How to capture Java Exceptions in batch file

Question

I have a batch file that calls java class. When the java class throws exception, how do I capture the exception as an error message in batch file.
This is the java program
import java.io.*;
public class Test{
       public static void main(String []args) {
     String wantThisToFail=null;
          try {
               if (wantThisToFail.equals("SomeString") ) {
                    System.out.println("Testing");     
          }catch (Exception e){
               System.out.println("Exception " + e);
This is the batch file
@echo off
echo Testing
REM execute the java class
java Test
set deployError=%ERRORLEVEL%
echo %deployError%
IF NOT %deployError% == 0 (
echo failed
)else (
echo succeeded
)Since the java class throws NullPointerException, i want the batch file to show "Failed" Message.
Please Help!!

Answer 1

Try capturing the return value of the command "java Test". If it succeeds, you should get a '0', otherwise you'll get something else. I admit it's been years since I had to do that, but it rings a bell. If it works, and you're on Java 5 or later, you can use the method Thread.setDefaultUncaughtExeptionHandler ( look at the docs ) and from there use System.exit(<your integer value return code here>) for more control over the return value