How to get the Portal Page name from PLSQL?
Can anyone tell me how to get the portal page name from my dynamic page using plsql?
Apparently you can get the page id and work it out from there, but my calls to get the page id are not returning any values anyway.
My code for attempting to get the page id is below.
<oracle>
declare
v_pageid varchar2(30);
begin
v_pageid := wwpro_api_parameters.get_value('_pageid', '/pls/portal30');
htp.print('Page is '|| v_pageid);
end;
</oracle>
Ideally I'd actually just like to get the page name. Is there a straightforward way to do this?
Thanks in advance!
Sarah
Few clarifications -
1. wwpro_api_parameters cannot be used to get default portal
page parameters such as '_pageid', '_dad', '_schema' etc.,
2. Page information can be obtained through any components which
are available in that particular page. For example, in case of
dynamic page, we need to publish it as a portlet and add it to the
page. This process creates necessary packages in the DB, but we
will not have access to the portlet methods.
So, I would prefer creating a simple DB provider & portlet and access
page title from its show method as follows -
//Declare local variable l_page_id, l_page_title as varchar2
select page_id into l_page_id from wwpob_portlet_instance$ where
portlet_id = p_portlet_record.portlet_id and
provider_id = p_portlet_record.provider_id;
select name into l_page_title from wwpob_page$ where id=l_page_id;
More information on DB provider can be found at
http://portalstudio.oracle.com/pls/ops/docs/FOLDER/COMMUNITY/PDK/articles/understanding.database.providers.html
Secondly, usage of wwpro_api_parameters.get_value method is
incorrect. This method expects two arguments -
<ul>
<li><b>p_name : </b> The name of the parameter to be returned.</li>
<li><b>p_reference_path : </b> An unique identifier for a portlet instance on the current page.</li>
</ul>
p_reference_path would be something like 99_SNOOP_PORTLET_76535103 and not some type of path as its name suggests.
The following code fragment fetches all parameters available
for a portlet.
Note : Copy this code into 'show' method of your portlet.
//Declare l_names, l_values as owa.vc_arr
* Retreive all of the names of parameters for this portlet
l_names := wwpro_api_parameters.get_names(
p_reference_path=>p_portlet_record.reference_path);
* Retreive all of the values of parameters for this portlet
l_values := wwpro_api_parameters.get_values(p_names=>l_names,
p_reference_path=>p_portlet_record.reference_path);
//Loop through these arrays to get parameter information
htp.p('<center><table BORDER COLS=2 WIDTH="90%" >');
htp.p('<tr ALIGN=LEFT VALIGN=TOP>');
htp.tableData(wwui_api_portlet.portlet_heading('Name',1));
htp.tableData(wwui_api_portlet.portlet_heading('Value',1));
htp.tableRowClose;
if l_names.count = 0 then
htp.p('<tr ALIGN=LEFT VALIGN=TOP>');
htp.p('<td COLSPAN="2">'
||wwui_api_portlet.portlet_text(
'No portlet parameters were passed on the URL.',1)
||'</td>');
htp.tableRowClose;
else
for i in 1..l_names.count loop
htp.p('<tr ALIGN=LEFT VALIGN=TOP>');
htp.tableData(l_names(i));
htp.tableData(l_values(i));
htp.tableRowClose;
end loop;
end if;
htp.p('</table></center>');
Hope it helps...
-aMJAD.
Similar Messages
-
How to get the jsp page name in jsp?
how to get the jsp page name in jsp? how the jsp get the jsp page name dynamic.
thanks in advance.Try request.getServletPath()
-
How to get the actual font name from a font file?
Hi
I have only the font Path I have to get the font name from that path. Any idea how to get the actual font name?
Thanks,I would ask you these questions:
Why do you need to do this? What are you ultimately trying to accomplish?
Are you really asking about the InDesign SDK?
Do you really need to get the "name" of a font from an arbitrary file? Or do you want information about a font installed on the system? If so, what OS?
Do you need to be able to handle any font format?
Which font "name" do you mean?
What language do you want the name in?
(1) It's not clear what you're trying to accomplish. A bit more information about your ultimate goal would be helpful.
(2) This question is not at all specific to the InDesign SDK. Are you really trying to do something in the context of an InDesign plug-in? If so, you probably want to look at IID_IFONTFAMILY and the IFontFamily::GetFamilyName function.
(3) If you are asking more generally, Windows and Mac both have system API calls to get this information, although those tend to deal with installed system fonts, not with arbitrary font files per se.
Also, you can parse the name table from a True Type or Open Type font without using any system APIs; as True Type and Open Type are well-documented standards. I would start by reading these:
The Naming Table
Font Names Table
(4) Although there are other standards, such as Type 1 (PostScript) fonts, and True Type Collection files and other formats, especially on Mac.
(5) Also, when you start down this road, you will quickly realize that your seemingly simple question is actually ambiguous, and that the answer is kind of complicated, because a font can have many names (a family name, a full font name, a style name, a PostScript name, etc.).
(6) And not only does a font have multiple names, it can have each of those names in multiple languages and encodings.
Any clarification would make this a better question. -
How to get the failover partner name from C++ client
Hi All,
I have configured the mirroring session for my application.
I want to modify the connection string with failover partner name.
Could any one please let me to know how to get the failover partner instance from C++ client dynamically.
Thanks,
Prasad.Are you looking for this?
http://www.connectionstrings.com/sql-server-2012/
http://stackoverflow.com/questions/25534972/auto-failover-multiple-connections-to-mirror-database-when-principal-goes-down -
How to get the pull path name from a file upload window
Hello everyone!
I have encountered the following problem with the following JSP code:
<form method="post" action="filename.jsp">
Upload JAVA program:
<input type=file size=20 name="fname" accept="java">
<input type=submit value="go">
</form>
<%
String s = "";
if (request.getParameter("fname") != null)
s = request.getParameter("fname")
%>
The value of s is alway the filename. However I want to get the full path in addition to the filename, so that I can read the file. Does anyone know how to get the pull name of the file?
thanks a lot in advance,Dear Sir,
thanks a lot for your reply. Please let me explain what I intended to do: I want to upload a file from the local machine and then read the content of the file. Therefore I need to the fullpath of the filename like /var/local/file.java instead of file.java. The latter is what I got.
The problem I have with your code is that the function like "request.getServerScheme()" is not recognized. Maybe is it because I didn't install servelet package? I only installed javax package btw. Also my application runns on Tomcat server if this could give you some information. The error message I had is as follows:
org.apache.jasper.JasperException: Unable to compile class for JSP
An error occurred at line: 36 in the jsp file: /addExercise.jsp
Generated servlet error:
[javac] Compiling 1 source file
/usr/local/jakarta-tomcat-5.0.12/work/Catalina/localhost/tutor/org/apache/jsp/addExercise_jsp.java:133: cannot resolve symbol
symbol : method getServerScheme ()
location: interface javax.servlet.http.HttpServletRequest
url = request.getServerScheme()
^
An error occurred at line: 36 in the jsp file: /addExercise.jsp
Generated servlet error:
/usr/local/jakarta-tomcat-5.0.12/work/Catalina/localhost/tutor/org/apache/jsp/addExercise_jsp.java:136: cannot resolve symbol
symbol : method getServerScheme ()
location: interface javax.servlet.http.HttpServletRequest
+ ((("http".equals(request.getServerScheme()) && request.getServerPort() != 80)
^
An error occurred at line: 36 in the jsp file: /addExercise.jsp
Generated servlet error:
/usr/local/jakarta-tomcat-5.0.12/work/Catalina/localhost/tutor/org/apache/jsp/addExercise_jsp.java:137: cannot resolve symbol
symbol : method getServerScheme ()
location: interface javax.servlet.http.HttpServletRequest
||("https".equals(request.getServerScheme()) && request.getServerPort() != 443))
^
An error occurred at line: 36 in the jsp file: /addExercise.jsp
Generated servlet error:
/usr/local/jakarta-tomcat-5.0.12/work/Catalina/localhost/tutor/org/apache/jsp/addExercise_jsp.java:139: cannot resolve symbol
symbol : method getServletConfig ()
location: interface javax.servlet.http.HttpServletRequest
+ "/" + request.getServletConfig().getServletName()
^
An error occurred at line: 36 in the jsp file: /addExercise.jsp
Generated servlet error:
/usr/local/jakarta-tomcat-5.0.12/work/Catalina/localhost/tutor/org/apache/jsp/addExercise_jsp.java:140: cannot resolve symbol
symbol : variable path
location: class org.apache.jsp.addExercise_jsp
+ "/" + path
^
5 errors
org.apache.jasper.compiler.DefaultErrorHandler.javacError(DefaultErrorHandler.java:128)
org.apache.jasper.compiler.ErrorDispatcher.javacError(ErrorDispatcher.java:351)
org.apache.jasper.compiler.Compiler.generateClass(Compiler.java:413)
org.apache.jasper.compiler.Compiler.compile(Compiler.java:453)
org.apache.jasper.compiler.Compiler.compile(Compiler.java:437)
org.apache.jasper.JspCompilationContext.compile(JspCompilationContext.java:555)
org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:291)
org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:301)
org.apache.jasper.servlet.JspServlet.service(JspServlet.java:248)
javax.servlet.http.HttpServlet.service(HttpServlet.java:856) -
How to get the long file name from an 8.3 name in Windows.
Because of a legacy string limitation, I have a list of files in 8.3 format. The actual files are saved with long names. How can I get the long name from the short name?
In JavaScript, I would get a file system object and get the file object from there with the short name. Then it's no problem to get the full name. But I don't see anything in Java that matches that. ???
Ideas?
Frank Perry, MSEEHere is what I did.
String displayName = "somefi~1.txt";
File fO = new File("c:\\"); // I have a more involved path but that's not important here.
String stPath = fO.getPath() + displayName;
File fD = new File(stPath); // get the file using the short name.
File fDc = new File(fD.getCanonicalPath()); // get another file using the cononical name
String FulldisplayName = fDc.getName(); // get the long name from there.
It's roundabout but it works. Since getName() on the file read with the short name only returns the name used to get the file, I open it twice. The alternative is to parse the cononical name for the file name but that's clumbsy too.
Frank -
How to get the target file name from an URL?
Hi there,
I am trying to download data from an URL and save the content in a file that have the same name as the file on the server. In some way, what I want to do is pretty similar to what you can do when you do a right click on a link in Internet Explorer (or any other web browser) and choose "save target as".
If the URL is a direct link to the file (for example: http://java.sun.com/images/e8_java_logo_red.jpg ), I do not have any problem:
URL url = new URL("http://java.sun.com/images/e8_java_logo_red.jpg");
System.out.println("Opening connection to " + url + "...");
// Copy resource to local file
InputStream is = url.openStream();
FileOutputStream fos=null;
String fileName = null;
StringTokenizer st=new StringTokenizer(url.getFile(), "/");
while (st.hasMoreTokens())
fileName=st.nextToken();
System.out.println("The file name will be: " + fileName);
File localFile= new File(System.getProperty("user.dir"), fileName);
fos = new FileOutputStream(localFile);
try {
byte[] buf = new byte[1024];
int i = 0;
while ((i = is.read(buf)) != -1) {
fos.write(buf, 0, i);
} catch (Throwable e) {
e.printStackTrace();
} finally {
if (is != null)
is.close();
if (fos != null)
fos.close();
}Everything is fine, the file name I get is "e8_java_logo_red.jpg", which is what I expect to get.
However, if the URL is an indirect link to the file (for example: http://javadl.sun.com/webapps/download/AutoDL?BundleId=37719 , which link to a file named JavaSetup6u18-rv.exe ), the similar code return AutoDL?BundleId=37719 as file name, when I would like to have JavaSetup6u18-rv.exe .
URL url = new URL("http://javadl.sun.com/webapps/download/AutoDL?BundleId=37719");
System.out.println("Opening connection to " + url + "...");
// Copy resource to local file
InputStream is = url.openStream();
FileOutputStream fos=null;
String fileName = null;
StringTokenizer st=new StringTokenizer(url.getFile(), "/");
while (st.hasMoreTokens())
fileName=st.nextToken();
System.out.println("The file name will be: " + fileName);
File localFile= new File(System.getProperty("user.dir"), fileName);
fos = new FileOutputStream(localFile);
try {
byte[] buf = new byte[1024];
int i = 0;
while ((i = is.read(buf)) != -1) {
fos.write(buf, 0, i);
} catch (Throwable e) {
e.printStackTrace();
} finally {
if (is != null)
is.close();
if (fos != null)
fos.close();
}Do you know how I can do that.
Thanks for your help
// JB
Edited by: jb-from-sydney on Feb 9, 2010 10:37 PMThanks for your answer.
By following your idea, I found out that one of the header ( content-disposition ) can contain the name to be used if the file is downloaded. Here is the full code that allow you to download locally a file on the Internet:
* Download locally a file from a given URL.
* @param url - the url.
* @param destinationFolder - The destination folder.
* @return the file
* @throws IOException Signals that an I/O exception has occurred.
public static final File downloadFile(URL url, File destinationFolder) throws IOException {
URLConnection urlC = url.openConnection();
InputStream is = urlC.getInputStream();
FileOutputStream fos = null;
String fileName = getFileName(urlC);
destinationFolder.mkdirs();
File localFile = new File(destinationFolder, fileName);
fos = new FileOutputStream(localFile);
try {
byte[] buf = new byte[1024];
int i = 0;
while ((i = is.read(buf)) != -1) {
fos.write(buf, 0, i);
} finally {
if (is != null)
is.close();
if (fos != null)
fos.close();
return localFile;
* Returns the file name associated to an url connection.<br />
* The result is not a path but just a file name.
* @param urlC - the url connection
* @return the file name
* @throws IOException Signals that an I/O exception has occurred.
private static final String getFileName(URLConnection urlC) throws IOException {
String fileName = null;
String contentDisposition = urlC.getHeaderField("content-disposition");
if (contentDisposition != null) {
fileName = extractFileNameFromContentDisposition(contentDisposition);
// if the file name cannot be extracted from the content-disposition
// header, using the url.getFilename() method
if (fileName == null) {
StringTokenizer st = new StringTokenizer(urlC.getURL().getFile(), "/");
while (st.hasMoreTokens())
fileName = st.nextToken();
return fileName;
* Extract the file name from the content disposition header.
* <p>
* See <a
* href="http://www.w3.org/Protocols/rfc2616/rfc2616-sec19.html">http:
* //www.w3.org/Protocols/rfc2616/rfc2616-sec19.html</a> for detailled
* information regarding the headers in HTML.
* @param contentDisposition - the content-disposition header. Cannot be
* <code>null>/code>.
* @return the file name, or <code>null</code> if the content-disposition
* header does not contain the filename attribute.
private static final String extractFileNameFromContentDisposition(
String contentDisposition) {
String[] attributes = contentDisposition.split(";");
for (String a : attributes) {
if (a.toLowerCase().contains("filename")) {
// The attribute is the file name. The filename is between
// quotes.
return a.substring(a.indexOf('\"') + 1, a.lastIndexOf('\"'));
// not found
return null;
} -
How to get customer number and name from the SD document
Hi All,
Can you please let me know how to get Customer Number and Name from the SD Document?
Thanks a lot....
AnilHi,
It will be displayed in the SD (BIlling document) itself, you clikc on the VF03. The customer name and number will also appear in the SO document also Tcode VA03
regards,
radhika
Edited by: kolipara radhika on Jul 10, 2009 5:32 AM -
How to get the last page SAP Script form
How to get the last page SAP Script form.
I want to print a specific information in the last page of SAP form (Script). Please tell me how to get the last page number.
RegardsHi
You have to check the system variable &NEXTPAGE&, if it's 0 it means you're in the last page.
From SAP Help:
This symbol is used to print the number of the following page. The output format is the same as with &PAGE& .
Note that on the last page of the output, in each window that is not of type MAIN, &NEXTPAGE& has the value 0.
/: IF &NEXTPAGE& = '0'
Last page
/: ENDIF
Max -
How to get the current page URL
HI All
I am working in oracle apps 4.0
I have one page called history in that i have one page item called Application url. My application id is 122 but its a copy of application 106
How to get the current page url for the page item.
Any steps should be help ful
Thanks & Regards
Srikkanth.MI'm not 100% clear on what the requirement is from the description, however it does sound like you are making things unnecessarily complicated.
If you want permanent/ID-independent links then use application and page aliases.
so here we used to display the url like this: <tt>{noformat}http://81.131.254.171:8080/apex/f?p=122{noformat}</tt>
Do you mean that the URL is displayed like that? If so that doesn't seem particularly helpful. How is anyone supposed to know what it is?
There are many ways to provide links in APEX—including lists and nav bars.
Where the link is to another resource located on the same server (such as another page in the same app, or a different app in the workspace), relative addressing can be used, making it unecessary to include scheme, domain and port information in the URL. For example, if the page to be linked to has a page alias <tt>ABOUT</tt> in an application with alias <tt>UNITY</tt>, and the apps share an authentication scheme/cookie to permit shared sessions, then the link URL is simply
f?p=UNITY:ABOUT:&APP_SESSION. -
How to get the current schema name
Hi,
Can anybody please tell me how to get the current schema name, there is some inbuilt function for this,but i am not getting that. Please help me.
Thanks
Jogeshok folks, I found the answer at Tom's as usual.
http://asktom.oracle.com/tkyte/who_called_me/index.html
I rewrote it into a function for kicks. just pass the results of DBMS_UTILITY.FORMAT_CALL_STACK to this function and you will get back the owner of the code making the call as well some extra goodies like the name of the code and the type of code depending on the parameter. This ignores the AUTHID CURRENT_USER issues which muddles the schemaid. Quick question, does the average user always have access to DBMS_UTILITY.FORMAT_CALL_STACK or does this get locked down on some systems?
cheers,
paul
create or replace
FUNCTION SELF_EXAM (
p_call_stack VARCHAR2,
p_type VARCHAR2 DEFAULT 'SCHEMA'
) RETURN VARCHAR2
AS
str_stack VARCHAR2(4000);
int_n PLS_INTEGER;
str_line VARCHAR2(255);
found_stack BOOLEAN DEFAULT FALSE;
int_cnt PLS_INTEGER := 0;
str_caller VARCHAR2(30);
str_name VARCHAR2(30);
str_owner VARCHAR2(30);
str_type VARCHAR2(30);
BEGIN
str_stack := p_call_stack;
-- Loop through each line of the call stack
LOOP
int_n := INSTR( str_stack, chr(10) );
EXIT WHEN int_cnt = 3 OR int_n IS NULL OR int_n = 0;
-- get the line
str_line := SUBSTR( str_stack, 1, int_n - 1 );
-- remove the line from the stack str
str_stack := substr( str_stack, int_n + 1 );
IF NOT found_stack
THEN
IF str_line like '%handle%number%name%'
THEN
found_stack := TRUE;
END IF;
ELSE
int_cnt := int_cnt + 1;
-- cnt = 1 is ME
-- cnt = 2 is MY Caller
-- cnt = 3 is Their Caller
IF int_cnt = 1
THEN
str_line := SUBSTR( str_line, 22 );
dbms_output.put_line('->' || str_line);
IF str_line LIKE 'pr%'
THEN
int_n := LENGTH('procedure ');
ELSIF str_line LIKE 'fun%'
THEN
int_n := LENGTH('function ');
ELSIF str_line LIKE 'package body%'
THEN
int_n := LENGTH('package body ');
ELSIF str_line LIKE 'pack%'
THEN
int_n := LENGTH('package ');
ELSIF str_line LIKE 'anonymous%'
THEN
int_n := LENGTH('anonymous block ');
ELSE
int_n := null;
END IF;
IF int_n IS NOT NULL
THEN
str_type := LTRIM(RTRIM(UPPER(SUBSTR( str_line, 1, int_n - 1 ))));
ELSE
str_type := 'TRIGGER';
END IF;
str_line := SUBSTR( str_line, NVL(int_n,1) );
int_n := INSTR( str_line, '.' );
str_owner := LTRIM(RTRIM(SUBSTR( str_line, 1, int_n - 1 )));
str_name := LTRIM(RTRIM(SUBSTR( str_line, int_n + 1 )));
END IF;
END IF;
END LOOP;
IF UPPER(p_type) = 'NAME'
THEN
RETURN str_name;
ELSIF UPPER(p_type) = 'SCHEMA.NAME'
OR UPPER(p_type) = 'OWNER.NAME'
THEN
RETURN str_owner || '.' || str_name;
ELSIF UPPER(p_type) = 'TYPE'
THEN
RETURN str_type;
ELSE
RETURN str_owner;
END IF;
END SELF_EXAM; -
How to get the total pages in ALV report?
Hi guys,
Since I used page breaks can somebody please help me on how to get the total pages in ALV report?sincerely please...thanks guys.automatic display total page.
https://www.sdn.sap.com/irj/servlet/prt/portal/prtroot/docs/library/uuid/e8a1d690-0201-0010-b7ad-d9719a415907
r -
How to get the Empty page in Webi report
Hi,
I have to insert the charts in the report but i don't have the space to insert the charts in same page so i need one more page how to get the blank page in report
thanks,turn your report from Page Layout to Draft Mode. Than you will be able to insert chart in it.
You can view Web Intelligence reports in different modes depending on how you want to work with data and how you want the data to appear.
1. In Web Intelligence Interactive, select the report tab of the report you want to view.
2. Click the arrow next to the View button on the main toolbar above the report.
3. Select the viewing mode.
4. In the Java Report Panel or Web Intelligence Rich Client, use Switch Page/Quick Display on the Reporting toolbar to alternate between Page mode and Quick Display mode.
Edited by: srrachna on Apr 22, 2011 2:25 PM -
How to get the default selection color from JTable
Hi, there,
I have a question for how to get the default selection color from JTable. I am currently implementing the customized table cell renderer, but I do want to set the selection color in the table exactly the same of default table cell renderer. The JTable.getSelectionBackgroup() did not works for me, it returned dark blue which made the text in the table unreadable. Anyone know how to get the window's default selection color?
Thanks,
-JennyThe windows default selection color is dark blue. Try selecting any text on this page. The difference is that the text gets changed to a white font so you can actually see the text.
If you don't like the default colors that Java uses then use the UIManager to change the defaults. The following program shows all the properties controlled by the UIManager:
http://www.discoverteenergy.com/files/ShowUIDefaults.java
Any of the properties can be changed for the entire application by using:
UIManager.put( "propertyName", value ); -
How to get list of file names from a directory?
How to get list of file names from a directory?
Please helpIn addition, this:
String filename = files;Should be this:
String filename = files;
That's just because he didn't use the "code" tags, so [ i ] made everything following it become italicized.
Maybe you are looking for
-
When I click on a link, whether e-mail, yahoo or other search engines, E-bay, Amazon, etc. I get sent to another site. If I click back and then re-click on the original site I get sent to where I wanted to be. While I am browsing on a web page of any
-
How do i allow youtube video to play in fullscreen in a blog on Server 10.6
Hi, After many tries with podcast composer; iI decided to switch to youtube as host for my videos. I still encounter a problem though, i cannot put the video in fullscreen mode even when i click on the button. Nothing happens. I modified the whitelis
-
My new I pad screen is yellow , what do I do now . Help
Please help what do I do when the new I pad screen turns yellow .
-
Hi all, I have recently installed Enterprise Portals. I am completely new to this Enterprise Portals.I am working on XI. Could anybody provide intoduction doc or tell me where to start or How to start EP? Thanks & Regards, Nandini
-
Future of o2 e-addresses and about o2 account login
Questions on my mind for quite a while.Would be grateful if someone could throw some light on these: Have Sky Broadband since o2 changed us over. But still use 2 of my old o2 email addresses.....QUESTION 1 - can I keep those forever? if not, will o2