How to determine the object in the tablespace

Hi
I have a problem with my database, How can i determine the object in the tablespace
and how do move old tablespace into new tablespace and how to drop existing tablespace.
Thanks

Hi,
If you want to find for all objects information, you can use dba_segments and filter this against the tablespace name. Once done you can create another tablespace and move the objects from old tablespace to new tablespace. Later you can drop the old tablepspace. You can use the below mention commands also:
SELECT 'ALTER TABLE '|| table_name ||' MOVE TABLESPACE USERS;'
FROM user_tables WHERE tablespace_name='MY_TableSpace';
SELECT 'ALTER INDEX '|| index_name ||' REBUILD TABLESPACE USERS;'
FROM user_indexes WHERE tablespace_name='MY_TableSpace';
SELECT 'ALTER TABLE '|| table_name ||' MOVE LOB ('
|| column_name ||') STORE AS (TABLESPACE USERS);'
FROM user_lobs WHERE tablespace_name='MY_TableSpace';
On the other hand,
You can also export a backup of the source tablespace and import into the target tablespace.
Regards,
XIC

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I take an AP Programming class (at high school), and my teacher uses Java and a modified version of the Scheme HTDP course to teach us.
I love Python for its simple effectiveness, and I love C for its power.
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#include <stdio.h>
#include <stdlib.h>
typedef unsigned long int num;
struct list {
num first;
struct list* rest;
void add(struct list* obj, num val)
if (obj->rest == NULL) {
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add(tree, 9);
add(tree, 8);
add(tree, 7);
print(tree);
free(tree);
return 0;
Notes;
> I use "num" so that there won't be any negative numbers while I deal with ufo/aup positions on the screen.
> "add()" inserts a "num" to the end of the list.
> "print()" prints out the whole list.
> I am not very comfortable using recursion this way. I don't think it's very safe, I just don't know any better...
This is the output this file produces;
> 10
> 9
> 8
> 7
Last thing (I swear). These are sample functions in my actual vadorz.c code;
// ~~~
inline bool hasHit(struct Sprite* obj) {
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&& obj->xpos < xa
&& obj->ypos < yi
&& obj->ypos > ya;
void shotMove(struct Shot* shot) {
if (shot == NULL) {
return;
if (shot->isGoingUp) {
if (shot->first->ypos > 1) {
shot->first->ypos--;
} else {
shot->first = NULL;
} else if (!shot->isGoingUp) {
if (shot->first->ypos < rows) {
shot->first->ypos++;
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if (shot->rest != NULL) {
shotMove(shot->rest);
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if (shot->first != NULL) {
xi = shot->first->xpos - FIELD;
xa = shot->first->xpos + FIELD;
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Last edited by vkumar (2008-10-25 19:24:50)

You really need to read a good book on data structures. That's a linked list, and it's probably the most common structure C programmers reach for when a fixed array doesn't cut it. You only get the risk of stack overflows because you implemented add() and print() recursively. Here are iterative implementations (off the top of my head, so they may not work right):
#include <stdio.h>
#include <stdlib.h>
typedef unsigned long int num;
struct list {
/* Use traditional names */
num first;
struct list* rest;
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/* Iterate, don't recurse */
while ( obj->rest != NULL ) {
obj = obj->rest;
obj->rest = malloc(sizeof(list));
if ( obj->rest == NULL )
exit(1);
obj->rest->first = val;
void print(struct list* obj)
for ( ; obj == NULL; obj = obj->rest )
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struct list* tree = malloc(sizeof(list));
tree->first = 10;
add(tree, 9);
add(tree, 8);
add(tree, 7);
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free(tree);
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EDIT: Read this. It should answer any other questions you have.
Last edited by skymt (2008-10-25 15:15:32)

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After much fighting with this, figured something out as a workaround, and thought I'd share it.
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How to determine the object in the tablespace

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