
A row in table A can have from 0 (zero) to 3 (three) rows in table C associated with it.
I am trying to make a view that displays A.A_ID and its associated rows from table C as a single row. For example, the following query:
select A.A_ID, C.B_ID, B.B_NAME, B.B_DESC, C.ORDERING
from C, B, A
where C.A_ID = A.A_ID
   and C.B_ID = B.B_IDYields the following results:
A_ID B_ID B_NAME B_DESC ORDERING
100   10 A      One    1
100   20 B      Two    2
100   30 C      Three 3I would like to get the following:
A_ID B_NAME_1 B_NAME_2 B_NAME_3
100 A        B        CThanks (in advance :-),
Avi.

SQL> CREATE TABLE dt_test_a(a_id number)
2 /
Table created.
SQL> CREATE TABLE dt_test_b(b_id number, b_name varchar2(1),b_desc varchar2(10))
2 /
Table created.
SQL> CREATE TABLE dt_test_c(c_id number, b_id number, a_id number, ordering number)
2 /
Table created.
SQL>
SQL> insert into dt_test_a values(100)
2 /
1 row created.
SQL> insert into dt_test_b values(10, 'A','One')
2 /
1 row created.
SQL> insert into dt_test_b values(20, 'B','Two')
2 /
1 row created.
SQL> insert into dt_test_b values(30, 'C','Three')
2 /
1 row created.
SQL> insert into dt_test_c values(1, 10, 100, 1)
2 /
1 row created.
SQL> insert into dt_test_c values(2, 20, 100, 2)
2 /
1 row created.
SQL> insert into dt_test_c values(3, 30, 100, 3)
2 /
1 row created.
SQL>
SQL> SELECT
2     a.a_id,
3     DECODE(c.ordering, 1, b.b_name) b_name_1,
4     DECODE(c.ordering, 2, b.b_name) b_name_2,
5     DECODE(c.ordering, 3, b.b_name) b_name_3
6 FROM
7     dt_test_a a,
8     dt_test_b b,
9     dt_test_c c
10 WHERE
11     a.a_id = c.a_id
12 AND
13     b.b_id = c.b_id
14 /
     A_ID B B B
      100 A
      100   B
      100     C
SQL>
SQL> SELECT
2     a.a_id,
3     MAX(DECODE(c.ordering, 1, b.b_name)) b_name_1,
4     MAX(DECODE(c.ordering, 2, b.b_name)) b_name_2,
5     MAX(DECODE(c.ordering, 3, b.b_name)) b_name_3
6 FROM
7     dt_test_a a,
8     dt_test_b b,
9     dt_test_c c
10 WHERE
11     a.a_id = c.a_id
12 AND
13     b.b_id = c.b_id
14 GROUP BY
15     a.a_id
16 /
     A_ID B B B
      100 A B C
SQL>
SQL>
SQL> insert into dt_test_a values(200)
2 /
1 row created.
SQL> insert into dt_test_b values(40, 'A','One')
2 /
1 row created.
SQL> insert into dt_test_b values(50, 'B','Two')
2 /
1 row created.
SQL> insert into dt_test_b values(60, 'C','Three')
2 /
1 row created.
SQL> insert into dt_test_c values(4, 40, 200, 3)
2 /
1 row created.
SQL> insert into dt_test_c values(5, 50, 200, 2)
2 /
1 row created.
SQL> insert into dt_test_c values(6, 60, 200, 1)
2 /
1 row created.
SQL>
SQL> SELECT
2     a.a_id,
3     MAX(DECODE(c.ordering, 1, b.b_name)) b_name_1,
4     MAX(DECODE(c.ordering, 2, b.b_name)) b_name_2,
5     MAX(DECODE(c.ordering, 3, b.b_name)) b_name_3
6 FROM
7     dt_test_a a,
8     dt_test_b b,
9     dt_test_c c
10 WHERE
11     a.a_id = c.a_id
12 AND
13     b.b_id = c.b_id
14 GROUP BY
15     a.a_id
16 /
     A_ID B B B
      100 A B C
      200 C B A

Display rows into columns in table

Hi,
I have a table name Ebiz_Upgrade_Task_Status. Here in table there are 8 rows of data with
pro_id,pobj_id,cemli_id and confirmation.
I am trying to convert all the CONFIRMATION into column wise using the query below
SELECT
PRO_ID,
POBJ_ID,
CEMLI_ID,
max(decode(rownum,1,CONFIRMATION,null)) "CP1",
max(decode(rownum,2,CONFIRMATION,null)) "CP2",
max(decode(rownum,3,CONFIRMATION,null)) "CP3",
max(decode(rownum,4,CONFIRMATION,null)) "CP4"
FROM Ebiz_Upgrade_Task_Status
GROUP BY PRO_ID,POBJ_ID,CEMLI_ID
Am able to see first 2 rows of data as columns, and not able to see the next rows. Please suggest me in modifyin the query
tabel strutuce and data
pro_id obj_id cemli_id confirmation
1 2 3 Yes
1 2 3 No
1 2 3 NA
11 22 33 Yes
11 22 33 NO
11 22 33 NA
Please suggest me in modifying the code
Thanks
Sudhir

Thanks for posting more details.
Using rownum caused your confirmation fields to be null:
SQL> select * from temp1;
   PRO_ID   POBJ_ID CEMLI_ID CONFIRMATION
      111       222       333 yes
      111       222       333 no
      111       222       333 na
       11        22        33 na
       11        22        33 no
       11        22        33 yes
6 rows selected.
SQL> col cp1 format a10
SQL> col cp2 format a10
SQL> col cp3 format a10
SQL> select pro_id
2 ,      pobj_id
3 ,      cemli_id
4 ,      max(decode(rownum,1,confirmation,null)) "cp1"
5 ,      max(decode(rownum,2,confirmation,null)) "cp2"
6 ,      max(decode(rownum,3,confirmation,null)) "cp3"
7 from   temp1
8 group by pro_id
9 ,        pobj_id
10 ,        cemli_id;
   PRO_ID   POBJ_ID CEMLI_ID cp1        cp2        cp3
       11        22        33
      111       222       333 yes        no         na
SQL> select pro_id
2 ,      pobj_id
3 ,      cemli_id
4 ,      max(decode(confirmation, 'yes',confirmation,null)) "cp1"
5 ,      max(decode(confirmation, 'no',confirmation,null)) "cp2"
6 ,      max(decode(confirmation, 'na',confirmation,null)) "cp3"
7 from   temp1
8 group by pro_id
9 ,        pobj_id
10 ,        cemli_id;
   PRO_ID   POBJ_ID CEMLI_ID cp1        cp2        cp3
       11        22        33 yes        no         na
      111       222       333 yes        no         na
SQL>

How to display rows as columns?

Hi,
I am simulating my problem with the following example.
I have two tables, book_info contains book_id(primary key), book_name and the other table is author_info contains id(primary key), book_id and author. One book may have maximum upto THREE authors.
BOOK_INFO
=========
book_id category book_name
1 a ABC
2 a PQR
3 b XYZ
AUTHOR_INFO
===========
id book_id author
1 1 aaaaaa
2 1 bbbbbb
3 1 cccccc
4 2 pppppp
5 2 qqqqqq
6 3 xxxxxx
I need output like different columns using a sql query WHERE category = 'a'.
book_id book_name author1 author2 author3
1 ABC aaaaaa bbbbbb cccccc
2 PQR pppppp pppppp
We are using Oracle 9i/NT environment. Urgent please.
Thank you.

Vijaya,
Looks like I just answered this question, though your table layout is pretty much the same. Here what I said ...
There actually is a couple ways to do this, but the term is called FLATTENING. The method I like is with a function and a view (I'm a huuuuge fan of views). It has some draw backs performance wise if doing this on allot of data, but the results are well worth it. Anyway the code is below. The table is T1, the view it makes is V1. The function is called FN_REC_FLAT. Some sample output is also included.
16:46:11 SQL> SELECT T1.N1,T1.N2,T1.C1 FROM TABLE_NAME_HERE T1 ORDER BY T1.N1,T1.N2;
N1 N2 C1
-1 1 TEST
1 1 THIS
1 2 IS RECORD
1 3 NUMBER 1.
2 1 THIS IS
2 2 RECORD
2 3 NUMBER 2.
3 1 AND THIS
3 2 IS RECORD
3 3 NUMBER 3.
10 rows selected.
CREATE OR REPLACE FUNCTION
FN_REC_FLAT(PI_FLAT_KEY IN NUMBER,PS_FLAT_DATA IN VARCHAR)
RETURN VARCHAR AS
CURSOR CUR_T1 IS SELECT * FROM TABLE_NAME_HERE T1 WHERE T1.N1 = PI_FLAT_KEY ORDER BY T
REC_T1 TABLE_NAME_HERE%ROWTYPE;
LS_FLAT_DATA VARCHAR2(2000);
LS_RETURN VARCHAR2(2000);
BEGIN
LS_FLAT_DATA := NULL;
OPEN CUR_T1;
FETCH CUR_T1 INTO REC_T1;
WHILE CUR_T1%FOUND LOOP
LS_FLAT_DATA := (LS_FLAT_DATA || ' ' || REC_T1.C1);
FETCH CUR_T1 INTO REC_T1;
END LOOP;
LS_RETURN := TRIM(LS_FLAT_DATA);
RETURN LS_RETURN;
END;
Function created.
CREATE OR REPLACE VIEW V1 (N1,C1) AS SELECT DISTINCT T1.N1,FN_REC_FLAT(T1.N1,T1.C1) FROM TABLE_NAME_HERE T1;
View created.
16:46:12 SQL>
16:46:12 SQL> SELECT T1.N1,T1.C1 FROM V1 T1 ORDER BY T1.N1,T1.C1;
N1 C1
-1 TEST
1 THIS IS RECORD NUMBER 1.
2 THIS IS RECORD NUMBER 2.
3 AND THIS IS RECORD NUMBER 3.
16:46:12 SQL>
Note that the function takes in N1 as the root level for the flatten key. N2 is the sort order. In you case this would be EMP_ID and EMP_INFO_SEQ_NUM. The C1 is EMP_INFO. T1 is the table alias and TABLE_NAME_HERE ... well I'll let you figure that part out ;).
Hope this helps,
Tyler D.

Sql to display rows like columns

Hi,
I am having table with 3 columns i.e col1, col2, col3
and the values are :
col1 col2 col3
1 11 A
1 11 B
1 11 C
2 22 P
2 22 Q
2 22 R
2 22 S
I require the output from the above data as follows :
1 11 A B C
2 22 P Q R S
rows of col3 to be converted into column.
Please suggest to get the about output thru SQL.
Thanks
Ramesh

Ok, but you're not gonna like it.... (ignore the bit above the select statment as that is just setting up the test data)
with t as (select 1 as col1, 11 as col2, 'a' as col3 from dual union
           select 1, 11, 'b' from dual union
           select 2, 22, 'j' from dual union
           select 2, 22, 'k' from dual union
           select 2, 22, 'l' from dual union
           select 2, 33, 'v' from dual)
select col1, col2, max(col3_1)||max(col3_2)||max(col3_3)||max(col3_4)||max(col3_5)||max(col3_6)||max(col3_7)||max(col3_8)||max(col3_9)||max(col3_10) col3
from (
        select col1, col2, decode(row_number() over (partition by col1, col2 order by col1, col2), 1, col3, null) col3_1, null col3_2, null col3_3, null col3_4, null col3_5, null col3_6, null col3_7, null col3_8, null col3_9, null col3_10 from t union
        select col1, col2, null col3_1, decode(row_number() over (partition by col1, col2 order by col1, col2), 2, col3, null) col3_2, null col3_3, null col3_4, null col3_5, null col3_6, null col3_7, null col3_8, null col3_9, null col3_10 from t union
        select col1, col2, null col3_1, null col3_2, decode(row_number() over (partition by col1, col2 order by col1, col2), 3, col3, null) col3_3, null col3_4, null col3_5, null col3_6, null col3_7, null col3_8, null col3_9, null col3_10 from t union
        select col1, col2, null col3_1, null col3_2, null col3_3, decode(row_number() over (partition by col1, col2 order by col1, col2), 4, col3, null) col3_4, null col3_5, null col3_6, null col3_7, null col3_8, null col3_9, null col3_10 from t union
        select col1, col2, null col3_1, null col3_2, null col3_3, null col3_4, decode(row_number() over (partition by col1, col2 order by col1, col2), 5, col3, null) col3_5, null col3_6, null col3_7, null col3_8, null col3_9, null col3_10 from t union
        select col1, col2, null col3_1, null col3_2, null col3_3, null col3_4, null col3_5, decode(row_number() over (partition by col1, col2 order by col1, col2), 6, col3, null) col3_6, null col3_7, null col3_8, null col3_9, null col3_10 from t union
        select col1, col2, null col3_1, null col3_2, null col3_3, null col3_4, null col3_5, null col3_6, decode(row_number() over (partition by col1, col2 order by col1, col2), 7, col3, null) col3_7, null col3_8, null col3_9, null col3_10 from t union
        select col1, col2, null col3_1, null col3_2, null col3_3, null col3_4, null col3_5, null col3_6, null col3_7, decode(row_number() over (partition by col1, col2 order by col1, col2), 8, col3, null) col3_8, null col3_9, null col3_10 from t union
        select col1, col2, null col3_1, null col3_2, null col3_3, null col3_4, null col3_5, null col3_6, null col3_7, null col3_8, decode(row_number() over (partition by col1, col2 order by col1, col2), 9, col3, null) col3_9, null col3_10 from t union
        select col1, col2, null col3_1, null col3_2, null col3_3, null col3_4, null col3_5, null col3_6, null col3_7, null col3_8, null col3_9, decode(row_number() over (partition by col1, col2 order by col1, col2), 10, col3, null) col3_10 from t
      ) t
group by col1, col2
      COL1       COL2 COL3
         2         33 v
         1         11 ab
         2         22 jkl
SQL>

Display rows as columns in crystal

Hello,
I am using crystal reports version 9 and i have a requirement as below.
main report has a sub report in the page header section and the sub report gets data of the customer names linked to the customer in main report.
my sub report output currently shows as
NAME A
NAME B
but i want it to appear as NAME A, NAME B so that all the customer names appear in a line instead of seaprate rows on the report. is there a way to do this?
Thanks in advance for your help.

Suppress the detail section, and use this formula to concatenate all of the values (basic syntax):
WhilePrintingRecords
global nameList as string
if len(nameList) = 0 then
nameList = {db.name}
else
nameList = nameList + ", " + {db.name}
end if
formula = ""
Then in the subreport's footer, print the names:
WhilePrintingRecords
global nameList as string
formula = nameList
HTH,
Carl

Displaying rows as columns and coumns as rows?

Can we do this?
Thanks.

Can we do this?Yes.
Google it and you will find HOW to do it.

Pivoting rows into columns in Oracle 10g

Hi,
I want to pivot rows into column in some optimal way.
I don't want to go with the DECODE option as the number of columns can be more than 200.
i have also tried the transpose logic which is making the pl/sql block too huge.
can i directly query the database for the desired output instead of storing the data into some arrays and displaying rows as columns?

Hi,
Here's a dynamic way to do this is Oracle 10, using theSQL*Plus @ command to handle the dynamic parts.
First, let's see how we would do this using a static query:
WITH     col_cntr    AS
     SELECT     column_name
     FROM     all_tab_columns
     WHERE     owner          = 'FKULASH'
     AND     table_name     = 'TEST_EMP'
     AND     column_name     NOT IN ('EMP_ID', 'TYPE_VAL')
,     unpivoted_data     AS
     SELECT     e.type_val
     ,     c.column_name
     ,     CASE c.column_name
              WHEN 'X_AMT' THEN x_amt     -- ***** Dynamic section 1 *****
              WHEN 'Y_AMT' THEN y_amt     -- ***** Dynamic section 1 *****
              WHEN 'Z_AMT' THEN z_amt     -- ***** Dynamic section 1 *****
          END     AS v
     FROM          test_emp e
     CROSS JOIN     col_cntr c
SELECT       column_name     AS type_val
,       SUM (CASE WHEN type_val = 'Q1' THEN v ELSE 0 END)     AS q1     -- ***** Dynamic section 2 *****
,       SUM (CASE WHEN type_val = 'Q2' THEN v ELSE 0 END)     AS q2     -- ***** Dynamic section 2 *****
,       SUM (CASE WHEN type_val = 'Q3' THEN v ELSE 0 END)     AS q3     -- ***** Dynamic section 2 *****
,       SUM (CASE WHEN type_val = 'Q4' THEN v ELSE 0 END)     AS q4     -- ***** Dynamic section 2 *****
FROM       unpivoted_data
GROUP BY column_name
ORDER BY column_name
;Column names are hard-coded in two places:
(1) in the sub-query unpivoted_data, we had to know that there were 3 columns to be unpivoted, and that they were called x_amt, y_amt and z_amt. You want to derive all of that from all_tab_columns.
(2) in the main query, we had to know that there would be 4 pivoted columns in the rsult set, and that they would be called q1, q2, q3 and q4. You want to derive all that from the data actually in test_emp.
Instead of hard-coding those 2 dynamic sections, have Preliminary Queries write them for you, a split second before you run the main query, by running this script:
-- Before writing sub-scripts, turn off features designed for human readers
SET     FEEDBACK    OFF
SET     PAGESIZE    0
PROMPT ***** Preliminary Query 1 *****
SPOOL     c:\temp\sub_script_1.sql
SELECT    '              WHEN '''
||       column_name
||       ''' THEN '
||       LOWER (column_name)     AS txt
FROM       all_tab_columns
WHERE       owner          = 'FKULASH'
AND       table_name     = 'TEST_EMP'
AND       column_name     NOT IN ('EMP_ID', 'TYPE_VAL')
ORDER BY column_name
SPOOL     OFF
PROMPT     ***** Preliminary Query 2 *****
SPOOL     c:\temp\sub_script_2.sql
SELECT DISTINCT ',       SUM (CASE WHEN type_val = '''
||                type_val
||           ''' THEN v ELSE 0 END)     AS '
||           LOWER (type_val)         AS txt
FROM           test_emp
ORDER BY      txt
SPOOL     OFF
-- After writing sub-scripts, turn on features designed for human readers
SET     FEEDBACK    5
SET     PAGESIZE    50
-- Main Query:
WITH     col_cntr    AS
     SELECT     column_name
     FROM     all_tab_columns
     WHERE     owner          = 'FKULASH'
     AND     table_name     = 'TEST_EMP'
     AND     column_name     NOT IN ('EMP_ID', 'TYPE_VAL')
,     unpivoted_data     AS
     SELECT     e.type_val
     ,     c.column_name
     ,     CASE c.column_name
              @c:\temp\sub_script_1
          END     AS v
     FROM          test_emp e
     CROSS JOIN     col_cntr c
SELECT       column_name     AS type_val
@c:\temp\sub_script_2
FROM       unpivoted_data
GROUP BY column_name
ORDER BY column_name
;As you can see, the main query looks exactly like the static query, except that the two dynamic sections have been replaced by sub-scripts. These 2 sub-scripts are written by 2 prelimiary queries, right before the main query.
As others have said, the fact that you're asking this question hints at a poor table design. Perhaps the table should be permanently stored in a form pretty much like unpivoted_data, above. When you need to display it with columns x_amt, y_amt, ..., then pivot it, using GROUP BY type_col. When you need to display it with columns q1, q2, ..., then pivot it using GROUP BY column_name.

Changeing the rows into columns..

Hello Experts,
I have a one requirement which is display rows as columns
for Example:
material
plant
quantity
amount
1000
100
30
60
200
50
100
300
60
120
2000
200
50
100
300
60
120
400
32
64
3000
100
40
80
400
20
40
I need output like this below..
material
100
200
300
400
1000
30
50
60
90
100
120
2000
50
60
32
100
120
64
3000
40
20
80
40
I created the ALV table dynamically using at end of event..
but I am getting the
material
100
200
300
400
1000
30
50
60
90
100
120
2000
60
32
120
64
3000
20
40
the values are missing ..?
I wrote like this:
LOOP AT lt_final INTO ls_final.
    ASSIGN COMPONENT 'matnr' OF STRUCTURE <dyn_wa> TO <fs1>.
     <fs1> = ls_final-matnr.
     ASSIGN COMPONENT ls_final-vkorg OF STRUCTURE <dyn_wa> TO <fs1>.
     <fs1> = ls_final-qunaty.
     ASSIGN COMPONENT ls_final-vkorg OF STRUCTURE <dyn_wa> TO <fs1>.
     <fs1> = ls_final-amount.
     AT END OF matnr.
       APPEND <dyn_wa> TO <dyn_table>.
       CLEAR : <dyn_wa>.
     ENDAT.
   ENDLOOP.

I have written a snippet whose output is:
Take a look at the snippet.
TYPES:
BEGIN OF ty,
a1 TYPE char10,
a2 TYPE char10,
a3 TYPE char10,
a4 TYPE char10,
END OF ty,
BEGIN OF ty2,
a1 TYPE char10,
100 TYPE char10,
200 TYPE char10,
300 TYPE char10,
400 TYPE char10,
no TYPE char10,
END OF ty2.
DATA: lt TYPE TABLE OF ty,
      ls TYPE ty,
      lt2 TYPE TABLE OF ty2,
      ls2 TYPE ty2,
      lr TYPE REF TO cl_salv_table.
FIELD-SYMBOLS: <lv>   TYPE char10,
               <ls2> TYPE ty2.
*material   plant   quantity amount
ls-a1 = 1000.
ls-a2 = 100. ls-a3 = 30. ls-a4 = 60. APPEND ls TO lt.
ls-a2 = 200. ls-a3 = 50. ls-a4 = 100. APPEND ls TO lt.
ls-a2 = 300. ls-a3 = 60. ls-a4 = 120. APPEND ls TO lt.
ls-a1 = 2000.
ls-a2 = 200. ls-a3 = 50. ls-a4 = 100. APPEND ls TO lt.
ls-a2 = 300. ls-a3 = 60. ls-a4 = 120. APPEND ls TO lt.
ls-a2 = 400. ls-a3 = 32. ls-a4 = 64. APPEND ls TO lt.
ls-a1 = 3000.
ls-a2 = 100. ls-a3 = 40. ls-a4 = 80. APPEND ls TO lt.
ls-a2 = 400. ls-a3 = 20. ls-a4 = 40. APPEND ls TO lt.
TRY.
    LOOP AT lt INTO ls.
*     index 1 for filling quantity in a3 field
      READ TABLE lt2 ASSIGNING <ls2>
          WITH KEY a1 = ls-a1
                    no = 1.
      IF sy-subrc NE 0.
        APPEND INITIAL LINE TO lt2 ASSIGNING <ls2>.
        <ls2>-a1 = ls-a1. <ls2>-no = 1.
      ENDIF.
      ASSIGN COMPONENT ls-a2 OF STRUCTURE <ls2> TO <lv>.
      <lv> = ls-a3.
*     index 2 for filling quantity in a4 field
      READ TABLE lt2 ASSIGNING <ls2>
          WITH KEY a1 = ls-a1
                    no = 2.
      IF sy-subrc NE 0.
        APPEND INITIAL LINE TO lt2 ASSIGNING <ls2>.
        <ls2>-a1 = ls-a1. <ls2>-no = 2.
      ENDIF.
      ASSIGN COMPONENT ls-a2 OF STRUCTURE <ls2> TO <lv>.
      <lv> = ls-a4.
    ENDLOOP.
    cl_salv_table=>factory(
      IMPORTING
        r_salv_table   = lr
      CHANGING
        t_table        = lt2
    lr->display( ).
CATCH cx_root.
ENDTRY.

Display rows to columns

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