Displaying all rows if value is blank

Hi all trying I am trying to display all the rows from a
database if the default value is blank
I have tried to put a * or ? in the php code What could be
wrong here?
What do I need to put for the variable section for the
correct syntax
As it its
Name = p
Type = numeric
Default value = -1
Run-Time value $_Get[‘p’]
Cat = is the Variable to select the rows if a value is
present
$p_Recordset_B = "-1";
if (isset($_GET['p'])) {
$p_Recordset_B = (get_magic_quotes_gpc()) ? $_GET['p'] :
addslashes($_GET['p']);
SELECT Company FROM Table WHERE Cat = %s <> 'NULL'
ORDER BY RAND() LIMIT 70

I am also having this problem, except I have a search form with a list that contains 3 options "Select Country", "Canada", and "U.S." and if a user leaves the field as "Select Country" I want the results page to show the records for both Canada and US, is there a value that can be entered into the Default Value field?
All help is appreciated.

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user12252618 wrote:
My Question is when I want to display multiple recoreds the rows are splits many time and displaying recoreds are combersome to understand, so please give me the solution about this problem.
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<snip>
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