Finding 5 most recent records for each customer with abnormal order amounts

The database consists of the following tables:
create table dbo.customer (
customer_id int identity primary key clustered,
customer_name nvarchar(256) not null
create table dbo.purchase_order (
purchase_order_id int identity primary key clustered
customer_id int not null,
amount money not null,
order_date date not null
Implement a query for the report that will provide the following information: for each customer output at most 5 different dates which contain
abnormally high or low amounts (bigger or less than 3 times SDTDEV from AVG), for each of these dates output minimum and maximum amounts as well.
Possible result: http://triontp.pop3.ru/333.gif

amount Not Between stdev_amt - 3 * avg_amt And stdev_amt + 3 * avg_amt
vice versa.
amount Not Between avg_amt - 3 * stdev_amt And avg_amt + 3 * stdev_amt)

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Select most recent DATE for an ID.

Hi All,
I need to SELECT the records with the most recent DATE for each ID. A DATE range is part of the selection criteria.
My data.
MY_ID MY_DATE
1684662 26-JAN-09
1424097 27-JAN-09
1684663 27-JAN-09
1684664 27-JAN-09
1684672 28-JAN-09
0689073 28-JAN-09
1052476 21-JAN-09
1052476 21-JAN-09
1360828 23-JAN-09
1684661 23-JAN-09
1052476 30-JAN-09
1052476 30-JAN-09
1052476 30-JAN-09
1052476 30-JAN-09
The code below works fine when selecting 1 ID in the SUBSELECT, but with multiple ID it still selects rownum=1 (of course). This as far as my thinking takes me.
SELECT my_id,
my_date
FROM
(SELECT my_id,
my_date
FROM my_table
ORDER BY my_date DESC
WHERE rownum = 1
AND *{color:#ff0000}my_id = 1052476{color}*
AND TO_CHAR(my_date,'YYYY/MM/DD') BETWEEN '2009/01/01' AND '2009/01/31';
If I could somehow pass the SELECT ID into the SUBSELECT WHERE clause I should have this done.
Any suggestions?
Thank You in Advance for Your help,
Lou

One of many possible soultions.
ME_XE?with data as
2 (
3     select 1684662 as id, to_date('26-JAN-09','dd-mon-yyyy') as the_date from dual union all
4     select 1424097 as id, to_date('27-JAN-09','dd-mon-yyyy') as the_date from dual union all
5     select 1684663 as id, to_date('27-JAN-09','dd-mon-yyyy') as the_date from dual union all
6     select 1684664 as id, to_date('27-JAN-09','dd-mon-yyyy') as the_date from dual union all
7     select 1684672 as id, to_date('28-JAN-09','dd-mon-yyyy') as the_date from dual union all
8     select 0689073 as id, to_date('28-JAN-09','dd-mon-yyyy') as the_date from dual union all
9     select 1052476 as id, to_date('21-JAN-09','dd-mon-yyyy') as the_date from dual union all
10     select 1052476 as id, to_date('21-JAN-09','dd-mon-yyyy') as the_date from dual union all
11     select 1360828 as id, to_date('23-JAN-09','dd-mon-yyyy') as the_date from dual union all
12     select 1684661 as id, to_date('23-JAN-09','dd-mon-yyyy') as the_date from dual union all
13     select 1052476 as id, to_date('30-JAN-09','dd-mon-yyyy') as the_date from dual union all
14     select 1052476 as id, to_date('30-JAN-09','dd-mon-yyyy') as the_date from dual union all
15     select 1052476 as id, to_date('30-JAN-09','dd-mon-yyyy') as the_date from dual union all
16     select 1052476 as id, to_date('30-JAN-09','dd-mon-yyyy') as the_date from dual
17 )
18 select id, the_date
19 from
20 (
21     select id, the_date, max(the_date) over (partition by id) as max_the_date
22     from data
23 )
24 where the_date = max_the_date;
                ID THE_DATE
            689073 28-JAN-0009 12 00:00
           1052476 30-JAN-0009 12 00:00
           1052476 30-JAN-0009 12 00:00
           1052476 30-JAN-0009 12 00:00
           1052476 30-JAN-0009 12 00:00
           1360828 23-JAN-0009 12 00:00
           1424097 27-JAN-0009 12 00:00
           1684661 23-JAN-0009 12 00:00
           1684662 26-JAN-0009 12 00:00
           1684663 27-JAN-0009 12 00:00
           1684664 27-JAN-0009 12 00:00
                ID THE_DATE
           1684672 28-JAN-0009 12 00:00
12 rows selected.
Elapsed: 00:00:00.03

How to select Most recent record with rest of record in ascending order...?

Dear Expert,
I have one table called Tab1 & have a lot columns. For this schenario, i mentioned few of the columns.
The columns are
product_type varchar2(100),
curr_date date (storing with time stamp),
other1_cloumn varchar2(10),
other2_cloumn varchar2(10)
Now I want to display all the records in ascending order except most recent record for every product_type || Union all || Most recent records in ascending order in single query.
For example...
product_type curr_date date other1_cloumn other2_cloumn
1, "10-May-2005 10:10:10", 10, 10
1, "10-May-2005 10:10:11", 10, 10
1, "10-May-2005 10:10:12", 10, 10
1, "10-May-2005 10:10:09", 10, 10
2, "10-May-2005 10:10:10", 10, 10
2, "10-May-2005 10:10:11", 10, 10
2, "10-May-2005 10:10:12", 10, 10
2, "10-May-2005 10:10:09", 10, 10
3, "10-May-2005 10:10:10", 10, 10
3, "10-May-2005 10:10:11", 10, 10
3, "10-May-2005 10:10:12", 10, 10
3, "10-May-2005 10:10:09", 10, 10
Now I want to display (OUTPUT) like...
1, "10-May-2005 10:10:10", 10, 10
1, "10-May-2005 10:10:11", 10, 10
1, "10-May-2005 10:10:09", 10, 10
2, "10-May-2005 10:10:10", 10, 10
2, "10-May-2005 10:10:11", 10, 10
2, "10-May-2005 10:10:09", 10, 10
3, "10-May-2005 10:10:10", 10, 10
3, "10-May-2005 10:10:11", 10, 10
3, "10-May-2005 10:10:09", 10, 10
1, "10-May-2005 10:10:12", 10, 10
2, "10-May-2005 10:10:12", 10, 10
3, "10-May-2005 10:10:12", 10, 10
Plz, provide a solution....

I want to display like...
select * from tab1 where (product_type,curr_date) in
(select product_type,max(curr_date) from tab1 group by product_type)
order by product_type
Union All
(select * from tab1 where (product_type,curr_date) NOT IN
(select product_type,max(curr_date) from tab1 group by product_type)
order by product_type)
But, In the above case, The ORDER BY Clause will not work...How to get this one...?
I mean.. I want to display all the records in ascending order except Most recent record base on Product type and next I want to display Most recent record in ascending order. I want to display both cases in a single query...?

SQL help: return number of records for each day of last month.

Hi: I have records in the database with a field in the table which contains the Unix epoch time for each record. Letz say the Table name is ED and the field utime contains the Unix epoch time.
Is there a way to get a count of number of records for each day of the last one month? Essentially I want a query which returns a list of count (number of records for each day) with the utime field containing the Unix epoch time. If a particular day does not have any records I want the query to return 0 for that day. I have no clue where to start. Would I need another table which has the list of days?
Thanks
Ray

Peter: thanks. That helps but not completely.
When I run the query to include only records for July using a statement such as following
============
SELECT /*+ FIRST_ROWS */ COUNT(ED.UTIMESTAMP), TO_CHAR((TO_DATE('01/01/1970','MM/DD/YYYY') + (ED.UTIMESTAMP/86400)), 'MM/DD') AS DATA
FROM EVENT_DATA ED
WHERE AGENT_ID = 160
AND (TO_CHAR((TO_DATE('01/01/1970','MM/DD/YYYY')+(ED.UTIMESTAMP/86400)), 'MM/YYYY') = TO_CHAR(SYSDATE-15, 'MM/YYYY'))
GROUP BY TO_CHAR((TO_DATE('01/01/1970','MM/DD/YYYY') + (ED.UTIMESTAMP/86400)), 'MM/DD')
ORDER BY TO_CHAR((TO_DATE('01/01/1970','MM/DD/YYYY') + (ED.UTIMESTAMP/86400)), 'MM/DD');
=============
I get the following
COUNT(ED.UTIMESTAMP) DATA
1 07/20
1 07/21
1 07/24
2 07/25
2 07/27
2 07/28
2 07/29
1 07/30
2 07/31
Some dates donot have any records and so no output. Is there a way to show the missing dates with a COUNT value = 0?
Thanks
Ray

Need to retrieve the most recent record per deposit number

Can someone please show me a way to solve my problem or at least point me in the right direction.
I have a simple bibliography table called mdd_biblio that has 3 fields:
bib_mdd_no this is a deposit number
bib_upd_by person who updated the record
bib_upd_date date the record was updated (timestamp)
A deposit might have more than one bibliographic entry with either the same date or a newer date and, the deposit might have one or more person updating the bibliography
The table has 4974 records but only 1867 are unique deposit numbers
All I want to do is select a single record that indicates when the deposit was last edited and and who did the editing (as indicated by the *). I don't care which record it is as long as it is the most recent date.
The following query retrieves 1944 records (67 duplicates) and has eliminated 3000 duplicates but hasn't eliminated them all. Why?
select unique(bib_mdd_no), bib_upd_by, bib_upd_date from mdd_biblio
order by bib_mdd_no
M64C/16-001 MDD 13-SEP-07 *
M64C/16-001 MDD 13-SEP-07
M64C/16-002 DPROUXE 30-NOV-07 *
M64C/16-002 MDD 13-SEP-07
M64C/16-002 MDD 13-SEP-07
M64C/16-003 DPROUXE 29-NOV-07 *
M64C/16-003 MDD 13-SEP-07
M64C/16-003 MDD 13-SEP-07
M64C/16-004 MDD 13-SEP-07 *
M64C/16-004 MDD 13-SEP-07
M64C/16-005 MDD 13-SEP-07 *
M64C/16-005 MDD 13-SEP-07
M64C/16-006 DPROUXE 03-DEC-07 *
M64C/16-006 MDD 13-SEP-07
M64C/16-007 MDD 02-OCT-07 *
M64C/16-008 MDD 02-OCT-07 *
M64C/16-009 MDD 02-OCT-07 *
M64C/16-010 MDD 02-OCT-07 *
I don't understand why of these duplicates still show up here since 3000 have been eliminated..
To Reiterate: What I really need is a simple query to retrieve the most recently edited record for each deposit number regardless of the updater's name. I need this in order to build a summary table from this and 15 other tables.
Thanks for any help you can give
Glenn

Usually it is done somehow like this
select bib_mdd_no,
       bib_upd_by,
       bib_upd_date
from (select bib_mdd_no,
               bib_upd_by,
               bib_upd_date,
               row_number() over (partition by bib_mdd_no order by bib_upd_date desc) r
          from mdd_biblio
where r = 1
order by bib_mdd_noRegards
Etbin

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Hi
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Try
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Actually I believe that all the answers are wrong.
I believe that there will never be a single statement. If you need to determine the last 100 records for a special user you first need to determine the highest document number.
this can be done by
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Use the record selection formula like this
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Dear SDN Team Members!
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These details must be printed seperately for each customer.
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Hi Krsihna,
Its simple.
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exporting formname = '<form name>'
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Hi,
am having a table where in i will be having data for so many group members. i need to fetch data for a particular group members whose number of rows of data may be more in numbers (but i want only one row of data for each member of the group)
here is the query for fetching all rows of data
select RI.RESOURCE_NAME,TR.MSISDN,TR.ADDRESS1_GOOGLE, TR.MSG_DATE_INFO, FROM TRACKING_REPORT TR, RESOURCE_INFO RI
WHERE TR.MSISDN IN (SELECT MSISDN FROM RESOURCE_INFO WHERE GROUP_ID ='1' AND COM_ID=2 ) AND RI.MSISDN=TR.MSISDN
order by MSG_DATE_INFOoutput of this query is...
>
ddd     12345          13-Mar-10 19:43:03
eee     54321     Tamil Nadu, India      13-Mar-10 19:39:48
ddd     12345          13-Mar-10 19:32:58
eee     54321     Tamil Nadu, India      13-Mar-10 19:30:07
ddd     12345          13-Mar-10 19:23:08
eee     54321     Tamil Nadu, India      13-Mar-10 19:20:14
fff     98765          13-Mar-10 19:19:22
ddd     12345          13-Mar-10 19:13:01
eee     54321     Tamil Nadu, India      13-Mar-10 19:09:50
ddd     12345          13-Mar-10 19:02:56
eee     54321     tn,ind      13-Mar-10 18:59:49
ddd     12345          13-Mar-10 18:53:08
eee     54321     tn,ind      13-Mar-10 18:49:50
ddd     12345          13-Mar-10 18:42:56
eee     54321     tn,ind      13-Mar-10 18:39:50
ddd     12345          13-Mar-10 18:33:00
eee     54321     tn,ind      13-Mar-10 18:29:50
ddd     12345          13-Mar-10 18:22:54
eee     54321     tn,ind      13-Mar-10 18:19:50
ddd     12345          13-Mar-10 18:12:56
eee     54321     tn,ind      13-Mar-10 18:09:50
ddd     12345          13-Mar-10 18:02:54
eee     54321     tn,ind      13-Mar-10 18:00:02
fff     98765     Tamil Nadu, India      13-Mar-10 17:59:26
fff     98765     Tamil Nadu, India      13-Mar-10 17:54:26
ddd     12345          13-Mar-10 17:52:56
eee     54321     tn,ind      13-Mar-10 17:49:50
fff     98765     Tamil Nadu, India      13-Mar-10 17:49:25
fff     98765     Tamil Nadu, India      13-Mar-10 17:44:26
ddd     12345          13-Mar-10 17:42:56
>
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>
ddd     12345          13-Mar-10 19:43:03
eee     54321     Tamil Nadu, India      13-Mar-10 19:39:48
fff     98765          13-Mar-10 19:19:22
>
how to modify the query to achieve this...?

Hi,
This is not giving the result which i want...
table is
CREATE TABLE TRACKING_REPORT
ID               NUMBER,
MSISDN           NUMBER(12)                   NOT NULL,
X                NUMBER(15,8)                 NOT NULL,
Y                NUMBER(15,8)                 NOT NULL,
TIME_STAMP       DATE,
MSG_DATE_INFO    DATE                         DEFAULT sysdate,
ADDRESS1_GOOGLE VARCHAR2(400 BYTE),
ADDRESS2_GOOGLE VARCHAR2(400 BYTE),
ADDRESS_MLINFO   VARCHAR2(400 BYTE),
REQ_ID           VARCHAR2(30 BYTE)
CREATE TABLE RESOURCE_INFO
RESOURCE_ID    NUMBER,
MSISDN         NUMBER,
RESOURCE_NAME VARCHAR2(25 BYTE),
ADDRESS        VARCHAR2(100 BYTE),
COM_ID         VARCHAR2(20 BYTE),
ADMIN_ID       NUMBER,
TIME_STAMP     DATE                           DEFAULT SYSDATE,
GROUP_ID       NUMBER
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Dear Experts .
The users want to see the report by status for the order detail report at document level it displays one record for each cube .
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Thanks,
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Ritesh

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Thanks for your interest.
The scenario is, I have 3 datasources form the same source system, All the 3 datasources have different fields except 'Incident Number'. So, each and every field has only one value in the report. But due to 3 separate datasources, it creates 3 records displahying values of each datasource in a separate record.
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Finding 5 most recent records for each customer with abnormal order amounts

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