How to find the tables which are the candidates for gathering stats in 10g
Hi,
In 10g how can we find the tables, partitions which are the candidates for gathering the stats.
I want to findo those tables, partitions and gather the stats on daily basis.
Thanks,
Mahi
The probem you describe has been posted about before. There are known issues with the default dbms_stats parameter settings for some environements.
What you can do is just go ahead an manually submit dbms_stats commands with appropriate parameters for tables that have not been analyzed or modify the maintenance window to give it more time.
I would rather just generate the missing statistics myself then the job can continue to run in the normal maintenance window. Since the job should be looking only for tables that meet the stale requirements then once everything is analyzed it is likely the job can keep the statistics updated in the default time allowed.
Be warned that the default parameter settings do not work well for some tables in some environments and if that proves true for your shop you can generate workable statistics on a table and then lock them so the nightly job ships regenerating the statistics for that table. You would then manually unlock, generate, and lock that statistics for that table as necessary.
HTH -- Mark D Powell --
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Thanks for your reply...
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open the following link.
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Something like the following will retrieve the table operators in a map:
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How to find all tables that are associated with a given domain name.
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the topic should already say everything.
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Need some help on CRM tables which have the details of the order created
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basically you link partner function of an order with view:
CRMV_LINKPARTNER.
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For sold-to-party you have to select 00000001.
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<b></b> -
Join 2 tables which are not related with any primary-foriegn key constraint
Hello,
How to join 2 tables which are not related with any primary key foreign key constraint.
Ex.Consider Table A has 5 columns->A_ID,A_Name,A_Address,A_City,A_Pin(Total 10 rows)
Table B has 5 columns->B_ID,B_Name,B_Adress,B_City,B_City(Total 30 rows)
From both the table i want the data,which i need to use in curosr to display finally as "Address Label".
Both the table are entirely different,but there can be some names of Table A which may come in Table B also,if the name,address and city is also same.That means same person in both the table.
So finally i want total number of distinct records(distinct data of Table A which is not in B+all the data of table B) to come under Address Label.
How can i write the select query for this condition?
Thanks
SwapnaHi, Swapna,
user11018268 wrote:
Hello,
How to join 2 tables which are not related with any primary key foreign key constraint.
Ex.Consider Table A has 5 columns->A_ID,A_Name,A_Address,A_City,A_Pin(Total 10 rows)
Table B has 5 columns->B_ID,B_Name,B_Adress,B_City,B_City(Total 30 rows)
Both the table are entirely different,but there can be some names of Table A which may come in Table B also,if the name,address and city is also same.That means same person in both the table.I think you want a UNION, not a join.
If you have 10 rows in table_a, and 30 rows in table_b, then
SELECT A_ID, A_Name, A_Address, A_City, A_Pin
FROM table_a
UNION
SELECT B_ID, B_Name, B_Adress, B_City, B_City
FROM table_b
ORDER BY 2, 4
;will produce up to 40 rows; 40 if there are no duplicates. (UNION implies DISTINCT.)
The corresponding column types should be similar, if not exactly the same.
There's no problem if A_Name is VARCHAR2 (50) and B_Name is CHAR (30).
However, there will be a problem if A_ID is a NUMBER and B_ID is a TIMESTAMP.
You must have the same number of columns in all branches of the UNION.
If you want an ORDER BY clause, put it at the very end, after the last branch of the UNION.
You can use positional notation (where 2 means the 2nd column) like I did, or you can use names from the first prong of the UNION (such as A_Name).
From both the table i want the data,which i need to use in curosr to display finally as "Address Label".
So finally i want total number of distinct records(distinct data of Table A which is not in B+all the data of table B) to come under Address Label.I'm not sure what your mean about "Address Label".
Whenever you have a question, post a little sample data (CREATE TABLE and INSERT statements, relevant columns only) from all tables, and the exact results (formatted) that you want from that data.
You can concatenate all 5 columns into one VARCHAR2 column, if you want to.
You'll probably want to use RPAD (or simillar functions) to make the output line up nicely.
If any of the columns are not strings, use TO_CHAR to make string versions of them.
For example:
SELECT TO_CHAR (A_ID, '9999999')
|| ' ' -- leave a little space between the left-justified a_id and the right-justified a_name
|| RPAD (A_Name, 25)
|| RPAD (A_Address, 50)
...Edited by: Frank Kulash on Nov 14, 2009 10:11 AM
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