How do i send the username and password to yahoo web page through url

how do i send the username and password to yahoo web page through url i.e as Query string so that my account in yahoo will open...

If you don't mind using a library, then download and use the Apache HttpClient library. It takes care of all these details for you.

Similar Messages

How can i clear the usernames and passwords history from all login websites?

how can i clear the usernames and passwords in the log in history of the websites? example when i want to login to my facebook i always type first letter of my e-mail and it comes with the passwords because before i put remember my password, and in other websites so, i just need to delete all this login history and it's not working from the clear everything !!! :S any idea please !! thanks in advance :)

See:
http://kb.mozillazine.org/Deleting_autocomplete_entries
http://kb.mozillazine.org/Password_Manager

How can I get the username and password from Oracle Forms to PJC !

Dear Sir,
I have username,password and push button fields in oracle forms. When user clicks the push button, I need to get username and password field contents to my Pluggable Java Program to authenticate the user trying to login. How can I get those text field contents to my java program..? Looking forward from you soon sir.
Thanks in Advance,
S Ramkumar

I tried that trigger but nothing reflects. I write that method in WHEN_BUTTON_PRESSED trigger.
In the form module I written,
Set_Custom_Property('BL.USERNAME',1,'NAME','');
Set_Custom_Property('BL.PASSWORD',1,'PASS','');
Implementation class of the push button I gave my java class file name.
In Java Code I tried register the form fields like,
public static final ID userName = ID.registerProperty("NAME");
public static final ID passWord = ID.registerProperty("PASS");
In Java Code I tried get the contents from registered properties,
public boolean setProperty(ID property, Object value) {
if(property == userName) {
System.out.println("Just I wish to see the name entered" + value.toString());
if(property == passWord) {
System.out.println("Just I wish to see the pass entered" + value.toString());
But even System.out.println() is working.
What's wrong with this code sir ???
Can you tell me How to register and get those field values in Java ?

How do I send a link and not an entire web page in

safari

Open the web page.
Click the "Share" button. Select "Email this page".
Mail will open up with the page selected.
In the header, on the rightside under the address, there is a box for "Send web content as:".
Click in that box and select "Link only". Link should appear in the mail.
For more on this:http://support.apple.com/kb/PH11890
Best

How can I access the username and password entered into an https IPlanet login so that it may be passed to an LDAP to obtain additional security classification information for that user?

Have you tried simply using the REMOTE_USER environment variable which is accessible via CGI by the following:
$customer = $ENV{"REMOTE_USER"};
Once you have that (which will correspond to the uid attribute in your LDAP server) you can do a query for the other things. The password shohuld not be required to lookupu other info since you know at this point that the are already authenticated.

Passing the username and password via report link

How can I pass the username and password via the reprt link?
thanks all.
Ahmad Esbita

Hi,
Jigar Oza
Thanks for u r reply, i have tried with application integrator but there is a problem with usermapping.
now what i have done is created HTTP System based on this system created URL iView,in application parameters username and password as MappedUser and MappedPassword every thing is working fine. user logged in automatically when he logged into portal.
there are tabs ,links in application .when i click on tabs or links it is assking to enter username and password of the application.
did i do any thing wrong in creating HTTP system or URL iView,
what are the necessary properties should be given.
replys are highly appreciated.
Regards
K Naveen Kishore

HT5295 How do I automatically sync a "private" podcast where I have to manually input the username and password? It syncs in my iTunes but gives me an error on my iPod.

How do I automatically sync a "private" podcast where I have to manually input the username and password? It syncs in my iTunes but gives me an error on my iPod?

Is this an iLife installation disk or system install disk? In either case download the demo version of Pacifist and open the install package on the disk. Locate iPhoto and use Pacifist to install iPhoto. Then you'll need to apply the latest updater from the Apple Downloads webpage:
Apple - Support - Downloads. Just search for the iPhoto version you installed to get the updaters for that version.
OT

How to get to see the usernames and passwords for wifi logins on iPad

How to get to see the usernames and passwords for wifi logins on iPad.

You can't access that on an iPad. The iPad does not have a Keychain Access type app like the Mac has. Maybe an application like iExplorer on your Mac will let you see them, but you can't see them on the iPad itself.

How do you auto connect to a PC server resource on re boot w/o having to type the username and password to that resource?

How do you auto connect to a PC server resource on re boot w/o having to type the username and password to that resource?

Open the server as you normally would. When you enter your password, click the box to "remember Password". Once mounted, select the server icon from your desktop and hit Command + L to make an alias. You can move that alias to some place out of the way if you wish. The go to System Preferences/Users and select your user profile, then Login Items. Simply add the alias you just created. Now every time you boot you will automatically be connected to that server.

How to catch exception while validating the username and password in hbm

Hi,
I do want to set the username and password dynamically in hibernate.cfg.xml
Here below is my configuration file.
{code<hibernate-configuration>
<session-factory>
       <property name="hibernate.bytecode.use_reflection_optimizer">false</property>
       <property name="hibernate.connection.driver_class">oracle.jdbc.driver.OracleDriver</property>
       <property name="hibernate.connection.pool_size">10</property>
       <property name="show_sql">true</property>
       <property name="hibernate.dialect">org.hibernate.dialect.OracleDialect</property>
       <property name="hibernate.hbm2ddl.auto">update</property>
       <property name="current_session_context_class">thread</property>
       <property name="show_sql">true</property>
     </session-factory>
</hibernate-configuration>{code}
Also im getting that session factory object like the below code.
public class Sessions {        private static SessionFactory sessionFactory;      private static Configuration configuration = new Configuration();        static {          try {              String userName = GuigenserviceImpl.userName;              String password = GuigenserviceImpl.password;              String hostName = GuigenserviceImpl.hostName;              String portNo = GuigenserviceImpl.portNo;              String sId = GuigenserviceImpl.sId;                  configuration                      .setProperty("hibernate.connection.username", userName);              configuration                      .setProperty("hibernate.connection.password", password);              configuration.setProperty("hibernate.connection.url",                      "jdbc:oracle:thin:@" + hostName + ":" + portNo + ":" + sId);                try {              configuration.configure("/hibernate.cfg.xml");              sessionFactory = configuration.buildSessionFactory();              GuigenserviceImpl.strAccpted = "true";              }              catch (Exception e) {                    e.printStackTrace();                  GuigenserviceImpl.strAccpted = "false";              }            }          catch (HibernateException hibernateException) {              GuigenserviceImpl.strAccpted = "false";              hibernateException.printStackTrace();          }          catch (Throwable ex) {                GuigenserviceImpl.strAccpted = "false";              ex.printStackTrace();              throw new ExceptionInInitializerError(ex);          }      }          public static SessionFactory getSessionFactory() {          return sessionFactory;      }
So, in this above scenario, suppose if im giving the wrong password means exception should be caught and the string variable "GuigenserviceImpl.strAccpted" should be assigned to false.
But im getting the SQL Exception only in console like wrong username and password. And finally i couldn't able to catch the exception in Sessions class, static block.
Anyone can help me in catching that SQL Exception in my Sessions class and i need to handle that SQL Exception in my class.
Im getting this following exception message in my console.
INFO: configuring from resource: /hibernate.cfg.xml Apr 6, 2009 2:47:00 PM org.hibernate.cfg.Configuration getConfigurationInputStream INFO: Configuration resource: /hibernate.cfg.xml Apr 6, 2009 2:47:00 PM org.hibernate.cfg.Configuration doConfigure INFO: Configured SessionFactory: null Apr 6, 2009 2:47:00 PM org.hibernate.connection.DriverManagerConnectionProvider configure INFO: Using Hibernate built-in connection pool (not for production use!) Apr 6, 2009 2:47:00 PM org.hibernate.connection.DriverManagerConnectionProvider configure INFO: Hibernate connection pool size: 10 Apr 6, 2009 2:47:00 PM org.hibernate.connection.DriverManagerConnectionProvider configure INFO: autocommit mode: false Apr 6, 2009 2:47:00 PM org.hibernate.connection.DriverManagerConnectionProvider configure INFO: using driver: oracle.jdbc.driver.OracleDriver at URL: jdbc:oracle:thin:@192.168.1.12:1521:orcl Apr 6, 2009 2:47:00 PM org.hibernate.connection.DriverManagerConnectionProvider configure INFO: connection properties: {user=scott, password=****} Apr 6, 2009 2:47:01 PM org.hibernate.cfg.SettingsFactory buildSettings WARNING: Could not obtain connection metadata java.sql.SQLException: ORA-01017: invalid username/password; logon denied        at oracle.jdbc.driver.SQLStateMapping.newSQLException(SQLStateMapping.java:70)      at oracle.jdbc.driver.DatabaseError.newSQLException(DatabaseError.java:131)      at oracle.jdbc.driver.DatabaseError.throwSqlException(DatabaseError.java:204)      at oracle.jdbc.driver.T4CTTIoer.processError(T4CTTIoer.java:455)      at oracle.jdbc.driver.T4CTTIoer.processError(T4CTTIoer.java:406)      at oracle.jdbc.driver.T4CTTIoer.processError(T4CTTIoer.java:399)      at oracle.jdbc.driver.T4CTTIoauthenticate.receiveOauth(T4CTTIoauthenticate.java:799)      at oracle.jdbc.driver.T4CConnection.logon(T4CConnection.java:368)      at oracle.jdbc.driver.PhysicalConnection.<init>(PhysicalConnection.java:508)      at oracle.jdbc.driver.T4CConnection.<init>(T4CConnection.java:203)      at oracle.jdbc.driver.T4CDriverExtension.getConnection(T4CDriverExtension.java:33)      at oracle.jdbc.driver.OracleDriver.connect(OracleDriver.java:510)      at java.sql.DriverManager.getConnection(DriverManager.java:525)      at java.sql.DriverManager.getConnection(DriverManager.java:140)      at org.hibernate.connection.DriverManagerConnectionProvider.getConnection(DriverManagerConnectionProvider.java:110)      at org.hibernate.cfg.SettingsFactory.buildSettings(SettingsFactory.java:84)      at org.hibernate.cfg.Configuration.buildSettings(Configuration.java:2073)      at org.hibernate.cfg.Configuration.buildSessionFactory(Configuration.java:1298)      at com.beyon.ezygui.server.Sessions.<clinit>(Sessions.java:39)      at com.beyon.ezygui.server.GuigenserviceImpl.testRPC(GuigenserviceImpl.java:322)      at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method)      at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:39)      at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:25)
Thanks in advance.
Thanks & Regards,
Kothandaraman N.

Hi,
Myself hardcoded that username and password checking like the below code.
String name = loginData.get("userName").toString();
          String pswd = loginData.get("pswd").toString();
          String hstName = loginData.get("hName").toString();
          String prtNo = loginData.get("portNo").toString();
          String sid = loginData.get("sId").toString();
          SessionFactory sessionFactory = null;
          try {
               if (name.trim().equals(userName) && pswd.trim().equals(password)
                         && hstName.trim().equals(hostName)
                         && prtNo.trim().equals(portNo) && sid.trim().equals(sId)) {
                    sessionFactory = Sessions.getSessionFactory();
                    strAccpted = "true";
               } else {
                    strAccpted = "false";
          } catch (Exception e) {
               e.printStackTrace();
               strAccpted = "false";
          }I have my own values in string objects, then comparing that values with the values from login form. If both values are matching, then i will do configurations in hibernate.
ResourceBundle resourceBundle = ResourceBundle
               .getBundle("com.beyon.ezygui.server.Queries");
     public static final String connection_url = resourceBundle
               .getString("connection.url");
     public static final String userName = resourceBundle.getString("userName");
     public static final String password = resourceBundle.getString("password");
     public static final String hostName = resourceBundle.getString("hostName");
     public static final String portNo = resourceBundle.getString("portNo");
     public static final String sId = resourceBundle.getString("sId");The above are the String objects i'm checking for the match with values from login form.
Thanks & Regards,
Kothandaraman N.

How do I unlink a device from an existing Apple ID. User forgot the username and password of the Apple ID

Hi,
A friend of mine bought a brand new iPad. He manage to enroll it to an Apple ID. However, he forgot the password of the Apple ID account and the device is linked to it. I tried to configure it myself. As i go through the configuration, it says "...This iPad is currently linked to an Apple ID (XXXXX)"
I asked my friend, he forgot the username and password.
Thanks....

Hi
I manage to login to his account and reset the password of his icloud account.
However, now when i activate the ipad using this apple id and the password. It says...
"xxxxxx" cannot be used to unlock this iPad.
I have provided the right Apple ID and Password - still didnt work?
Thanks.

I lost the usernames and passwords for my websites when I installed Firefox 4. How do I recover them?

I bookmarked frequently used websites. Many of which had secure user names and passwords. I used firefox, norton and roboform to remember the user names and passwords. All of these were lost when I upgraded to Firefox 4. I need to recover the usernames and passwords. I also want to use these features going forward. What do I do?

Figured it out. Just gotta delete keychain.plist, which is found in one of the following two spots:
C:\Users\YOURUSERNAME\AppData\Roaming\Apple Computer\Preferences\keychain.plist
C:\Documents and Settings\YOURUSERNAME\AppData\Apple Computer\Preferences\keychain.plist

Pass the username and password in URL to auto log in the application from SharePoint List

how to Pass the username and password in URL to auto log in the application from SharePoint List
I have a link in my SharePoint list when user try to open the link its asking username and password .i want to put username and password in URL to auto log in into that external URL from sharepoint
please help me it is possible

Check out
http://serverfault.com/questions/371907/can-you-pass-user-pass-for-http-basic-authentication-in-url-parameters
Kind regards,
Margriet Bruggeman
Lois & Clark IT Services
web site: http://www.loisandclark.eu
blog: http://www.sharepointdragons.com

Getting the Username and password Of Enterprise Portal in WebDynPro

Hi Friends,
          I have developed one webdynpro application to read the excel sheet from KM Repository. i have used URL to open the connection to that excel file and to get the Inputstream.
          While opening the connection to the excel, I've hardcoded the username and password. I need to get the username and password of the user who login into the Enterprise portal and runs that application. then i need to pass that username and password along with URL of the Excel sheet.
          Could you people find the solution and replied to me. I am waiting for your bright answer.
Thanks and Regards,
Sandeep Kumar Bonam.

A very standard question in this forum.
Refer this :
Re: How to get User Id in Web dynpro application
Regards,
Subramanian V.

How to give Username and password when calling HTTP page?

I have this code when i run this I get credentials error. How to give credentials .The authentication is set to windows in the https page. Means pop up will appear to get the credentials
declare
req UTL_HTTP.REQ;
resp UTL_HTTP.RESP;
value varchar2(1024);
p_url varchar2(4000);
OPT varchar2(1000);
BEGIN
dbms_output.put_line('');
p_url:='http://www.xyz.com/';
dbms_output.put_line(p_url);
req := UTL_HTTP.begin_REQUEST(p_url);
utl_http.set_header(req, 'User-Agent', 'Mozilla/4.0');
resp := utl_http.get_response(req);
loop
utl_http.read_line(resp, value, true);
dbms_output.put_line(value);
end loop;
exception
when utl_http.end_of_body then
utl_http.end_response(resp);
END;
When i run this i get
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1"/>
<title>401 - Unauthorized: Access is denied due to invalid credentials.</title>
<style type="text/css">

Basic authentication is set using the UTL_HTTP.Set_Authentication() call.
If you are using a proxy and need procy authentication, you can set the username and password for proxy access, as part of the proxy URL. E.g.
utl_http.set_proxy( 'http://proxyuser:[email protected]', null );NTLM (Windows NT LAN Manager) authentication is proprietary and not part of the HTTP specifications. If that is needed, try and use the username and password as part of the URL - or do some research on how to manually perform NTLM authentication.
If you are using HTTPS, you need an Oracle Wallet with that server's certificate (making it a trusted certificate), and then set/use the wallet using the UTL_HTTP.Set_Wallet() call. See sample code in {message:id=10820182}.

How do i send the username and password to yahoo web page through url

Similar Messages

Maybe you are looking for