How do I insert multiple values into different fields in a stored procedure

Question

I am writing a Stored Procedure where I select data from various queries, insert the results into a variable and then I insert the variables into final target table. This works fine when the queries return only one row. However I have some queries that return multiple rows and I am trying to insert them into different fields in the target table. My query is like
SELECT DESCRIPTION, SUM(AMOUNT)
INTO v_description, v_amount
FROM SOURCE_TABLE
GROUP BY DESCRIPTION;
This returns values like
Value A , 100
Value B, 200
Value C, 300
The Target Table has fields for each of the above types e.g.
VALUE_A, VALUE_B, VALUE_C
I am inserting the data from a query like
INSERT INTO TARGET_TABLE (VALUE_A, VALUE_B, VALUE_C)
VALUES (...)
How do I split out the values returned by the first query to insert into the Insert Statement? Or do I need to split the data in the statement that inserts into the variables?
Thanks
GB

Answer 1

"Some of the amounts returned are negative so the MAX in the select statement returns 0 instead of the negative value. If I use MIN instead of MAX it returns the correct negative value. However I might not know when the amount is going to be positive or negative. Do you have any suggestions on how I can resolve this?"
Perhaps something like this could be done in combination with the pivot queries above, although it seems cumbersome.
SQL> with data as (
  2        select  0 a, 0 b,  0 c from dual   -- So column a has values {0, 1, 4},
  3  union select  1 a, 2 b, -3 c from dual   --    column b has values {0, 2, 5},
  4  union select  4 a, 5 b, -6 c from dual ) --    column c has values {0, -3, -6}.
  5  --
  6  select  ( case when max.a > 0 then max.a else min.a end) abs_max_a
  7  ,       ( case when max.b > 0 then max.b else min.b end) abs_max_b
  8  ,       ( case when max.c > 0 then max.c else min.c end) abs_max_c
  9  from    ( select  ( select max(a) from data ) a
10            ,       ( select max(b) from data ) b
11            ,       ( select max(c) from data ) c
12            from      dual ) max
13  ,       ( select  ( select min(a) from data ) a
14            ,       ( select min(b) from data ) b
15            ,       ( select min(c) from data ) c
16            from      dual ) min
17  /
ABS_MAX_A  ABS_MAX_B  ABS_MAX_C
         4          5         -6
SQL>