Finding a combination of data in several rows and on the same column

Question

In a table I have two cloumn
ID
and
ID6 that repersent joined account that have several partners ID
for example:
ID ID6
====== ===========
11215 6100
11152 6100
11242 6101
11523 6101
11125 6101
11254 6101
there is about 60,000 rows
I have a table with several ID in a row and I need to find the missing ID6 if it exist (not all ID are join account) and put it in that row if exist
the table look like this
11523,11125,11254, 11242
11658,15662
11458
11215,11152
there is about 5,000 rows
I use plsql developer.
How do I do that ?
ELI

Answer 1

Solution
SELECT ID
        FROM T2
        MODEL
            RETURN UPDATED ROWS
            PARTITION BY (ROWNUM  RN)
            DIMENSION BY (0 I)
            MEASURES (ID)
            ( ID [FOR I FROM 1 TO NVL(LENGTH(REGEXP_REPLACE(ID[0],'[^,]','')),0) + 1 INCREMENT 1]
              = REGEXP_SUBSTR(ID[0],'[^,]+',1,CV(I)))
MINUS
SELECT TO_CHAR(ID) ID
FROM T1
Demo
SQL> WITH T1 AS (              SELECT 11215 ID,6100 ID6 FROM DUAL UNION ALL
  2                 SELECT 11152,6100 FROM DUAL UNION ALL
  3                 SELECT 11242,6101 FROM DUAL UNION ALL
  4                 SELECT 11523,6101 FROM DUAL UNION ALL
  5                 SELECT 11125,6101 FROM DUAL UNION ALL
  6                 SELECT 11254,6101 FROM DUAL
  7                 ), T2 AS (
  8                 SELECT '11523,11125,11254,11242' ID FROM DUAL UNION ALL
  9                 SELECT '11658,15662' FROM DUAL UNION ALL
10                 SELECT '11458' FROM DUAL UNION ALL
11                 SELECT '11215,11152' FROM DUAL
12               )
13  SELECT ID
14          FROM T2
15          MODEL
16              RETURN UPDATED ROWS
17              PARTITION BY (ROWNUM  RN)
18              DIMENSION BY (0 I)
19              MEASURES (ID)
20              ( ID [FOR I FROM 1 TO NVL(LENGTH(REGEXP_REPLACE(ID[0],'[^,]','')),0) + 1 INCREMENT
1]
21                = REGEXP_SUBSTR(ID[0],'[^,]+',1,CV(I)))
22  MINUS
23  SELECT to_char(ID) id
24  FROM T1
25  /
ID
11458
11658
15662
SQL>