How to fetch the records which matches a partial value?

Question

Hi,
I have a table called Employee which contains the following value in Category column
ID Value
1 Student,Staff
2 Staff
3 Parent,Student
4 Member,Staff,Student
I wanted to fetch only 1 and 3rd and 4th record since it matches the value Student.
basically looking for the exact pattern matched with student separated by comma.
how to perform this query. it would be great, if i get the query in MS Sql also.
Edited by: Pannar on Nov 1, 2009 7:08 PM

Answer 1

Hi,
I'm sure the regexps will pass by, but here's a way (no idea if this will run in MS SQL, I'm not familiar with that):
HO%xe> with employee as ( --generating your sample data:
2  select 1 id, 'Student,Staff' category from dual union all
3  select 2, 'Staff' from dual union all
4  select 3, 'Parent,Student' from dual union all
5  select 4 ,'Member,Staff,Student' from dual
6  )
7  --
8  -- Actual query:
9  --
10  select id
11  ,      category
12  from   employee
13  where  category like '%Student%'
14  and    instr(category, ',')>0;
       ID CATEGORY
        1 Student,Staff
        3 Parent,Student
        4 Member,Staff,StudentYou can use UPPER or LOWER as well, if you want to be case-insensitive.
edit
Something like:
MHO%xe> with employee as ( --generating your sample data:
  2  select 1 id, 'Student,Staff' category from dual union all
  3  select 2, 'Staff' from dual union all
  4  select 3, 'Parent,Student' from dual union all
  5  select 4 ,'Member,Staff,Student' from dual union all
  6  select 5, 'Student' from dual union all
  7  select 6, 'Student,' from dual
  8  )
  9  --
10  -- Actual query:
11  --
12  select id
13  ,      category
14  from   employee
15  where  regexp_like(category,',Student|Student,');
        ID CATEGORY
         1 Student,Staff
         3 Parent,Student
         4 Member,Staff,Student
         6 Student,Might work as well.
Edited by: hoek on Nov 1, 2009 2:50 PM