Help needed in sql

Hi,
I am getting the filename as below and i want to extract some part of the string with the filename and the output need as below
FileName : THE_PK_SOURCE_CLASS0002_PKID5403_20130603_342342.txt 
Output:
======
5403-THE_PK_SOURCE_CLASS0002_PKID5403
Please help me in advance
Thx,

That's easy. Just mark the last two parts asa optional ({0,2})
with data as (
select 'THE_PK_SOURCE_CLASS0002_PKID5403_20130603_342342.txt' str from dual
union all
select '20130712-v1-THE_PK_SOURCE_CLASS0002_PKID5403_20130603_342342.txt' from dual
union all
select '20130712-v1-THE_PK_SOURCE_CLASS0002_PKID5403_1222.txt' from dual
union all
select '20130712-v1-THE_PK_SOURCE_CLASS0002_PKID5403.txt' from dual
union all
select '20130712-v1-THE_PK_SOURCE_CLASS0002_PKID5403_132.txt' from dual
union all
select '20130712-v1-THE_PK_SOURCE_CLASS0002_PKID5403_20130603_342342.txt' from dual
select
-- all from the start to and including the last hyphen is cut off
regexp_replace(str, '^(.+-)?([^-]+?)(\d+)(_\d+){0,2}\.txt$', '\3-\2\3') str
from data
from data
STR
5403-THE_PK_SOURCE_CLASS0002_PKID5403
5403-THE_PK_SOURCE_CLASS0002_PKID5403
5403-THE_PK_SOURCE_CLASS0002_PKID5403
5403-THE_PK_SOURCE_CLASS0002_PKID5403
5403-THE_PK_SOURCE_CLASS0002_PKID5403
5403-THE_PK_SOURCE_CLASS0002_PKID5403
Message was edited by: chris227 Changed to the simplified version, but it's the same for the "corrected" veriosn too.

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    http://download-west.oracle.com/docs/cd/B10501_01/appdev.920/a96612/u_file.htm#ARPLS069
    Joel P�rez

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