How to get these substrings based on the string entered

Question

Hi friends
i want the substring entered in the string
the string is something like this: 1234,3653,7684,3254,8777,987,234
now i want
the substrings between commas
can some one help me with it pls
in the first substring i need 1234
in the second i need 3653...
so on till the end..
what ever the string be until the last one
pls help

Answer 1

Hi,
You can do something like this:
SELECT     txt
,     REGEXP_SUBSTR (txt, '[^,]+', 1, 1)     AS part_1
,     REGEXP_SUBSTR (txt, '[^,]+', 1, 2)     AS part_2
,     REGEXP_SUBSTR (txt, '[^,]+', 1, 3)     AS part_3
FROM     table_x
;If there are fewer than n parts, then the technique above will not raise an error; it will just return NULL for part_n.
I hope this answers your question.
If not, post a little sample data (CREATE TABLE and INSERT statements, relevant columns only), and the results you want from that data.
Explain how you get those results from that data.
What do you want if the input is like this"
{code}
'foo,,bar'
{code}
? Do you want to consider this as 2 parts ('bar' is the 2nd) or a s 3 (the 2nd is NULL, and 'bar' is the 3rd)? Include examples in your sample data and results.
Always say what version of Oracle you're using.