How do I get Unicode chars beyond the ASCII range to display ?

Question

Hello all.
I have just recently started to learn Java.
I want to display the data in a array using Unicode characters, but when I use the unicode code from the code sheet I merely get a ?.
I looked about the net and understand that Java doesnt support none ASCII characters (by default?) , I think its possible to import various codes but not sure about that.
Anyways...
My question is: How do I get the Unicode character 2254 Box Drawing Element to display (also other non standard ASCII ) ? Print("\u2254") results in a ?.
If you are wondering why:
I want to store a map for a game into a data array with the entities represented as normal letters and characters, this map will be generated by the program randomly but I want to see the output of the map to test if its obeying the rules I set out for the map generation.
I figured just read the array and print out the result , but to make it more legible in debugging convert the text characters to box drawing characters.

Answer 1

Both methods you mentioned just generate a question mark instead of the box drawing element I want.
I can get all the normal, ie letters and numbers and the common characters... but beyond that and all I get is a '?' in its place.
Initially I just wanted it to print the character in the legend.
The code below just prints a few lines of text , the legend to decipher the level display, and calls a class to create a level ..then the last call is to call a debug class to display the level that was created.
*   Prelim Code for the Random Dungeon Generator       *
*   used in Dungeon Runner                             *
*   Created : 03/07/2009                               *
public class DungeonGenerator {
      public static void main (String[] args) {
      System.out.println(
           "Prelimary code for the Random Dungeon Generator for Dungeon Runner Game\n\n"
                               );                    // Just a text heading reminder for me
      System.out.println(
           "Test 1 - debug screen - 03 July 2009\n\n"
      System.out.println("Legend: \u2254 = Top Left Corner \t 2 = Top Right Corner");
      System.out.println("        3 = Bot Left Corner \t 4 = Bot Right Corner");
      System.out.println("        L = Left Wall \t\t R = Right Wall");
      System.out.println("        T = Top Wall \t\t B = Bottom Wall");
      System.out.println("        D = Doorway \t\t + = Play Space");
      System.out.println("        E = Exit Entity \t S = Start Entity");
      System.out.println("        . = None Play Space");
      System.out.println("\n----------------------------------------------------\n");
     // Call the LevelGen
     /** This is just a temperary call method
          I am will use another array and a
          loop to call the LevelGen the
          number of levels I decide the
          game will have
     LevelGen levelone = new LevelGen();          // Calls the LevelGen to create a Level
     levelone.displayLevel();                    // Display the level that was generated
                                             // for debugging only
      }     // End Main method
}      // End DungeonGenerator class