Extracting Images from EPS - Problem with the Output

Question

Hello,
I got a big problem extracting images from an EPS, which has been made in InDesign. The image does not appear correct.
Source code:
%ALDImageFileName: Speicher:image.jpg
%ALDImageDimensions: 30 30
%ALDImageCropRect: 0 0 30 30
%ALDImageCropFixed: 0 0 30 30
%ALDImagePosition: 203.8677 344.8913 203.8677 359.2913 218.2677 359.2913 218.2677 344.8913
%ALDImageType: 4 8
%%BeginObject: image
[14.4 0 0 14.4 203.868 344.891 ]ct
snap_to_device
Adobe_AGM_Image/AGMIMG_fl cf /ASCII85Decode fl /RunLengthDecode filter ddf
<<
/T 1
/W 30
/H 30
/M[30 0 0 -30 0 30 ]
/BC 8
/D[0 1 0 1 0 1 0 1 ]
/DS [
[AGMIMG_fl 30 string /rs cvx /pop cvx] cvx
[AGMIMG_fl 30 string /rs cvx /pop cvx] cvx
[AGMIMG_fl 30 string /rs cvx /pop cvx] cvx
[AGMIMG_fl 30 string /rs cvx /pop cvx] cvx
/O 3
>>
%%BeginBinary: 1
img
p&G-p!<E*"!<<3"!!!&i!!30$!Vl`q!V$-m!WW3&!r`0#!Wh]h!!20]!WW3$qZ$^!!!!&f!!30$!WE'!
!WE'$!<<*#nc/[l!W<!#!WW3%h>dNVnGiXl!<<-)!!*'"!<<2f!<*$!!<3)a!!!&t!!*-%kl:\ar;Zm"
!!2He#6G2G(D[>Z!<*#e!!WKUEK,/l!r`0"!V$.!!Wi?'-t[mD-NjDN!!2Zk!!3#u"T\]4$OR%8!!!&h
!!<6)*\I@D!\,8pq>g3h%KQP0';ta-rr2ho&-2b3mf3Y*Q/q,jk2D[9"76'h!=o#B!Y,22n,Nn!!!=Q!
0.ee,0/"XS!VHHl!!E<'!"[l]rrUsd!Ug!r&'a/!k3(mej38#8mJm8&'`/UF'`J.(!"8l.+"o,p/hSe-
/M8.8!!<6%!i#Yn!<2rs!2Ao^$NZFPk2tpjkND!jP3r;O%29TU'`o-b%e'H-!=:8,0/"h-.kN>(.gkeH
"T^(Js8W&srrE$$rr;gE!V-4"""*$ljlY^djQYmmi$\'q!W`9(p([Q1nc/dn!#@(:r[nC..kE8)/emgU
!<IHErs8W(rr<#trr76B!:p1!CZadBk2kmhj65^iD"%E-$5O?k'`&OE$M"0,!<<uh0.ee0/h\e,/h.k2
!!*+arVm-$s8W)us8J2U!;Z[(L?.U[kN:sflf@0hK^f$D!=T\>'a5?f'c%2YnGit6/1iM*/1iA*.kWFi
nc/dn!I+SBqYpWrrcdo5!<N60C$4[@ki_*hl0.?lD".K0!=9MV'c%S_'`f!Vnc01&!!t50/M8P+/h8J)
.gH+F!!+PDrVllsrVlrp.KT,@#QauQip#Ifk3*$4ki:gb-3Nc<$j.4Z'GV>s'bqJt('F(,%06GL/hJ_.
.k<;..j"f]!!32!rql]tr;WMmmf3c`k2tsgk2tmikEZ,Kn,NJ!'`/UJ'G_,X!V-6i!=L8*/2&S./M&=P
!!2Ti"9AV]s8N#t"o\JY&c_t$!"-g0j6,RdkNBr!!r2ii!!!]1'a,9f'*84(!"Ar/""YuT/M8Y)!WW3$
nc0%!!!!Z$s8N#ts76`i!"T,3!!3\bl0.?qjkC7H!!;`lrW!!#!>PMJ!u;Ub!Ug$f!=JlU/M/S*/ggZ#
!!2Ng$3K)as8N&tjT#8]m/R@3k2b[ck03)j!>?4H'`\p6!!**(r[e6p.kWIZmJm:h!#kk:#.sp7ru_:B
mJmV6jQ>U%kN:kH!!!)h!!!'!'`\gE'`eC:mf3^r!=pb8/ds9_.h;[J!!u[*s8GIerr6%#m/RGck3(kk
kNM&%!Up'o!<<*)'bhDfrY5G=!Vufj!"K#0!#mOB.0(kM0,afj!V$-u!<A8^s6B[Es8S8_!U]poKBMCG
!7'`iKECN@#RhF_'*&[\'b'X5r;[9-!$a!F*W[<7.jP)q!V-4#!<<,As8T>(W;lnB!!!&g!"63skFhmD
jlEuS!!2Ng#S7^d%KHtR'bTm7!s/H(/-mj['`\n!/1Ukk!"985s8@'?Du]k7%KHP#!"8l0$KC71C'%l,
jl$a?!!<6%!!3'6!X\o6rY5J8!!2Qh#Ri::0*_I`/1U`S%.4)q5Q:Zg2ukf6s8P=a!V$-t!]]?)jY?ff
kN:qhmJmFp()7Pf!!N99!!Vcj$l1NL.KKPM/1iIi!!3'!o`,F%!dakFpBL[$pAb/A!Up's!H@5cf`qK\
hWF!BmJmV%'GV;_!!*`J'FFm3!!WH(!?WpE,Q7ZH+tP;f!!2foq>^W-s8Tn6!!L"8s0r.!!">[bkcXsf
!3>;FU]CPd!!<]G'bL?E!tZ.^&+9K$!\#`P)?'U>'eM$g!!2Zk!W`9$$g.KhLB.ATL&_2?"7Q9n!RU)n
I/X*KGN@l9"Rc<t',;8j!!!$,'bhAP!!WQ+!"US5%fQG1%PKFQn,NUm!*fL'9)\en8,rO]!V-4"!rrBu
jQ/].!WYOLl&b?6"9AcD'aFX;"9oSU%0>nt$NV(q!rr<%"YC_q"7Z@"!<<+Eq@Wc/!#,C9"9&;k!!E?)
D;u0+!!<qtS-&0["T\T'$5EXA!!33:%da5t!<<]/!!3u<!V$-o!<<*#!FZ$-!!A;d!!2ipq#CKu!<?7$
!!WK)KEM8T"RZ6i$2so,!<<Q0li77k!!30$!<</h!!!'!!!E<'!!!&c!"8o/!!*'#"98E'!WW;h!!!'!
!!NB'!<<*#n,N[o!<<*#!!!'!!!!&f!!E<&!!*-"!!!'!!!**%o)K!s!!*-$!<<*#!!<-"!Wi?&l2Ueb
rVup!q#Gp~>
%%EndBinary
%%EndObject
Orginal image Size 553,9 KB
After decoding the size is only 1,8 KB
First try.
public class ASCII85Decode {
private ByteBuffer buf;
* initialize the decoder with byte buffer in ASCII85 format
private ASCII85Decode(ByteBuffer buf) {
this.buf = buf;
* get the next character from the input.
* @return the next character, or -1 if at end of stream
private int nextChar() {
// skip whitespace
// returns next character, or -1 if end of stream
while (buf.remaining() > 0) {
char c = (char) buf.get();
if (!isWhiteSpace(c)) {
return c;
// EOF reached
return -1;
public static boolean isWhiteSpace(int c) {
return (c == ' ' || c == '\t' || c == '\r' || c == '\n'
|| c == 0 || c == 12);
// 0=nul, 12=ff
* decode the next five ASCII85 characters into up to four decoded
* bytes.  Return false when finished, or true otherwise.
* @param baos the ByteArrayOutputStream to write output to, set to the
*        correct position
* @return false when finished, or true otherwise.
private boolean decode5(ByteArrayOutputStream baos)
throws PDFParseException {
// stream ends in ~>
int[] five = new int[5];
int i;
for (i = 0; i < 5; i++) {
five[i] = nextChar();
if (five[i] == '~') {
if (nextChar() == '>') {
break;
} else {
throw new PDFParseException(
"Bad character in ASCII85Decode: not ~>");
} else if (five[i] >= '!' && five[i] <= 'u') {
five[i] -= '!';
} else if (five[i] == 'z') {
if (i == 0) {
five[i] = 0;
i = 4;
} else {
throw new PDFParseException(
"Inappropriate 'z' in ASCII85Decode");
} else {
throw new PDFParseException(
"Bad character in ASCII85Decode: " + five[i]
+ " (" + (char) five[i] + ")");
if (i > 0) {
i -= 1;
int value = five[0] * 85 * 85 * 85 * 85 + five[1] * 85 * 85
* 85 + five[2] * 85 * 85 + five[3] * 85 + five[4];
for (int j = 0; j < i; j++) {
int shift = 8 * (3 - j);
baos.write((byte) ((value >> shift) & 0xff));
return (i == 4);
* decode the bytes
* @return the decoded bytes
private ByteBuffer decode() throws PDFParseException {
// start from the beginning of the data
buf.rewind();
// allocate the output buffer
ByteArrayOutputStream baos = new ByteArrayOutputStream();
// decode the bytes
while (decode5(baos)) {
return ByteBuffer.wrap(baos.toByteArray());
* decode an array of bytes in ASCII85 format.
* <p>
* In ASCII85 format, every 5 characters represents 4 decoded
* bytes in base 85.  The entire stream can contain whitespace,
* and ends in the characters '~&gt;'.
* @param buf the encoded ASCII85 characters in a byte buffer
* @param params parameters to the decoder (ignored)
* @return the decoded bytes
public static ByteBuffer decode(ByteBuffer buf)
throws PDFParseException {
ASCII85Decode me = new ASCII85Decode(buf);
return me.decode();
2. Try
public class Ascii85Decode {
private final FileOutputStream fos;
private Ascii85Decode() throws FileNotFoundException {
File f = new File("/home/markus/1/test/bild.jpg");
fos = new FileOutputStream(f);
@Override
protected void finalize() throws Throwable {
fos.close();
super.finalize();
public static byte[] decode(byte[] in) throws FileNotFoundException, IOException {
Ascii85Decode ascii85Decode = new Ascii85Decode();
ascii85Decode.setData(in);
ascii85Decode.decode85();
return null;
static long pow85[] = {85 * 85 * 85 * 85, 85 * 85 * 85, 85 * 85, 85, 1};
private byte[] in;
private void setData(byte[] in) {
this.in = in;
void wput(long tuple, int bytes) throws IOException {
switch (bytes) {
case 4:
putchar((int) (tuple >> 24));
putchar((int) (tuple >> 16));
putchar((int) (tuple >> 8));
putchar((int) tuple);
break;
case 3:
putchar((int) (tuple >> 24));
putchar((int) (tuple >> 16));
putchar((int) (tuple >> 8));
break;
case 2:
putchar((int) (tuple >> 24));
putchar((int) (tuple >> 16));
break;
case 1:
putchar((int) (tuple >> 24));
break;
void decode85() throws IOException {
long tuple = 0;
int c, count = 0;
int i=0;
for (;;) {
switch (c = in[i]) {
default:
if (c < '!' || c > 'u') {
System.err.println("%s: bad character in ascii85 region: %#o\n");
System.exit(1);
tuple += (c - '!') * pow85[count++];
if (count == 5) {
wput(tuple, 4);
count = 0;
tuple = 0;
break;
case 'z':
if (count != 0) {
System.err.println("%s: z inside ascii85 5-tuple\n");
System.exit(1);
putchar(0);
putchar(0);
putchar(0);
putchar(0);
break;
case '~':
if (in[i+1] == '>') {
if (count > 0) {
count--;
tuple += pow85[count];
wput(tuple, count);
c = in[i+1];
return;
System.err.println("%s: ~ without > in ascii85 section\n");
System.exit(1);
case '\n':
case '\r':
case '\t':
case ' ':
case '\0':
case '\f':
case '\b':
case 0177:
break;
i++;
private void putchar(int l) throws IOException {
//System.out.write(l);
fos.write(l);
Does anybody have an idea to solve the problem?

Answer 1

A scan from string function can be used as per the attachment. The double \ ('\\') is in the format string in order to interpret the '\' characters in your input string as literal characters and not special formatting.
Message Edited by Dennis Knutson on 07-10-2006 03:53 PM
Attachments:
Scan From String.JPG ‏5 KB