How to get the date for the first monday of each month

Dear Members,
How to get the date for the first monday of each month.
I have written the following code
SELECT decode (to_char(trunc(sysdate+30 ,'MM'),'DAY'),'MONDAY ',trunc(sysdate+30 ,'MM'),NEXT_DAY(trunc(sysdate+30 ,'MM'), 'MON')) FROM DUAL
But it look bith complex.
Abhishek
Edited by: 9999999 on Mar 8, 2013 4:30 AM

Use IW format - it will make solution NLS independent. And all you need is truncate 7<sup>th</sup> day of each month using IW:
select sysdate current_date,
        trunc(trunc(sysdate,'mm') + 6,'iw') first_monday_the_month
from dual
CURRENT_D FIRST_MON
08-MAR-13 04-MAR-13
SQL> Below is list of first monday of the month for this year:
with t as(
          select add_months(date '2013-1-1',level-1) dt
            from dual
            connect by level <= 12
select dt first_of_the_month,
        trunc(dt + 6,'iw') first_monday_the_month
from t
FIRST_OF_ FIRST_MON
01-JAN-13 07-JAN-13
01-FEB-13 04-FEB-13
01-MAR-13 04-MAR-13
01-APR-13 01-APR-13
01-MAY-13 06-MAY-13
01-JUN-13 03-JUN-13
01-JUL-13 01-JUL-13
01-AUG-13 05-AUG-13
01-SEP-13 02-SEP-13
01-OCT-13 07-OCT-13
01-NOV-13 04-NOV-13
FIRST_OF_ FIRST_MON
01-DEC-13 02-DEC-13
12 rows selected.
SQL> SY.

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