How to get the last transaction in a row in SQL Developer?

Question

What syntax would I use to get the last transaction of a row in SQL developer?
The way I have my query set-up currently it is not returning the correct data, here is my current syntax:
select ssn, max(tran_id), chng_type,tran_id
from pda_tran
where ssn = 'xxx-xxx-0011'
and chng_type = 'C'
group by ssn, chng_type,tran_id;
It returns a 'C' chng_type but it is not the last one. when I query on this ssn this is what I get:
ssn tran_id chng_type
xxx-xxx-0011 001 A
xxx-xxx-0011 002 E
xxx-xxx-0011 003 C
xxx-xxx-0011 004 S
xxx-xxx-0011 005 C
xxx-xxx-0011 006 T
I only want to return the ssn's with a last transaction chng_type of 'C'. How can I get the correct information returned. Please advise.

Answer 1

From what I see and read... there is one to many group by
You wrote
select ssn, max(tran_id), chng_type,tran_id
from pda_tran
where ssn = 'xxx-xxx-0011'
and chng_type = 'C'
group by ssn, chng_type,tran_id;
If you want the max(tran_id), remove it from the "group by"
select ssn, chng_type, max(tran_id)
FROM
(SELECT 'xxx-xxx-0011' ssn, '001' tran_id, 'A' chng_type FROM DUAL UNION
SELECT 'xxx-xxx-0011' ssn, '002' tran_id, 'E' chng_type FROM DUAL UNION
SELECT 'xxx-xxx-0011' ssn, '003' tran_id, 'C' chng_type FROM DUAL UNION
SELECT 'xxx-xxx-0011' ssn, '004' tran_id, 'S' chng_type FROM DUAL UNION
SELECT 'xxx-xxx-0011' ssn, '005' tran_id, 'C' chng_type FROM DUAL UNION
SELECT 'xxx-xxx-0011' ssn, '006'tran_id, 'T' chng_type FROM DUAL )
where ssn = 'xxx-xxx-0011'
and chng_type = 'C'
group by ssn, chng_type;