Get the data with more than one of the desired value

Question

Hi,
I need to pull the records with more than one value of 'Other' on the delivery days fields.
The delivery fields are mon,tue,wed,thu,fri and sat that tells the where the item will be delivered. The value can be Home, Work, or Other.
Here is the Sample data:
cust_id: 123
item: newspaper
mon: Home
tue:Work
wed: Other
thu: Home
fri: Other
sat: Other
And here is my query so far.
select
cust_id,
item,
mon,
tue,
wed,
thu,
fri,
sat,
sum(case when (del_mon = 'O' or del_tue ='O' or del_wed ='O' or del_thu ='O' or del_fri ='O' or del_sat='O') then 1
else 0 end) as day_ctr
from customer
Could you please help me with the right formula I need to get this?
Thank you in advance..

Answer 1

First
DESC customer
Second
Can you explain what you are trying with
sum(case when (del_mon = 'O' or del_tue ='O' or del_wed ='O' or del_thu ='O' or del_fri ='O' or del_sat='O') then 1 else 0 end) as day_ctr
Third
Usually it's helpful a example of the result you want...
Perhaps you want this
select DECODE(mon,1,(select distinct mon from customer), 'OTHER') mon,
        DECODE(tue,1,(select distinct tue from customer), 'OTHER') tue,
        DECODE(wed,1,(select distinct wed from customer), 'OTHER') wed,
        DECODE(thu,1,(select distinct thu from customer), 'OTHER') thu,
        DECODE(fri,1,(select distinct fri from customer), 'OTHER') fri,
        DECODE(sat,1,(select distinct sat from customer), 'OTHER') sat from
select
COUNT(DISTINCT mon) mon,
COUNT(DISTINCT tue) tue,
COUNT(DISTINCT wed) wed,
COUNT(DISTINCT thu) thu,
COUNT(DISTINCT fri) fri,
COUNT(DISTINCT sat ) sat
from customer
)