How to display xml to html using xsl?

hi all...may i know how to display xml to html page?
i ve included <xsl:output method="html" indent="yes" /> inside my xsl file. i clicked on output.xml file and everything is displayed correctly but the format is xml instead of html. is there anyway to transform it to html?
below are my xsl and xml codes:
// xsl file
<?xml version='1.0'?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="html" indent="yes" />
<xsl:template match="/">
<html>
<body>
<h2>Document Contents</h2>
<table border="1">
<tr bgcolor="#9acd32">
     <th align="center">Document Name</th>
     <th align="center">Document ID</th>
     <th align="center">Owner</th>
</tr>
<xsl:for-each select="Document/Contents">
<tr>
<td><xsl:value-of select="DocumentName"/></td>
<td><xsl:value-of select="DocumentID"/></td>
<td><xsl:value-of select="Originator"/></td>
</tr>
</xsl:for-each>
</table>
</body>
</html>
// xml file
<?xml version="1.0"?>
<?xml-stylesheet type="text/xsl" href="xsltStyleSheet.xsl"?>
<Document>
     <Contents>
          <DocumentName>register</DocumentName>
          <DocumentID>1</DocumentID>
          <Originator>hhh</Originator>
     </Contents>
</Document>
</xsl:template></xsl:stylesheet>

your XSL transforms to HTML (in fact XHTML): what more do you expect? did you expected anything different from the following output? if yes: what and why?
<html>
     <body>
          <h2>Document Contents</h2>
          <table border="1">
               <tr bgcolor="#9acd32">
                    <th align="center">Document Name</th>
                    <th align="center">Document ID</th>
                    <th align="center">Owner</th>
               </tr>
               <tr>
                    <td>register</td>
                    <td>1</td>
                    <td>hhh</td>
               </tr>
          </table>
     </body>
</html>

Similar Messages

Problem in transforming xml to html using xsl

Hi everybody ,
I am creating a xml in memory and i want to transform using xsl into an html.
I want to embed some html code also in the data node.But when I get the html it simply writes as it is. I tried to make it cdata section but it did not worked. Pls help.
crypticashu
import javax.xml.parsers.DocumentBuilder;
import javax.xml.parsers.DocumentBuilderFactory;
import javax.xml.parsers.ParserConfigurationException;
import javax.xml.transform.dom.DOMSource;
import org.w3c.dom.*;
import javax.xml.transform.*;
import javax.xml.transform.stream.*;
public class mytemp {
     public static void main(String args[])
     DocumentBuilder builder = null;
     Document document = null;
     DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance();
     try
     builder = factory.newDocumentBuilder();
     document = builder.newDocument();
     catch (ParserConfigurationException e)
     e.printStackTrace();
     Element root = (Element) document.createElement("REPORT");
     document.appendChild(root);
     Node child = document.createElement("DATA");
     CDATASection data = document.createCDATASection("<b>Hello World </b>");
     child.appendChild(data);
     root.appendChild(child);
     document.getDocumentElement().normalize();
     DOMSource domsource = new DOMSource(document);
          TransformerFactory tfactory = TransformerFactory.newInstance();
          File f = new File("c:/mytemp/report.xsl");
          StreamSource xsl = new StreamSource(f);
          File html = new File("c:/myhtml.html");
          try
               Templates templates = tfactory.newTemplates(xsl);
               Transformer transformer = templates.newTransformer();
               transformer.transform(domsource, new StreamResult(html));
          catch(Exception e)
               e.printStackTrace();
     }

want to embed some html code also in the data node.But when I get the html it simply writes as it is.That statement contradicts:
In real application i will be getting data containg html tags.I want the parser to read that data as simple text. Both cannot be true. You either want the HTML to not be parsed or you want the transformer to deal with it. Which one?
- Saish

JEditorPane - How to display XML Linked HTML File in JEditorPane ?

Dear Friends,
I have a HTML File consisting of stylesheet, xml linked (for data) and with headers, footers...
When i called a ordinary html file using setpage property of JEditorpane..it's working no problem...but when i call the html file having xml linked or buttons...it's not properly displayed....
If anybody hits this problem....pls...help me....
Regards,
V.Prasanna

If you only need to display it, consider your HttpServletRequest just as byte stream. :) Just read from ServletInputStream and write it back into ServletOutputStream of HttpServletResponse.
If you want to process incoming XML, please give some details first, what exactly you want to do. :)

Idoc-xi-file scenario. how to display file in html format

I am not sure whether this is a valid question.........but want to confirm as it was asked by somebody
In idoc-xi-file scenario....... how to display file in html format ??
Thanks in advance
Kumar

Hi Vijayakumar,
Thanks for your reply !! You mean to say I got to use XSLT mapping and also .htm and .html extension together to produce the html file ?? or it is sufficient to use any one of them to produce the html file ??
Regards
Kumar

How to do Grouping of Workbooks using XSL in Discoverer Viewer?

Hello Discoverer Experts,
My question is related to grouping of workbook names using XSL in Discoverer Viewer. This is a sample xml data file which contains 6 workbooks.
<eul>
     <workbooks>
          <workbook>
               <wb_name>Purchasing Workbook 1</wb_name>
               <worksheets>
                    <worksheet>
                         <ws_name>A</ws_name>
                    </worksheet>
                    <worksheet>
                         <ws_name>B</ws_name>
                    </worksheet>
               </worksheets>
          </workbook>
          <workbook>
               <wb_name>Purchasing Workbook 2</wb_name>
               <worksheets>
                    <worksheet>
                         <ws_name>C</ws_name>
                    </worksheet>
                    <worksheet>
                         <ws_name>D</ws_name>
                    </worksheet>
               </worksheets>
          </workbook>
          <workbook>
               <wb_name>Manufacturing Workbook 1</wb_name>
               <worksheets>
                    <worksheet>
                         <ws_name>E</ws_name>
                    </worksheet>
                    <worksheet>
                         <ws_name>F</ws_name>
                    </worksheet>
               </worksheets>
          </workbook>
          <workbook>
               <wb_name>Manufacturing Workbook 2</wb_name>
               <worksheets>
                    <worksheet>
                         <ws_name>G</ws_name>
                    </worksheet>
                    <worksheet>
                         <ws_name>H</ws_name>
                    </worksheet>
               </worksheets>
          </workbook>
          <workbook>
               <wb_name>CEO Workbook 1</wb_name>
               <worksheets>
                    <worksheet>
                         <ws_name>I</ws_name>
                    </worksheet>
                    <worksheet>
                         <ws_name>J</ws_name>
                    </worksheet>
               </worksheets>
          </workbook>
          <workbook>
               <wb_name>CEO Workbook 2</wb_name>
               <worksheets>
                    <worksheet>
                         <ws_name>K</ws_name>
                    </worksheet>
                    <worksheet>
                         <ws_name>L</ws_name>
                    </worksheet>
               </worksheets>
          </workbook>
     </workbooks>
</eul>
The XSL is generating a List of Workbooks in <table> by using <xsl:for-each select="eul/workbooks/workbook">
<table>
<tr><td>Purchasing Workbook 1</td></tr>
<tr><td>Purchasing Workbook 2</td></tr>
<tr><td>Manufacturing Workbook 1</td></tr>
<tr><td>Manufacturing Workbook 2</td></tr>
<tr><td>CEO Workbook 1</td></tr>
<tr><td>CEO Workbook 2</td></tr>
</table>
Now my question is:
1. The client want to see this report in Groups i.e
<table>
<tr><th>Group Name: Purchasing</th></tr>
<tr><td>Purchasing Workbook 1</td></tr>
<tr><td>Purchasing Workbook 2</td></tr>
</table>
<table>
<tr><th>Group Name: Manufacturing</th></tr>
<tr><td>Manufacturing Workbook 1</td></tr>
<tr><td>Manufacturing Workbook 2</td></tr>
</table>
<table>
<tr><th>Group Name: CEO</th></tr>
<tr><td>CEO Workbook 1</td></tr>
<tr><td>CEO Workbook 2</td></tr>
</table>
How can I achieve this grouping using XSL ? Has anybody tried customizing the XSL file to achieve grouping of workbooks by name?
Any help is highly appreciated.
Thanks in advance.
Warm Regards,
Pranav Desai

Hi Friends..
This is not the reply.
I have also some question..
Some related topic I found on this.
That's why I am posting the same question here also..
Dear friends..
I need help to customize our discoverer viewer.
We are creating work sheets in arial font size 8.
But, when it's viewing through discoverer viewer it's coming big size.
If we saw the source code by right click, it's taking some style sheets where
the font size is mentioned as 8. not 8px.
How I can modify the work sheets in viewer.
Exactly which tag I should modify for this.
And the other thing is the heading section is coming something as
jung.
Like this...
&nb12.09.52 PM 27-OCT-02; 27-OCT-02 &n12.09.52 PM12.09.52 PM
From: 01-JAN-2002 To: 30-DEC-2002o Page :1 / 1
How we will correct this ?
Please reply me as the earliest.
With Thanks & Regards,
Sheeja
[email protected]

Conversion from xml to csv using xsl

hi i am converting from xml to csv using xsl i am getting the extra junk character(space) in the csv file.below i written the xml file and xsl file
xml file
<?xml version="1.0" encoding="UTF-8" standalone="yes"?>
<?xml-stylesheet type="text/xsl"?>
<DOCUMENTS>
     <FILE>
     <DOCUMENT>
          <BUSINESS>finance</BUSINESS>
          <PROGRAM>CM</PROGRAM>
          <PROJECT>Testing Area</PROJECT>
          <NAME>121940~1.doc</NAME>
          <TEXT>SQL</TEXT>
          <LINK>http://www.sql.org/</LINK>
     </DOCUMENT>
     <DOCUMENT>
          <BUSINESS>finance</BUSINESS>
          <PROGRAM>CM</PROGRAM>
          <PROJECT>Testing Area</PROJECT>
          <NAME>121940~1.doc</NAME>
          <TEXT>Information</TEXT>
          <LINK>http://google.com/</LINK>
     </DOCUMENT>
     <DOCUMENT>
          <BUSINESS>finance</BUSINESS>
          <PROGRAM>CM</PROGRAM>
          <PROJECT>Testing Area</PROJECT>
          <NAME>121940~1.doc</NAME>
          <TEXT>Configuration</TEXT>
          <LINK>http://msdn.microsoft.com/</LINK>
     </DOCUMENT>
     </FILE>
</DOCUMENTS>
xsl file
<?xml version="1.0"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">
<xsl:output method="text" indent="yes"/>
<xsl:template match="DOCUMENTS">
<xsl:text>Business,Program,Project,DocumentName,Textforlink,Hyperlink</xsl:text>
<xsl:apply-templates/>
</xsl:template>
<xsl:template match="FILE">
<xsl:value-of select="DOCUMENT/BUSINESS"/>
<xsl:value-of select="','"/>
<xsl:value-of select="DOCUMENT/PROGRAM"/>
<xsl:value-of select="','"/>
<xsl:value-of select="DOCUMENT/PROJECT"/>
<xsl:value-of select="','"/>
<xsl:value-of select="DOCUMENT/NAME"/>
<xsl:apply-templates/>
</xsl:template>
<xsl:template match="DOCUMENT">
<xsl:value-of select="','"/>
<xsl:value-of select="','"/>
<xsl:value-of select="','"/>
<xsl:value-of select="','"/>
<xsl:value-of select="TEXT"/>
<xsl:value-of select="','"/>
<xsl:value-of select="LINK"/>
</xsl:template>
</xsl:stylesheet>
for converting to csv i am using java program.
please go through it.

<xsl:value-of select="','"/>That's not the correct way to output a literal comma. Just write the comma directly, or use xsl:text. And don't put in those line breaks either. You can reduce the rule for FILE to something like this:
xsl:template match="FILE">
<xsl:value-of select="DOCUMENT/BUSINESS"/>, <xsl:value-of select="DOCUMENT/PROGRAM"/>, <xsl:value-of select="DOCUMENT/PROJECT"/>, <xsl:value-of select="DOCUMENT/NAME"/>
<xsl:apply-templates/>
</xsl:template>

How to Display XML in a UIWebView?

Hi everybody. I like how Safari displays XML files and I would like to emulate that functionality in an iPhone UIWebView. However, I just can't get it to look the same when passing a URL to the UIWebView.
For example, take a simple XML file like http://molottery.com/rss-num.xml. Viewing that in Safari looks okay, but passing that same URL into a UIWebView just shows a blank page.
I changed the web protocol from http to feed (feed://molottery.com/rss-num.xml) and it launches the page in Safari instead of my UIWebView. Looks good, but it quit my app... :- (
I noticed that XML files on the iPhone get re-routed through reader.mac.com so I tried appending that to my URL (http://reader.mac.com/mobile/v1/http://molottery.com/rss-num.xml) but that did not work either.
When I tried URLEncoding the string like Safari does (http://reader.mac.com/mobile/v1/http%3A%2F%2Fmolottery.com%2Frss-num.xml) I get a UIWebView saying that "This Application Is Viewable Only On iPhone".
So how can I emulate the regular Safari XML functionality inside my UIWebView? I will post my code upon request, if that will help. Any assistance from the Developer Community would be greatly appreciated.
Thanks!

You may have better luck in the iPhone dev forums...
https://devforums.apple.com/community/iphone/web

How to display all the surveys using content query web part

Can you please tell me how to display all the surveys using content query web part in more details? I also created a subsite and multiple surveys in that site. Then, I inserted a Content Query Web Part and select the List Type to be "Survey",
however, it returned nothing. Did I miss anything?

Hi,
OOTB Survey List does not contain any
Content Types and it has the following structure:
Response entry is represented by
List Item
Response entry consist of questions and answers, where Question correspond to
Field and Answer to Item value respectively.
For querying Survey List via CQWP the following properties could be used
BaseType
<Lists BaseType="4">
ServerTemplate
<Lists ServerTemplate="102">
Example
To retrieve all the responses from Survey lists, specify List Type property as shown on picture
Reference:
http://stackoverflow.com/questions/17280778/display-all-surveys-using-content-query-web-part
Best Regards,
Eric
TechNet Community Support
Please remember to mark the replies as answers if they help, and unmark the answers if they provide no help. If you have feedback for TechNet Support, contact
[email protected]

How to display smartforms table lines useing different background colour

Hi all:
How to display smartforms table lines useing different background colour .
for example:
line1:green
line2:red
line3:green
line4:red
line5:green
line6:red
line7:green
line8:red
Any help is highly appreciated!!
启明星

Hi,
Create a two lines one for header and second for data in the table.
1)In table painter we can find the pencil mark.
2)select the pencil mark
3)now select the line which you need to shade
4) now select the shading colour in the table painter and the provide the resolution up to 100% and select table pattrn for that line.
5) Now you can use this for the header now only the header gets shaded and the remaining gets unshaded.
reward points if useful
Thanks and Regards,
Nishant

How to display another window by using Check box

Hi Friends,
I have one doubt in Webdynpro with java. How to display another window by using Check box?
For Exam My requirement is I am getting BAPI from ECC System. So I have to go given input details in first view and output details in Second View. So in Second View I will taken Table that data will displayed in rows. each and every row first check box is available.
Here Select Check Box of particular row then click Edit button. That row data will be displayed in one popup window.
empid, name, sal ,firstname, last Name
empid, name, sal ,firstname, last Name
empid, name, sal ,firstname, last Name
Suppose I have to select check box in First Row Click on EDIT button That row data will be displayed in another popup window here customer will change details depending up requirement click on SAVE Button that update data will saved in ECC System.
How to display another window by using Check box?
Regards
Vijay

Hi Vijay
Your question is not clear enough to give an answer. Do you have some difficulties with the code for opening a popup-window? There are many-many examples in the forum how to open/close a popup.
Or you do not know how to bind the popup opening with clicking a check box? Just put the code in the onSelect event handler of the check box.
BR, Siarhei
Edited by: Siarhei Pisarenka on Mar 11, 2010 10:55 AM

How to display items from database using catagorylookupdroplet

Hi everyone,
i want to know how to display items from database using catagorylookup droplet. if anybody have any code snippet please share it.
Thanks in advance,

<dsp:droplet name=".................../CategoryLookup">
     <dsp:param name="id" param="itemId"/>
     <dsp:oparam name="output">
          <dsp:valueof param="element.displayName"/>
               <%-- This is show the Child Category --%>
               <dsp:droplet name="......................./ForEach">
               <dsp:param name="array" param="element.childCategories"/>
               <dsp:oparam name="outputStart">Child Categories</dsp:oparam>
               <dsp:oparam name="output">
                    <dsp:a href="">//bydefault it will take its own file's name
                         <dsp:param name="itemId" param="element.repositoryId"/>                                                                                          <dsp:valueof param="element.displayName"/>
                    </dsp:a>
               </dsp:oparam>
               </dsp:droplet>
               <%-- This is show the Child Product --%>
               <dsp:droplet name=".............../ForEach">
                    <dsp:param name="array" param="element.childProducts"/>
                    <dsp:oparam name="outputStart">Child Products</dsp:oparam>
                              <dsp:oparam name="output">
                                   <dsp:droplet name="................/ProductLookup">
                                        <dsp:param name="id" param="itemId"/>
                                        <dsp:param name="elementName" value="Prod"/>
                                        <dsp:oparam name="output">
                                             <dsp:getvalueof id="img102" param="Prod.smallImage.url" idtype="java.lang.String">
                                                  <dsp:img height="250" width="250" src="<%=img102%>"/>
                                             </dsp:getvalueof>
                                        </dsp:oparam>
                                   </dsp:droplet>
                                   <dsp:a href="productView.jsp">
                                        <dsp:param name="itemId" param="element.repositoryId"/>
                                        <dsp:valueof param="element.displayName"/>
                                   </dsp:a>
Hope this helps.
-RMishra

ENTITIES and transforming XML to XML/HTML using XSL

I am going absolutely nuts. When using XSL to transform an XML
file to HTML or another XML schema, critical entities dissappear.
For example:
<oldtag>press "any" key</oldtag>
will get rendered to
<newtag>press "any" key</newtag>
by the XML/XSL parser, which is not valid HTML or XML.
How do I preserve these entities through the transformation
process. Escaping the text (in the XML source) with <![CDATA[]]
is not possible in this case.--Michael
null

Assuming you can't use a CDATA in the DTD to prevent parsing,
then my suggestion would be to use the XSL stylesheet to restore
the entities as there is no way that I am aware of that will set
conditional expansion.
Oracle XML Team
http://technet.oracle.com
Oracle Technology Network
Michael Van Auken (guest) wrote:
: I am going absolutely nuts. When using XSL to transform an
XML
: file to HTML or another XML schema, critical entities
dissappear.
: For example:
: <oldtag>press "any" key</oldtag>
: will get rendered to
: <newtag>press "any" key</newtag>
: by the XML/XSL parser, which is not valid HTML or XML.
: How do I preserve these entities through the transformation
: process. Escaping the text (in the XML source) with <![CDATA
: > is not possible in this case.
: --Michael
null

Converting XML document to HTMl using xsl

Hi,
I'm trying to convert an xml document into html page using xsl. But when I try to open the page in the browser nothing comes up.
I'm not sure if I am using the PrintWriter correctly.
StreamResult result = new StreamResult(new PrintWriter(new (File"text.html")));
Please help.

Oops! I wrote the parenthesis wrong in the previous mail
This is the correct one I use in my program.
StreamResult result = new StreamResult(new PrintWriter(new File("text.html")));
Please help. Its urgent

Image not displaying in pdf report using XSL-FO and using Oracle 11g databa

Good Afternoon,
I have created over 15 reports using XSL-fo, with the following syntax to display an image on the pdf:
fo:block margin-left="0.24cm" margin-right="0.27cm" margin-top="0.0cm" ><fo:external-graphic content-width="scale-to-fit" content-height="scale-to-fit" width="1.73cm" height="1.57cm" >
<xsl:attribute name="src">'url("http://readiness:7780/i/marforcom_symbol_rpts.gif")'</xsl:attribute></fo:external-graphic>
</fo:block>
This syntax works fine when using Oracle 10g, now my database has been upgraded to 11g and my image no longer displays in the reports. I have already upload the image into the database as a workspace image.
I have tried to point the image @ the image by using url(#WORKSPACE_IMAGE#marforcom_symbol_rpts.gif)
or <img src ="#IMAGE_PREFIX#marforcom_symbol_rpts.gif")
and it still doesn't work.
I have searched this forum trying to come up with a solution that will fix my problem and am unable to.
Current config: Oracle 11g, using pl/sql gateway.
I need to know how to point the xsl-fo file to the database, where the image now resides.
Thanks,
Mary
Edited by: MaryM on Jul 25, 2012 3:15 PM
Edited by: MaryM on Jul 25, 2012 3:51 PM

Hi,
I think you need load images to database XDB virtual directory /i/ and then use #IMAGE_PREFIX# substitution.
This might help to access /i/
http://www.apex-blog.com/oracle-apex/accessing-i-using-ftp-170.html
Or use this to load images
http://oracleinsights.blogspot.fi/2012/05/loading-images-into-oracle-xdb.html
Regards,
Jari
My Blog: http://dbswh.webhop.net/dbswh/f?p=BLOG:HOME:0
Twitter: http://www.twitter.com/jariolai

How to display Xml in a JEditorPane(in an applet)

Hi All,
I have an applet and i want to display xml in a JEditorPane in an applet. This xml document has a xsl attached to it for transformation. How can i do the transformation??
Help or sample code or link to a sample code is highly appreciated!!!!
Thanks
Ragu

Look this servlet which does a transformation. JEditorPane could call this servlet (with the method setPage) to do the transformation:
public class SampleXSLTServlet extends javax.servlet.http.HttpServlet {
public final static String FS = System.getProperty("file.separator");
// Respond to HTTP GET requests from browsers.
public void doGet (javax.servlet.http.HttpServletRequest request,
javax.servlet.http.HttpServletResponse response)
throws javax.servlet.ServletException, java.io.IOException
// Set content type for HTML.
response.setContentType("text/html; charset=UTF-8");
// Output goes to the response PrintWriter.
java.io.PrintWriter out = response.getWriter());
try
javax.xml.transform.TransformerFactory tFactory =
javax.xml.transform.TransformerFactory.newInstance();
//get the real path for xml and xsl files.
String ctx = getServletContext().getRealPath("") + FS;
// Get the XML input document and the stylesheet, both in the servlet
// engine document directory.
javax.xml.transform.Source xmlSource =
new javax.xml.transform.stream.StreamSource
(new java.net.URL("file", "", ctx+"foo.xml").openStream());
javax.xml.transform.Source xslSource =
new javax.xml.transform.stream.StreamSource
(new java.net.URL("file", "", ctx+"foo.xsl").openStream());
// Generate the transformer.
javax.xml.transform.Transformer transformer =
tFactory.newTransformer(xslSource);
// Perform the transformation, sending the output to the response.
transformer.transform(xmlSource,
new javax.xml.transform.stream.StreamResult(out));
// If an Exception occurs, return the error to the client.
catch (Exception e)
out.write(e.getMessage());
e.printStackTrace(out);
// Close the PrintWriter.
out.close();

How to display xml to html using xsl?

Similar Messages

Maybe you are looking for