Help! XSLT

Question

I have been searching Oracle sites for 2 days on XSLT. I am writing an interface (over 20 actually) What I want to do is generate xml fragments and zip them together dynamically. The XSLT isn't necessarily the difficult part, just getting Oracle to do it from xmltype variables instead of files on disk. Am I going to have to write java classes to do this?

Answer 1

Thanks for your reply pepijn. Unfortunately, that doesn't work. This is a sample of that solution:
DECLARE
targetxml sys.xmltype;
sourcexml sys.xmltype;
xsltsrc sys.xmltype;
reslt VARCHAR2(4000);
BEGIN
newxml := xmltype.createxml('<HELLO>Hello World</HELLO>');
SELECT msg_txt INTO sourcexml FROM interface_messages WHERE interface_msg_seq_no = 1459550; -- XML source
xsltsrc := xmltype.createxml('<xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">'||
' <xsl:output method="xml" indent="yes"/>'||
'<xsl:template match="/">'||
' <xsl:copy>'||
' <xsl:copy-of select="document(sourcexml)/*" />'||
' <xsl:copy-of select="document(targetxml)/*" />'||
' </xsl:copy>'||
'</xsl:template>'||
'</xsl:stylesheet>');
sourcexml := newxml.transform(xsltsrc);
reslt := sourcexml.getstringval(); -- print the result
dbms_output.put_line(substr(reslt, -1, 255));
END;
This throws Ora - 30625 method dispatch on a NULL SELF argument. In other words, sourcexml was null. What I want to happen is take sourcexml and merge/add newxml to it using the xslt. The xml selected from the table is just a sample xml. What I want (need) to do is generate xml (select xmlelement(....)) in several segments and depending on the requirements assemble them together. XSLT appears to be the best method, but Oracle's XSLT parser only reads files. and the transform function and method take only 1 xml parameter.
Sigh!
Dean