How to get the failover partner name from C++ client

Hi All,
I have configured the mirroring session for my application.
I want to modify the connection string with failover partner name.
Could any one please let me to know how to get the failover partner instance from C++ client dynamically.
Thanks,
Prasad.

Are you looking for this?
http://www.connectionstrings.com/sql-server-2012/
http://stackoverflow.com/questions/25534972/auto-failover-multiple-connections-to-mirror-database-when-principal-goes-down

Similar Messages

How to get the Portal Page name from PLSQL?

Can anyone tell me how to get the portal page name from my dynamic page using plsql?
Apparently you can get the page id and work it out from there, but my calls to get the page id are not returning any values anyway.
My code for attempting to get the page id is below.
<oracle>
declare
v_pageid varchar2(30);
begin
v_pageid := wwpro_api_parameters.get_value('_pageid', '/pls/portal30');
htp.print('Page is '|| v_pageid);
end;
</oracle>
Ideally I'd actually just like to get the page name. Is there a straightforward way to do this?
Thanks in advance!
Sarah

Few clarifications -
1. wwpro_api_parameters cannot be used to get default portal
page parameters such as '_pageid', '_dad', '_schema' etc.,
2. Page information can be obtained through any components which
are available in that particular page. For example, in case of
dynamic page, we need to publish it as a portlet and add it to the
page. This process creates necessary packages in the DB, but we
will not have access to the portlet methods.
So, I would prefer creating a simple DB provider & portlet and access
page title from its show method as follows -
//Declare local variable l_page_id, l_page_title as varchar2
select page_id into l_page_id from wwpob_portlet_instance$ where
portlet_id = p_portlet_record.portlet_id and
provider_id = p_portlet_record.provider_id;
select name into l_page_title from wwpob_page$ where id=l_page_id;
More information on DB provider can be found at
http://portalstudio.oracle.com/pls/ops/docs/FOLDER/COMMUNITY/PDK/articles/understanding.database.providers.html
Secondly, usage of wwpro_api_parameters.get_value method is
incorrect. This method expects two arguments -
<ul>
<li><b>p_name : </b> The name of the parameter to be returned.</li>
<li><b>p_reference_path : </b> An unique identifier for a portlet instance on the current page.</li>
</ul>
p_reference_path would be something like 99_SNOOP_PORTLET_76535103 and not some type of path as its name suggests.
The following code fragment fetches all parameters available
for a portlet.
Note : Copy this code into 'show' method of your portlet.
//Declare l_names, l_values as owa.vc_arr
* Retreive all of the names of parameters for this portlet
l_names := wwpro_api_parameters.get_names(
p_reference_path=>p_portlet_record.reference_path);
* Retreive all of the values of parameters for this portlet
l_values := wwpro_api_parameters.get_values(p_names=>l_names,
p_reference_path=>p_portlet_record.reference_path);
//Loop through these arrays to get parameter information
htp.p('<center><table BORDER COLS=2 WIDTH="90%" >');
htp.p('<tr ALIGN=LEFT VALIGN=TOP>');
htp.tableData(wwui_api_portlet.portlet_heading('Name',1));
htp.tableData(wwui_api_portlet.portlet_heading('Value',1));
htp.tableRowClose;
if l_names.count = 0 then
htp.p('<tr ALIGN=LEFT VALIGN=TOP>');
htp.p('<td COLSPAN="2">'
||wwui_api_portlet.portlet_text(
'No portlet parameters were passed on the URL.',1)
||'</td>');
htp.tableRowClose;
else
for i in 1..l_names.count loop
htp.p('<tr ALIGN=LEFT VALIGN=TOP>');
htp.tableData(l_names(i));
htp.tableData(l_values(i));
htp.tableRowClose;
end loop;
end if;
htp.p('</table></center>');
Hope it helps...
-aMJAD.

How to get the actual font name from a font file?

Hi
I have only the font Path I have to get the font name from that path. Any idea how to get the actual font name?
Thanks,

I would ask you these questions:
Why do you need to do this? What are you ultimately trying to accomplish?
Are you really asking about the InDesign SDK?
Do you really need to get the "name" of a font from an arbitrary file? Or do you want information about a font installed on the system? If so, what OS?
Do you need to be able to handle any font format?
Which font "name" do you mean?
What language do you want the name in?
(1) It's not clear what you're trying to accomplish. A bit more information about your ultimate goal would be helpful.
(2) This question is not at all specific to the InDesign SDK. Are you really trying to do something in the context of an InDesign plug-in? If so, you probably want to look at IID_IFONTFAMILY and the IFontFamily::GetFamilyName function.
(3) If you are asking more generally, Windows and Mac both have system API calls to get this information, although those tend to deal with installed system fonts, not with arbitrary font files per se.
Also, you can parse the name table from a True Type or Open Type font without using any system APIs; as True Type and Open Type are well-documented standards. I would start by reading these:
The Naming Table
Font Names Table
(4) Although there are other standards, such as Type 1 (PostScript) fonts, and True Type Collection files and other formats, especially on Mac.
(5) Also, when you start down this road, you will quickly realize that your seemingly simple question is actually ambiguous, and that the answer is kind of complicated, because a font can have many names (a family name, a full font name, a style name, a PostScript name, etc.).
(6) And not only does a font have multiple names, it can have each of those names in multiple languages and encodings.
Any clarification would make this a better question.

How to get the pull path name from a file upload window

Hello everyone!
I have encountered the following problem with the following JSP code:
<form method="post" action="filename.jsp">
Upload JAVA program:
<input type=file size=20 name="fname" accept="java">
<input type=submit value="go">
</form>
<%
String s = "";
if (request.getParameter("fname") != null)
s = request.getParameter("fname")
%>
The value of s is alway the filename. However I want to get the full path in addition to the filename, so that I can read the file. Does anyone know how to get the pull name of the file?
thanks a lot in advance,

Dear Sir,
thanks a lot for your reply. Please let me explain what I intended to do: I want to upload a file from the local machine and then read the content of the file. Therefore I need to the fullpath of the filename like /var/local/file.java instead of file.java. The latter is what I got.
The problem I have with your code is that the function like "request.getServerScheme()" is not recognized. Maybe is it because I didn't install servelet package? I only installed javax package btw. Also my application runns on Tomcat server if this could give you some information. The error message I had is as follows:
org.apache.jasper.JasperException: Unable to compile class for JSP
An error occurred at line: 36 in the jsp file: /addExercise.jsp
Generated servlet error:
[javac] Compiling 1 source file
/usr/local/jakarta-tomcat-5.0.12/work/Catalina/localhost/tutor/org/apache/jsp/addExercise_jsp.java:133: cannot resolve symbol
symbol : method getServerScheme ()
location: interface javax.servlet.http.HttpServletRequest
url = request.getServerScheme()
^
An error occurred at line: 36 in the jsp file: /addExercise.jsp
Generated servlet error:
/usr/local/jakarta-tomcat-5.0.12/work/Catalina/localhost/tutor/org/apache/jsp/addExercise_jsp.java:136: cannot resolve symbol
symbol : method getServerScheme ()
location: interface javax.servlet.http.HttpServletRequest
+ ((("http".equals(request.getServerScheme()) && request.getServerPort() != 80)
^
An error occurred at line: 36 in the jsp file: /addExercise.jsp
Generated servlet error:
/usr/local/jakarta-tomcat-5.0.12/work/Catalina/localhost/tutor/org/apache/jsp/addExercise_jsp.java:137: cannot resolve symbol
symbol : method getServerScheme ()
location: interface javax.servlet.http.HttpServletRequest
||("https".equals(request.getServerScheme()) && request.getServerPort() != 443))
^
An error occurred at line: 36 in the jsp file: /addExercise.jsp
Generated servlet error:
/usr/local/jakarta-tomcat-5.0.12/work/Catalina/localhost/tutor/org/apache/jsp/addExercise_jsp.java:139: cannot resolve symbol
symbol : method getServletConfig ()
location: interface javax.servlet.http.HttpServletRequest
+ "/" + request.getServletConfig().getServletName()
^
An error occurred at line: 36 in the jsp file: /addExercise.jsp
Generated servlet error:
/usr/local/jakarta-tomcat-5.0.12/work/Catalina/localhost/tutor/org/apache/jsp/addExercise_jsp.java:140: cannot resolve symbol
symbol : variable path
location: class org.apache.jsp.addExercise_jsp
+ "/" + path
^
5 errors
     org.apache.jasper.compiler.DefaultErrorHandler.javacError(DefaultErrorHandler.java:128)
     org.apache.jasper.compiler.ErrorDispatcher.javacError(ErrorDispatcher.java:351)
     org.apache.jasper.compiler.Compiler.generateClass(Compiler.java:413)
     org.apache.jasper.compiler.Compiler.compile(Compiler.java:453)
     org.apache.jasper.compiler.Compiler.compile(Compiler.java:437)
     org.apache.jasper.JspCompilationContext.compile(JspCompilationContext.java:555)
     org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:291)
     org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:301)
     org.apache.jasper.servlet.JspServlet.service(JspServlet.java:248)
     javax.servlet.http.HttpServlet.service(HttpServlet.java:856)

How to get the long file name from an 8.3 name in Windows.

Because of a legacy string limitation, I have a list of files in 8.3 format. The actual files are saved with long names. How can I get the long name from the short name?
In JavaScript, I would get a file system object and get the file object from there with the short name. Then it's no problem to get the full name. But I don't see anything in Java that matches that. ???
Ideas?
Frank Perry, MSEE

Here is what I did.
String displayName = "somefi~1.txt";
File fO = new File("c:\\"); // I have a more involved path but that's not important here.
String stPath = fO.getPath() + displayName;
File fD = new File(stPath); // get the file using the short name.
File fDc = new File(fD.getCanonicalPath()); // get another file using the cononical name
String FulldisplayName = fDc.getName(); // get the long name from there.
It's roundabout but it works. Since getName() on the file read with the short name only returns the name used to get the file, I open it twice. The alternative is to parse the cononical name for the file name but that's clumbsy too.
Frank

How to get the target file name from an URL?

Hi there,
I am trying to download data from an URL and save the content in a file that have the same name as the file on the server. In some way, what I want to do is pretty similar to what you can do when you do a right click on a link in Internet Explorer (or any other web browser) and choose "save target as".
If the URL is a direct link to the file (for example: http://java.sun.com/images/e8_java_logo_red.jpg ), I do not have any problem:
URL url = new URL("http://java.sun.com/images/e8_java_logo_red.jpg");
System.out.println("Opening connection to " + url + "...");
// Copy resource to local file
InputStream is = url.openStream();
FileOutputStream fos=null;
String fileName = null;
StringTokenizer st=new StringTokenizer(url.getFile(), "/");
while (st.hasMoreTokens())
                fileName=st.nextToken();
System.out.println("The file name will be: " + fileName);
File localFile= new File(System.getProperty("user.dir"), fileName);
fos = new FileOutputStream(localFile);
try {
    byte[] buf = new byte[1024];
    int i = 0;
    while ((i = is.read(buf)) != -1) {
        fos.write(buf, 0, i);
} catch (Throwable e) {
    e.printStackTrace();
} finally {
    if (is != null)
        is.close();
    if (fos != null)
        fos.close();
}Everything is fine, the file name I get is "e8_java_logo_red.jpg", which is what I expect to get.
However, if the URL is an indirect link to the file (for example: http://javadl.sun.com/webapps/download/AutoDL?BundleId=37719 , which link to a file named JavaSetup6u18-rv.exe ), the similar code return AutoDL?BundleId=37719 as file name, when I would like to have JavaSetup6u18-rv.exe .
URL url = new URL("http://javadl.sun.com/webapps/download/AutoDL?BundleId=37719");
System.out.println("Opening connection to " + url + "...");
// Copy resource to local file
InputStream is = url.openStream();
FileOutputStream fos=null;
String fileName = null;
StringTokenizer st=new StringTokenizer(url.getFile(), "/");
while (st.hasMoreTokens())
                fileName=st.nextToken();
System.out.println("The file name will be: " + fileName);
File localFile= new File(System.getProperty("user.dir"), fileName);
fos = new FileOutputStream(localFile);
try {
    byte[] buf = new byte[1024];
    int i = 0;
    while ((i = is.read(buf)) != -1) {
        fos.write(buf, 0, i);
} catch (Throwable e) {
    e.printStackTrace();
} finally {
    if (is != null)
        is.close();
    if (fos != null)
        fos.close();
}Do you know how I can do that.
Thanks for your help
// JB
Edited by: jb-from-sydney on Feb 9, 2010 10:37 PM

Thanks for your answer.
By following your idea, I found out that one of the header ( content-disposition ) can contain the name to be used if the file is downloaded. Here is the full code that allow you to download locally a file on the Internet:
      * Download locally a file from a given URL.
      * @param url - the url.
      * @param destinationFolder - The destination folder.
      * @return the file
      * @throws IOException Signals that an I/O exception has occurred.
     public static final File downloadFile(URL url, File destinationFolder) throws IOException {
          URLConnection urlC = url.openConnection();
          InputStream is = urlC.getInputStream();
          FileOutputStream fos = null;
          String fileName = getFileName(urlC);
          destinationFolder.mkdirs();
          File localFile = new File(destinationFolder, fileName);
          fos = new FileOutputStream(localFile);
          try {
               byte[] buf = new byte[1024];
               int i = 0;
               while ((i = is.read(buf)) != -1) {
                    fos.write(buf, 0, i);
          } finally {
               if (is != null)
                    is.close();
               if (fos != null)
                    fos.close();
          return localFile;
      * Returns the file name associated to an url connection.<br />
      * The result is not a path but just a file name.
      * @param urlC - the url connection
      * @return the file name
      * @throws IOException Signals that an I/O exception has occurred.
     private static final String getFileName(URLConnection urlC) throws IOException {
          String fileName = null;
          String contentDisposition = urlC.getHeaderField("content-disposition");
          if (contentDisposition != null) {
               fileName = extractFileNameFromContentDisposition(contentDisposition);
          // if the file name cannot be extracted from the content-disposition
          // header, using the url.getFilename() method
          if (fileName == null) {
               StringTokenizer st = new StringTokenizer(urlC.getURL().getFile(), "/");
               while (st.hasMoreTokens())
                    fileName = st.nextToken();
          return fileName;
      * Extract the file name from the content disposition header.
      * <p>
      * See <a
      * href="http://www.w3.org/Protocols/rfc2616/rfc2616-sec19.html">http:
      * //www.w3.org/Protocols/rfc2616/rfc2616-sec19.html</a> for detailled
      * information regarding the headers in HTML.
      * @param contentDisposition - the content-disposition header. Cannot be
      *            <code>null>/code>.
      * @return the file name, or <code>null</code> if the content-disposition
      *         header does not contain the filename attribute.
     private static final String extractFileNameFromContentDisposition(
               String contentDisposition) {
          String[] attributes = contentDisposition.split(";");
          for (String a : attributes) {
               if (a.toLowerCase().contains("filename")) {
                    // The attribute is the file name. The filename is between
                    // quotes.
                    return a.substring(a.indexOf('\"') + 1, a.lastIndexOf('\"'));
          // not found
          return null;
     }

How to get customer number and name from the SD document

Hi All,
Can you please let me know how to get Customer Number and Name from the SD Document?
Thanks a lot....
Anil

Hi,
It will be displayed in the SD (BIlling document) itself, you clikc on the VF03. The customer name and number will also appear in the SO document also Tcode VA03
regards,
radhika
Edited by: kolipara radhika on Jul 10, 2009 5:32 AM

How to get the current schema name

Hi,
Can anybody please tell me how to get the current schema name, there is some inbuilt function for this,but i am not getting that. Please help me.
Thanks
Jogesh

ok folks, I found the answer at Tom's as usual.
http://asktom.oracle.com/tkyte/who_called_me/index.html
I rewrote it into a function for kicks. just pass the results of DBMS_UTILITY.FORMAT_CALL_STACK to this function and you will get back the owner of the code making the call as well some extra goodies like the name of the code and the type of code depending on the parameter. This ignores the AUTHID CURRENT_USER issues which muddles the schemaid. Quick question, does the average user always have access to DBMS_UTILITY.FORMAT_CALL_STACK or does this get locked down on some systems?
cheers,
paul
create or replace
FUNCTION SELF_EXAM (
   p_call_stack VARCHAR2,
   p_type VARCHAR2 DEFAULT 'SCHEMA'
) RETURN VARCHAR2
AS
   str_stack   VARCHAR2(4000);
   int_n       PLS_INTEGER;
   str_line    VARCHAR2(255);
   found_stack BOOLEAN DEFAULT FALSE;
   int_cnt     PLS_INTEGER := 0;
   str_caller VARCHAR2(30);
   str_name    VARCHAR2(30);
   str_owner   VARCHAR2(30);
   str_type    VARCHAR2(30);
BEGIN
   str_stack := p_call_stack;
   -- Loop through each line of the call stack
   LOOP
     int_n := INSTR( str_stack, chr(10) );
     EXIT WHEN int_cnt = 3 OR int_n IS NULL OR int_n = 0;
     -- get the line
     str_line := SUBSTR( str_stack, 1, int_n - 1 );
     -- remove the line from the stack str
     str_stack := substr( str_stack, int_n + 1 );
     IF NOT found_stack
     THEN
        IF str_line like '%handle%number%name%'
        THEN
           found_stack := TRUE;
        END IF;
     ELSE
        int_cnt := int_cnt + 1;
         -- cnt = 1 is ME
         -- cnt = 2 is MY Caller
         -- cnt = 3 is Their Caller
         IF int_cnt = 1
         THEN
            str_line := SUBSTR( str_line, 22 );
            dbms_output.put_line('->' || str_line);
            IF str_line LIKE 'pr%'
            THEN
               int_n := LENGTH('procedure ');
            ELSIF str_line LIKE 'fun%'
            THEN
               int_n := LENGTH('function ');
            ELSIF str_line LIKE 'package body%'
            THEN
               int_n := LENGTH('package body ');
            ELSIF str_line LIKE 'pack%'
            THEN
               int_n := LENGTH('package ');
            ELSIF str_line LIKE 'anonymous%'
            THEN
               int_n := LENGTH('anonymous block ');
            ELSE
               int_n := null;
            END IF;
            IF int_n IS NOT NULL
            THEN
               str_type := LTRIM(RTRIM(UPPER(SUBSTR( str_line, 1, int_n - 1 ))));
             ELSE
               str_type := 'TRIGGER';
             END IF;
             str_line := SUBSTR( str_line, NVL(int_n,1) );
             int_n     := INSTR( str_line, '.' );
             str_owner := LTRIM(RTRIM(SUBSTR( str_line, 1, int_n - 1 )));
             str_name := LTRIM(RTRIM(SUBSTR( str_line, int_n + 1 )));
          END IF;
       END IF;
   END LOOP;
   IF UPPER(p_type) = 'NAME'
   THEN
      RETURN str_name;
   ELSIF UPPER(p_type) = 'SCHEMA.NAME'
   OR    UPPER(p_type) = 'OWNER.NAME'
   THEN
      RETURN str_owner || '.' || str_name;
   ELSIF UPPER(p_type) = 'TYPE'
   THEN
      RETURN str_type;
   ELSE
      RETURN str_owner;
   END IF;
END SELF_EXAM;

How to get list of file names from a directory?

How to get list of file names from a directory?
Please help

In addition, this:
String filename = files;Should be this:
String filename = files;
That's just because he didn't use the "code" tags, so [ i ] made everything following it become italicized.

How to get the report server name in Forms 10g.

How to get the report server name in Forms 10g.
I'm using the Application Server 10g 10.1.2.

Hello,
I do not think that you can get this value from anywhere. A solution is to put the Reports server name in an environment variable stored in the /forms/server/default.env file, then to query it at Forms runtime with the TOOL_ENV.Getvar() built-in.
Francois

How to retrieve the all user name from system domain(including login user)?

Hi, I am trying to get the system domain all users name. But I unable to get the all user name except domain login user name. I used the below code. What I want to do to get the all user name from system domain. Kindly any one help me.
Properties envVars = new Properties();
Runtime r = Runtime.getRuntime();
String OS = System.getProperty("os.name").toLowerCase();
     if ((OS.indexOf("nt") > -1) || (OS.indexOf("windows 2000") > -1 ) || (OS.indexOf("windows xp") > -1) )
          p = r.exec( "cmd.exe /c set" );
     BufferedReader br = new BufferedReader ( new InputStreamReader( p.getInputStream() ) );
     String line;
     while( (line = br.readLine()) != null )
          int idx = line.indexOf( '=' );
          String key = line.substring( 0, idx );
          String value = line.substring( idx+1 );
          envVars.setProperty( key, value );
     String domainDNSName = envVars.getProperty("USERDNSDOMAIN");
     String userName = envVars.getProperty("USERNAME");
     System.out.println("\n\n\n DOMAIN NAME == "+domainDNSName +" USERNAME == "+userName);
Thanks & Regards
Palani

Thanks kajbj,
I don't know, How many users in domain. I neet to get all the user names from my domain. User like A, B,C,D, E,F. I need to get this users name.
public class Env {
     public static void main(String[] args) {
          System.out.println("USERDOMAIN: " + System.getenv("USERDOMAIN"));
          System.out.println("USERNAME: " + System.getenv("USERNAME"));
Here , I am getting the login user name only. So i needs all user name. How to retrive or get this.
Regards
Palani

How to get Driver and url names from a connection pool

Hi,
How to get the DriverName and URL from an existing pool, If I know the name of
connection pool ? Is it possible to know the name of related pool , if I know
the name of datasource?
Thx
Manish

hi
there are 2 ways:
url must be: jdbc:weblogic:pool[:connectionPoolID]
or
jdbc:weblogic:jts[:connectionPoolID] (if you want to use jts with your JDBC connection.)
see http://e-docs.bea.com/wls/docs60//javadocs/weblogic/jdbc/pool/Driver.html
However, I think it is safer to configure and use DataSource to get connection.
Nicolas
"kumar" <[email protected]> wrote:
>
Hi,
How to get the DriverName and URL from an existing pool, If I know the name
of
connection pool ? Is it possible to know the name of related pool , if I
know
the name of datasource?
Thx
Manish

How to get the store procedure name inside this store procedure?

how to get the store procedure name inside this store procedure?

Why cant you get the procedure name as hard code as the proc name is going to change.
Are you looking for getting the parent proc name from child proc name which is getting executed within parent proc?
Try the below:
--Parent Proc
Alter Proc sp_test
as
Begin
Declare @s varbinary(MAX) = Cast('sp_test' as Varbinary(MAX));
SET CONTEXT_INFO @s;
exec sp_test2
End
--Child proc
Alter proc sp_test2
as
SELECT Cast(CONTEXT_INFO() as varchar(100));
--Test execution
Exec sp_test
Please mark this reply as answer if it solved your issue or vote as helpful if it helped.
[Blog]

How to get the current function name in java

How to get the current function name in java.
In c it is done as
printf("%s",__func__);
Thanx in advance.

j0o wrote:
System.out.println("Class Name: " + new Exception().getStackTrace()[0].getClassName() +
"/n Method Name : " + new Exception().getStackTrace()[0].getMethodName() +
"/n Line number : " + new Exception().getStackTrace()[0].getLineNumber());
I pointed the OP at this approach yesterday in one of his multi-posts. I still have not been given my Dukes!

How to get the backup of photos from i cloud id ?

plz provide me the answers as soon as possible.

BALAJI_PRASANNA wrote:
Hello,
I am very new to Labview. Í have an image of an LED and wanted to find the luminance value. I got the luminance image from the IMAQ ExtractSingleColorPlane but the value is not displaying. I just wanted to know how to get the value of luminance from the IMAQ ExtractSingleColorPlane. I have attached what i have done below.
Thanks in advance.
Before learning about LabVIEW, learn about images. An Image (in LabVIEW) is a "representation of an image", that is, the wire itself doesn't really have a "value", but "points to" a collection of data that can be "imaged" (i.e. looked at as through it were a picture), "manipulated" (for example, extracting a color plane, basically getting the "red channel", an image looking as through it were viewed through a red filter), and possibly returning arrays of numbers representing the intensity of the light at a certain position in the picture.
BS

How to get the failover partner name from C++ client

Similar Messages

Maybe you are looking for