How do I calculate a time such as work hours

How do I calculate a time such as, a cell may have any time valve pertaining to daily work hours. 8:00 or 7:00 or 10:30. My question is I want another cell to represent any amount over 8:00. Like in a nine hour day you would have 8:00 with 1:00 overtime

This may help:
The first row is a header.
select the three columns and format as "Duration":
now enter the formulas as:
B2=IFERROR(IF(A2>DURATION(0, 0, 8), DURATION(0, 0, 8), DURATION(0, 0, 0)), "")
C2=IFERROR(A2-B2, "")
select B2 and C2, then fill down as needed

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giltober wrote:
Jerry,
I start working at 5pm and finish in 1am which means i worked for 8 hours.
the only way to get the correct answer is to enter the dates also?
is there a formula that i can enter that will take in consideration that every time i work i start at the afternoon and finish after midnight?
i have a cell that i enter the date..
im still new to numbers and i dont know i to put that into consideration...
thank you for your help
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That's right, my mistake on the detail. I must have been distracted. I stand by the rest of my post.
Here's my approach to solving the problem:
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11/07/2007 00:00:01 23841.572266
11/07/2007 00:01:01 23608.240234
11/07/2007 00:02:01 23238.177734
11/07/2007 00:03:01 23373.197266
11/07/2007 00:04:01 23244.857422
11/07/2007 00:05:02 23408.943359
11/07/2007 00:06:01 23138.939453
11/07/2007 00:07:01 23325.080078
11/07/2007 00:08:01 23433.609375
11/07/2007 00:10:01 22783.115234
11/07/2007 00:11:01 22642.421875
11/07/2007 00:12:01 22226.654297
11/07/2007 00:13:01 22741.773438
11/07/2007 00:14:01 22611.898438
11/07/2007 00:16:01 22810.580078
11/07/2007 00:17:01 22404.023438
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11/07/2007 00:19:01 22672.619141
11/07/2007 00:20:02 22268.031250
11/07/2007 00:21:01 21770.136719
11/07/2007 00:22:01 22877.025391
11/07/2007 00:23:01 22565.330078
11/07/2007 00:24:01 22781.949219
11/07/2007 00:25:01 22324.345703
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Message was edited by: MAppleby
Michael Appleby

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FROM m
Best Regards,Uri Dimant SQL Server MVP,
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