How to insert various number of values into a table

Hi
Im devoloping application using swing components..How can i insert values from JTextField to table if the form contains number of textfield(more than 30) and JRadioButtons(Radio Buttons are in button group).
thanks in advance.

Hi
i designed a form with 58 Textfields. i want to get data from those fields and i have to store those into a database table. how can i do that .is there any simple way to do that?. do you have any example code? pls give me...

Similar Messages

How to insert the image or logo into the table as a field in webdynpro abap

Hi Friends,
Please tell me how to insert the image or logo into the table as a field in webdynpro abap.........

Hi Alagappan ,
In your view layout you take table UI element and then you bind it with some context nodes.
The attributes of your nodes comes as a field.
Now in these fields you can set various properties and image is one of them.
Go to ->
1. View Layout -> Right Click on ROOTUIELEMENTCONTAINER -> INSERT ELEMENT -> TABLE
2. Right click on table -> Create Binding.
Here you have to bind it with the appropriate context node.
You will get two properties here
a- Standard Cell Editor :- ( make it image )
b- Standard properties :- ( If required set image properties ).
3. If you want put image from out side then import it as a mime object and set the source of your table field ( used as a image )
also have a look :-
[Image Properties|http://help.sap.com/saphelp_nw04/helpdata/en/f3/1a61a9dc7f2e4199458e964e76b4ba/content.htm]
Hope this will solve your problem.
Reply if any case of any issue.
Thanks & Regards,
Monishankar C

To insert N number of values in a table for backup

Hello experts,
I need to insert N number of values in a table using
SQL or PL/SQL. Please help me to do this.
i have tried this. but not working
CREATE PROCEDURE P1
AS
-- start loop & repeat N times
INSERT INTO [T1]
    ([Value])
VALES
    (:value)
INSERT INTO [T2]
    ([valueID])
VALUES
    (:IDENTITY)
-- END LOOP
END;

>almost i got the answer.
Then is it not time to close the thread as mark it Answered ?
Or, your "almost" requires more ...!
Regards
Girish Sharma

How to insert or update multiple values into a records of diff fields

Hai All
I have to insert or update or multiple values into a single records of diff fields from one to another table.
Table1 has 3 fields
Barcode bardate bartime
0011 01-02-10 0815
0022 01-02-10 0820
0011 01-02-10 1130
0022 01-02-10 1145
0011 01-02-10 1230
0022 01-02-10 1235
0011 01-02-10 1645
0022 01-02-10 1650
these are the times that comes in at 0815 and goes break at 1130 and comes in at 1230 and goes home at 1645
from these table i have to insert into another table called table2
and the fields are barcode, date,timein intrin,introut,tiomout
And the output want to like this
barcode timein intrin introut timeout date
0011 0815 1130 1230 1645 01-02-10
0022 0820 1145 1235 1650 01-02-10
If any give some good answer it will be help full..
Thanks & Regards
Srikkanth.M

SQL> with table1 as (
2 select '0011' Barcode,'01-02-10' bardate,'0815' bartime from dual union
3 select '0022','01-02-10','0820' from dual union
4 select '0011','01-02-10','1130' from dual union
5 select '0022','01-02-10','1145' from dual union
6 select '0011','01-02-10','1230' from dual union
7 select '0022','01-02-10','1235' from dual union
8 select '0011','01-02-10','1645' from dual union
9 select '0022','01-02-10','1650' from dual
10 )
11 select barcode, bardate,
12         max(decode(rn,1,bartime,null)) timein,
13         max(decode(rn,2,bartime,null)) intrin,
14         max(decode(rn,3,bartime,null)) introut,
15         max(decode(rn,4,bartime,null)) timeout from (
16                          select barcode, bardate, bartime,
17                                 row_number() over (partition by barcode, bardate
18                                                    order by bartime) rn
19                            from table1)
20 group by barcode, bardate;
BARC BARDATE TIME INTR INTR TIME
0011 01-02-10 0815 1130 1230 1645
0022 01-02-10 0820 1145 1235 1650Max
http://oracleitalia.wordpress.com

How to insert data from APEX form into two tables

Hi,
I'm running APEX 4.1 with Oracle XE 11g, having two tables CERTIFICATES and USER_FILES. Some of the (useless) fields are cut to reduce information:
CREATE TABLE CERTIFICATES
CERT_ID NUMBER NOT NULL ,
CERT_OWNER NUMBER NOT NULL ,
CERT_VENDOR NUMBER NOT NULL ,
CERT_NAME VARCHAR2 (128) ,
CERT_FILE NUMBER NOT NULL ,
) TABLESPACE CP_DATA
LOGGING;
ALTER TABLE CERTIFICATES
ADD CONSTRAINT CERTIFICATES_PK PRIMARY KEY ( CERT_ID ) ;
CREATE TABLE USER_FILES
FILE_ID NUMBER NOT NULL ,
FILENAME VARCHAR2 (128) ,
BLOB_CONTENT BLOB ,
MIMETYPE VARCHAR2 (32) ,
LAST_UPDATE_DATE DATE
) TABLESPACE CP_FILES
LOGGING
LOB ( BLOB_CONTENT ) STORE AS SECUREFILE
TABLESPACE CP_FILES
STORAGE (
PCTINCREASE 0
MINEXTENTS 1
MAXEXTENTS UNLIMITED
FREELISTS 1
BUFFER_POOL DEFAULT
RETENTION
ENABLE STORAGE IN ROW
NOCACHE
ALTER TABLE USER_FILES
ADD CONSTRAINT CERT_FILES_PK PRIMARY KEY ( FILE_ID ) ;
ALTER TABLE CERTIFICATES
ADD CONSTRAINT CERTIFICATES_USER_FILES_FK FOREIGN KEY
CERT_FILE
REFERENCES USER_FILES
FILE_ID
NOT DEFERRABLE
What I'm trying to do is to allow users to fill out all the certificate data and upload a file in an APEX form. Once submitted the file should be uploaded in the USER_FILES table and all the fields along with CERT_ID, which is the foreign key pointing to the file in the USER_FILES table to be populated to the CERTIFICATES table. APEX wizard forms are based on one table and I'm unable to build form on both tables.
That's why I've created a view (V_CERT_FILES) on both tables and using INSTEAD OF trigger to insert/update both tables. I've done this before and updating this kind of views works perfect. Here is where the problem comes, if I'm updating the view all the data is updated correctly, but if I'm inserting into the view all the fields are populated at CERTIFICATES table, but for USER_FILES only the fields FILE_ID and LAST_UPDATE_DATE are populated. The rest three regarding the LOB are missing: BLOB_CONTENT, FILENAME, MIMETYPE. There are no errors when running this from APEX, but If I try to insert into the view from SQLDeveloper, I got this error:
ORA-22816: unsupported feature with RETURNING clause
ORA-06512: at line 1
As far as I know RETURNING clause in not supported in INSTEAD of triggers, although I didn't have any RETURNING clauses in my trigger (body is below).
Now the interesting stuff, after long tracing I found why this is happening:
First, insert is executed and the BLOB along with all its properties are uploaded to wwv_flow_file_objects$.
Then the following insert is executed to populate all the fields except the BLOB and it's properties, rowid is RETURNED, but as we know RETURNING clause is not supported in INSTEAD OF triggers, that's why I got error:
PARSE ERROR #1918608720:len=266 dep=3 uid=48 oct=2 lid=48 tim=1324569863593494 err=22816
INSERT INTO "SVE". "V_CERT_FILES" ( "CERT_ID", "CERT_OWNER", "CERT_VENDOR", "CERT_NAME", "BLOB_CONTENT") VALUES (:B1 ,:B2 ,:B3 ,:B4, ,EMPTY_BLOB()) RETURNING ROWID INTO :O0
CLOSE #1918608720:c=0,e=11,dep=3,type=0,tim=1324569863593909
EXEC #1820672032:c=3000,e=3168,p=0,cr=2,cu=4,mis=0,r=0,dep=2,og=1,plh=0,tim=1324569863593969
ERROR #43:err=22816 tim=1324569863593993
CLOSE #1820672032:c=0,e=43,dep=2,type=1,tim=1324569863594167
Next my trigger gets in action, sequences are generated, CERTIFICATES table is populated and then USER_FILES, but only the FILE_ID and LAST_UPDATE_DATE.
Finally update is fired against my view (V_CERT_FILES), reading data from wwv_flow_files it populates BLOB_CONTENT, MIMETYPE and FILENAME fields at the specific rowid in V_CERT_FILES, the one returned from the insert at the beginning. Last, file is deleted from wwv_flow_files.
I'm using sequences for the primary keys, this is only the body of the INSTEAD OF trigger:
select user_files_seq.nextval into l_file_id from dual;
select certificates_seq.nextval into l_cert_id from dual;
insert into user_files (file_id, filename, blob_content, mimetype, last_update_date) values (l_file_id, :n.filename, :n.blob_content, :n.mimetype, sysdate);
insert into certificates (cert_id, cert_owner, cert_vendor, cert_name, cert_file) values (l_cert_id, :n.cert_owner, :n.cert_vendor, :n.cert_name, l_file_id);
I'm surprised that I wasn't able to find a valuable source of information regarding this problem, only MOS note about running SQLoader against view with CLOB column and INSTEAD OF trigger. The solution would be to ran it against base table, MOS ID 795956.1.
Maybe I'm missing something and that's why I decided to share my problem here. So my question is how do you create this kind of architecture, insert into two tables with a relation between them in APEX ? I read a lot in the Internet, some advices were for creating custom form with APEX API, create a custom ARP, create two ARP or create a PL/SQL procedure for handing the DML?
Thanks in advance.
Regards,
Sve

Thank you however I was wondering if there was an example available which uses EJB and persistence.

How to restrict the number of Records into the Table?

Is there any way that I can restrict the number of records can be entered into the table?
For example I have created a table TAB1 with size category 0( zero).
User dont want to enter more than 100 values, How to restrict the number entries? Whether Basis can do it?
Regards,
Prathap

Hi Prathap,
You can write a code in table maintenance events to restrict the number of Records added into the Table to constant.
Solution:
Se11 -> enter table name (TAB1) -> F6 -> Utlities -> Table maint. generator -> Envirnment -> modification -> events -> write here the form routine name.
Double click on routine name. You will get into include section of the code. Write here code like:
IF current_rec_num > 100.
messgae error 'Entry restriceted to 100'
ENDIF.
Somewhat this way you can achieve your target.
Regards,
Sachin

Insert/Update multiple checkbox values into a table

Hi all,
I created an interactive report with checkboxes in it.
My application is like,
step 1: user will give his ID in a text box and click on 'submit' which redirects to IR page which has got checkboxes
step 2: IR report displays all the environments and access levels as two of its columns
step 3: if user checks on some box in IR, those particular environments and access levels (may be multiple environments and access levels) for that particular ID should get inserted into a table.
I have created a model application at http://apex.oracle.com/pls/apex/f?p=71510:20 (wokspace:test_me, username=test, paswrd: apex14gm)
I found this forum too, https://forums.oracle.com/thread/2387391?start=0&tstart=0. But I am confused of how to implement it!
How to achieve this??
Pls help me out....
Thanks in advance

Hi Kanishkaa,
I've taken a look at your application.
So the things that I noticed that are wrong:
1)Your report: You created 2 items but you gave the 2 items the same idx. This is really weird I'm not sure if APEX knows how to handle this. Don't give 2 items the same idx. Furthermore you need to create 2 additional hidden items since you also want to store the access level and the environment.
2)The PL/SQL Process: Your PL/SQL Process: your making a type t_checkboxes, but your not actually doing anything with this type. Your not giving this any value. So obviously you get an error.
You really should rewrite this process based on the process in my blog. Please read it again carefully, if you just use the one insert statement you are using then even if you write a correct process that doesn't give any errors, the wrong data will be inserted.
Regards,
Joni

How to insert Serialised Object(XML DOM) into Oracle Table(as BLOB or CLOB)

we need a urgent help. How can we insert and retrieve the XML Document DOM Object into Oracle Table.Actually we used BLOB for insert the DOM Object,its inserted finely but we have a problem in retrieving that object, we got error when v're retrieving. so could you anyone tell us what's this exact problem and how can we reslove this problem If anyone knows or used this kind operation, pls let us know immediately.
Thanks in advance.

Please repost your question in the appropriate XML forum, http://forums.oracle.com/forums/index.jsp?cat=51

How to insert an in-line image into a table cell using Pages on OS X?

How can I insert an image into a table cell using Pages (OS X) without it becoming the cell background? I want it to be a regular in-line image, but can't figure out how to do this for the life of me. Thanks!

Welcome to Discussions.
To insert an image into a cell, select the cell, then go to the Graphics Inspector and from the Fill drop down choose Image Fill and then select then image you want. You can now select from a new drop down how you want the image to fit.
Walt

How to insert a value into a table

I have an ordering system. It displays all the orders by
customer ID. If an order is complete, a check number is entered for
the corresponding line item, otherwise it is left blank.
My code uses the following code to display the form. All are
display fields only, except for the last one, where the check
number can be entered.
<cfoutput query="qryDetail" group="partNumber">
<tr>
<td valign="top" class="TitleText"
align="center">#lineItem#</td>
<td valign="top" class="TitleText"
align="center">#OrderNumber#</td>
<td valign="top" class="TitleText"
align="center">#partNumber#</td>
<td valign="top" class="TitleText"
align="center">#dollarformat(qryDetail.unitValue)#</td>
<td valign="top" class="TitleText" align="center">
<cfinput type="text" name="checkNumber#keyID#">
<input type="hidden" name="keyID"
value="#qryDetail.keyID#">
</td>
I use something like the following to update the table with
the check numbers entered.
<cfloop index="KeyID" list="#form.KeyID#"
delimiters=",">
<cfquery name="qryUpdate" datasource="dbName">
update tblChecks
set checkNumber = '#Evaluate("form.checkNumber#KeyID#")#'
where custID = '#form.custID#'
and KeyID = '#KeyID#'
</cfquery>
</cfloop>
Now we have another table that will contain the customer
order history. If the check number was entered for a particular
line item, I need to insert that line item nubmer into this table,
along with some other columns. I tried to use the same loop, then
other loops, but cannot seem to get this to work. Seems simple
enough, but I obvisouly am missing something.
How would I insert the line item number (only if a check
number was entered for that line item) into the table ?

Here is the code with the queries commented out :
<cfloop list="#form.fieldnames#" index="field">
<cfif left(field, 11) is "checkNumber" AND
len(trim(form[field]))>
<cfset keyID = listlast(field, '_')>
<cfset lineItem = listgetat(field, 2, '_')>
<cfset checknum = form[field]>

<cfoutput> loop is
field: <b>#field#</b><br>
checknum: #checknum#<br>
lineitem: #lineitem#<br>
keyID: #keyID#<br>
</cfoutput>
<cfelse>
<cfoutput>Else is
field: <b>#field#</b><br>
form[field]: #form[field]#<br>
len: #len(trim(form[field]))#<br>
</cfoutput><cfabort>
</cfif>
</cfloop>
This is the output. If I do not put in cfabort, the code just
drops thru and I never see any output display, so I use cfabort to
stop so I can see the output.
loop is field: CHECKNUMBER_11_218
CHECKNum: xxxxxxxxxxxxxxxxxxxx
lineitem: 11
keyID: 218
Else is field: CHECKNUMBER_1_24
form[field]:
I entered the x's into checknum for line item 11, so that is
correct.
I then took out the comments from the update query and tried
it again and it updated for line item 11 (you were right, I had to
take out the single quotes in the query). I then removed the
commets for the insert query and it did not insert. I tried the
whole thing again and tried to add to line item 10 and it dropped
straight to the else part, displaying :
Else is field: CHECKNUMBER_1_24
form[field]:
len: 0
So it seems the if statement if failing the second time thru
the loop :
<cfif left(field, 11) is "checkNumber" AND
len(trim(form[field]))>
This is my input statement :
<cfinput type="text"
name="checkNumber_#lineItem#_#keyID#">
I am really confused now. It seems to work the first time
thru the loop, then the second time it fails.

SQL Server 2012 Management Studio: Creating a Database and a dbo Table. Inserting VALUES into the table. How to insert 8 Values for future use in XQuery?

Hi all,
In my SQL Server 2012 Management Studio (SSMS2012), I tried to create a Database (MacLochainnsDB) and a dbo Table (marvel). then I wanted insert 8 VALUES into the Table by using the following code:
USE master
IF EXISTS
(SELECT 1
FROM sys.databases
WHERE name = 'MacLochlainnsDB')
DROP DATABASE MacLochlainnsDB
GO
CREATE DATABASE MacLochlainnsDB
GO
CREATE TABLE [dbo].[marvel] (
[avenger_name] [char] (30) NULL)
INSERT INTO marvel
(avenger_name)
VALUES
('Hulk', 1),
('Iron Man', 2),
('Black Widow', 3),
('Thor', 4),
('Captain America', 5),
('Hawkeye', 6),
('Winter Soldier', 7),
('Iron Patriot', 8)
I got the following error Message:
Msg 110, Level 15, State 1, Line 5
There are fewer columns in the INSERT statement than values specified in the VALUES clause. The number of values in the VALUES clause must match the number of columns specified in the INSERT statement.
How can I correct this problem?
Please kindly help and advise.
Thanks in advance,
Scott Chang
P. S.
The reason I tried to create the Database, dbo Table, and then to insert the VALUES is to learn the following thing:
You can query the entire node tree with the following xquery statement because it looks for the occurrence of any node with the /* search string:
DECLARE @x xml;
SET @x = N'<marvel>
<avenger_name>Captain America</avenger_name>
</marvel>';
SELECT @x.query('/*');
You can query the avenger_name elements from the marvel_xml table with the following syntax:
SELECT xml_table.query('/marvel/avenger_name')
FROM marvel_xml;
It returns the following set of avenger_name elements:
<avenger_name>Hulk</avenger_name>
<avenger_name>Iron Man</avenger_name>
<avenger_name>Black Widow</avenger_name>
<avenger_name>Thor</avenger_name>
<avenger_name>Captain America</avenger_name>
<avenger_name>Hawkeye</avenger_name>
<avenger_name>Winter Soldier</avenger_name>
<avenger_name>Iron Patriot</avenger_name>
You can query the fourth avenger_name element from the marvel_xml table with the following xquery statement:
SELECT xml_table.query('/marvel[4]/avenger_name')
FROM marvel_xml;
It returns the following avenger_name element:
<avenger_name>Thor</avenger_name>

Hi Scott,
The master database records all the system-level information for a SQL Server system, so best practise would be not to create any user-defined
object within it.
To change your default database(master by default) of your login to another, follow the next steps so that next time when connected you don't have to use "USE dbname" to switch database.
Open SQL Server Management Studio
--> Go to Object explorer(the left panel by default layout)
--> Extend "Security"
--> Extend "Logins"
--> Right click on your login, click "propertites"
--> Choose the "Default database" at the bottom of the pop-up window.
--or simply by T-SQL
Exec sp_defaultdb @loginame='yourLogin', @defdb='youDB'
Regarding your question, you can reference the below.
SELECT * FROM master.sys.all_objects where name ='Marvel'
--OR
SELECT OBJECT_ID('master.dbo.Marvel') --if non empty result returns, the object exists
--usually the OBJECT_ID is used if a if statement as below
IF OBJECT_ID('master.dbo.Marvel') IS NOT NULL
PRINT ('TABLE EXISTS') --Or some other logic
What is the sys.all_objects? See
here.
If you have any question, feel free to let me know.
Eric Zhang
TechNet Community Support

How to insert line number into APPLIED_CUSTOMER_TRX_LINE_ID?

Hi All,
I am working on the table of receivable AR_RECEIVABLE_APPLICATIONS_ALL.
I get some information about APPLIED_CUSTOMER_TRX_LINE_ID form TRM.
APPLIED_CUSTOMER_TRX_LINE_ID NUMBER (15)
The line number of the debit item or credit memo to which a payment or credit memo is applied
So, I want to use APPLIED_CUSTOMER_TRX_LINE_ID to join with transaction's line (RA_CUSTOMER_TRX_LINES_ALL).
But after applied the credit memo, the APPLIED_CUSTOMER_TRX_LINE_ID is NULL.
How to insert line number into APPLIED_CUSTOMER_TRX_LINE_ID?

Hi Eric,
The application is already at the AR Invoice (header) level. Oracle doesn't give you privilege to apply the invoice at invoice line or distribution level. You need to match the applied_customer_trx_id to customer_trx_id of ra_customer_trx_all to get the applied invoice/debit memo number. Hope my comments are helpful to you.
KG

How to insert a number using ADO or OLEDB by oracle provider

I create a talbe .
Create Table A
(id number(7));
I use ADO to access the table a;
_ConnectionPtr pConn=NULL;
pConn.CreateInstance(__uuidof(Connection));
_RecordsetPtr pRst=NULL;
pRst.CreateInstance(__uuidof(Recordset));
pConn->Provider="OraOLEDB.Oracle.1";
try
     pConn->Open("","ISVISION","ISVISION",NULL);
     pRst->CursorLocation=adUseClient;
     pRst->Open("A",pConn.GetInterfacePtr(),adOpenStatic,adLockOptimistic,adCmdTable);
     pRst->AddNew();
     pRst->Fields->Item[0L]->Value=100L;
//It raise a exception,why?
//If I convert the datetype of "ID" to CHAR(7)
//and pRst->Fields->Item[0L]->Value=L"100",it is ok.
     pRst->Update();
     pRst->Close();
     pConn->Close();
catch (_com_error& e)
     MessageBox(e.Description(),"error",MB_OK|MB_ICONWARNING);
     return ;
if (pConn)
pConn.Release();
if (pRst)
pRst.Release();
I create a table Aã
create table A
     ID number(7)
Now ,I use OLE DB to access the table A;
struct CIsA
     CIsA()
          memset(this, 0, sizeof(*this));
public:
     DB_NUMERIC m_ID;
     BEGIN_COLUMN_MAP(CIsA)
          COLUMN_ENTRY_PS(1, 7, 0, m_ID)
     END_COLUMN_MAP()
DEFINE_COMMAND(CIsA, _T("SELECT ID FROM A"))
CDataSource DataSource;
HRESULT hrt=DataSource.Open(_T("OraOLEDB.Oracle.1"),NULL,_T("ISVISION"),_T("ISVISION"));
CSession Session;
hrt=Session.Open(DataSource);
CDBPropSet propset(DBPROPSET_ROWSET);
propset.AddProperty(DBPROP_IRowsetChange, true);
propset.AddProperty(DBPROP_UPDATABILITY,
     DBPROPVAL_UP_INSERT | DBPROPVAL_UP_CHANGE | DBPROPVAL_UP_DELETE);
CCommand<CAccessor<CIsA> > Command;
Command.Open(Session,NULL,&propset);
tcscpy((TCHAR*)Command.mID.val,_T("1245"));
Command.m_ID.sign=1;
hrt=Command.Insert();//It is wrong,why?
Command.Close();
Session.Close();
DataSource.Close();
In Fact,the two problems is the same. The key of problem is how to insert a number into oracle.
help me! thank you.

hi
create a table something like this.
create table image(
Image_Id number(5),
Image    blob);create a form with the same table and use the following code.
when-button-pressed trigger.
read_image_file('c:\image_name.jpg' , 'jpg' , 'image.image');if its correct/helpful please mark it thanks.
sarah

How to read .html file and store values into oracle table from html file

Hi all ,
How to read .html file and store values into oracle table from html file using pl/sql
Please Help.....

Hi,
Kindly find following sample html code ,i want to store every value in different column in database .
<html><body><p/>
<div style="position:absolute;top:47px;left:37px;font-family:'Times New Roman';font-size:10pt;white-space:nowrap;">
</div>
<div style="position:absolute;top:47px;left:680px;font-family:'Times New Roman';font-size:10pt;white-space:nowrap;">
</div>
<div style="position:absolute;top:94px;left:151px;font-family:'Times New Roman';font-size:1pt;white-space:nowrap;">
</div>
<div style="position:absolute;top:1080px;left:115px;font-family:'Times New Roman';font-size:8pt;white-space:nowrap;">4497743
</div>
<div style="position:absolute;top:1079px;left:442px;font-family:'Times New Roman';font-size:9pt;white-space:nowrap;"> Miclyn Express Offshore Pre-Quotation Disclosure
</div>
<div style="position:absolute;top:1079px;left:680px;font-family:'Times New Roman';font-size:9pt;white-space:nowrap;">
</div>
<div style="position:absolute;top:1079px;left:723px;font-family:'Times New Roman';font-size:9pt;white-space:nowrap;">page 5
</div>
<div style="position:absolute;top:1083px;left:151px;font-family:'Times New Roman';font-size:1pt;white-space:nowrap;">
</div>
<div style="position:absolute;top:107px;left:151px;font-family:'Times New Roman';font-size:10pt;white-space:nowrap;"><b>Attachment 2 ¿ indicative statement of 20 largest shareholders </b>
</div>
<div style="position:absolute;top:139px;left:262px;font-family:'Times New Roman';font-size:10pt;white-space:nowrap;"><b>Name </b>
</div>
<div style="position:absolute;top:131px;left:415px;font-family:'Times New Roman';font-size:10pt;white-space:nowrap;"><b>Number of Shares </b>
</div>
<div style="position:absolute;top:147px;left:458px;font-family:'Times New Roman';font-size:10pt;white-space:nowrap;"><b>Held </b>
</div>
<div style="position:absolute;top:131px;left:560px;font-family:'Times New Roman';font-size:10pt;white-space:nowrap;"><b>Percentage of </b>
</div>
<div style="position:absolute;top:147px;left:567px;font-family:'Times New Roman';font-size:10pt;white-space:nowrap;"><b>shares held </b>
</div>
<div style="position:absolute;top:179px;left:161px;font-family:'Times New Roman';font-size:11pt;white-space:nowrap;">Macquarie Capital Group Limited 92,378,000
</div>
<div style="position:absolute;top:179px;left:531px;font-family:'Times New Roman';font-size:11pt;white-space:nowrap;">
</div>
<div style="position:absolute;top:179px;left:618px;font-family:'Times New Roman';font-size:11pt;white-space:nowrap;">34.00%r
</div>
<div style="position:absolute;top:179px;left:663px;font-family:'Times New Roman';font-size:11pt;white-space:nowrap;">
</div>
<div style="position:absolute;top:212px;left:161px;font-family:'Times New Roman';font-size:11pt;white-space:nowrap;">HSBC Custody Nominees (Australia)
</div>
<div style="position:absolute;top:227px;left:161px;font-family:'Times New Roman';font-size:11pt;white-space:nowrap;">Limited
</div>
<div style="position:absolute;top:220px;left:464px;font-family:'Times New Roman';font-size:11pt;white-space:nowrap;">36,458,220
</div>
<div style="position:absolute;top:220px;left:531px;font-family:'Times New Roman';font-size:11pt;white-space:nowrap;">
</div>
<div style="position:absolute;top:220px;left:618px;font-family:'Times New Roman';font-size:11pt;white-space:nowrap;">13.42%
</div>
<div style="position:absolute;top:220px;left:663px;font-family:'Times New Roman';font-size:11pt;white-space:nowrap;">
</div>
<div style="position:absolute;top:260px;left:161px;font-family:'Times New Roman';font-size:11pt;white-space:nowrap;">Ray Rider Limited 27,170,000
</div>
<div style="position:absolute;top:260px;left:531px;font-family:'Times New Roman';font-size:11pt;white-space:nowrap;">
</div>
<div style="position:absolute;top:260px;left:618px;font-family:'Times New Roman';font-size:11pt;white-space:nowrap;">10.00%
</div>
<div style="position:absolute;top:260px;left:663px;font-family:'Times New Roman';font-size:11pt;white-space:nowrap;">
</div>
<div style="position:absolute;top:300px;left:531px;font-family:'Times New Roman';font-size:11pt;white-space:nowrap;">
</div>
<div style="position:absolute;top:300px;left:625px;font-family:'Times New Roman';font-size:11pt;white-space:nowrap;">7.96%
</div>
<div style="position:absolute;top:300px;left:663px;font-family:'Times New Roman';font-size:11pt;white-space:nowrap;">
</div>
<div style="position:absolute;top:333px;left:161px;font-family:'Times New Roman';font-size:11pt;white-space:nowrap;">National Australia Bank Custodian
</div>
<div style="position:absolute;top:348px;left:161px;font-family:'Times New Roman';font-size:11pt;white-space:nowrap;">Services
</div>
<div style="position:absolute;top:341px;left:464px;font-family:'Times New Roman';font-size:11pt;white-space:nowrap;">12,866,550
</div>
<div style="position:absolute;top:341px;left:531px;font-family:'Times New Roman';font-size:11pt;white-space:nowrap;">
</div>
<div style="position:absolute;top:341px;left:625px;font-family:'Times New Roman';font-size:11pt;white-space:nowrap;">4.74%
</div>
<div style="position:absolute;top:341px;left:663px;font-family:'Times New Roman';font-size:11pt;white-space:nowrap;">
</div>
<div style="position:absolute;top:381px;left:161px;font-family:'Times New Roman';font-size:11pt;white-space:nowrap;">Citigroup Nominees Pty Ltd 6,942,541
</div>
<div style="position:absolute;top:381px;left:531px;font-family:'Times New Roman';font-size:11pt;white-space:nowrap;">
</div>
<div style="position:absolute;top:381px;left:625px;font-family:'Times New Roman';font-size:11pt;white-space:nowrap;">2.56%r
</div>
<div style="position:absolute;top:381px;left:663px;font-family:'Times New Roman';font-size:11pt;white-space:nowrap;">
</div>
<div style="position:absolute;top:421px;left:531px;font-family:'Times New Roman';font-size:11pt;white-space:nowrap;">
</div>
<div style="position:absolute;top:421px;left:625px;font-family:'Times New Roman';font-size:11pt;white-space:nowrap;">2.14%r
</div>
<div style="position:absolute;top:421px;left:663px;font-family:'Times New Roman';font-size:11pt;white-space:nowrap;">
</div>
<div style="position:absolute;top:462px;left:161px;font-family:'Times New Roman';font-size:11pt;white-space:nowrap;">UBS Securities Australia Ltd 4,806,760
</div>
<div style="position:absolute;top:462px;left:531px;font-family:'Times New Roman';font-size:11pt;white-space:nowrap;">
</div>
<div style="position:absolute;top:462px;left:625px;font-family:'Times New Roman';font-size:11pt;white-space:nowrap;">1.77%
</div>
<div style="position:absolute;top:462px;left:663px;font-family:'Times New Roman';font-size:11pt;white-space:nowrap;">
</div>
<div style="position:absolute;top:494px;left:161px;font-family:'Times New Roman';font-size:11pt;white-space:nowrap;">Merrill Lynch Equities (Australia)
</div>
<div style="position:absolute;top:510px;left:161px;font-family:'Times New Roman';font-size:11pt;white-space:nowrap;">Limited
</div>
<div style="position:absolute;top:502px;left:472px;font-family:'Times New Roman';font-size:11pt;white-space:nowrap;">4,325,000
</div>
<div style="position:absolute;top:502px;left:531px;font-family:'Times New Roman';font-size:11pt;white-space:nowrap;">
</div>
<div style="position:absolute;top:502px;left:625px;font-family:'Times New Roman';font-size:11pt;white-space:nowrap;">1.59%
</div>
<div style="position:absolute;top:502px;left:663px;font-family:'Times New Roman';font-size:11pt;white-space:nowrap;">
</div>
<div style="position:absolute;top:550px;left:161px;font-family:'Times New Roman';font-size:11pt;white-space:nowrap;">Equities Ltd
</div>
<div style="position:absolute;top:542px;left:472px;font-family:'Times New Roman';font-size:11pt;white-space:nowrap;">4,150,000
</div>
<div style="position:absolute;top:542px;left:531px;font-family:'Times New Roman';font-size:11pt;white-space:nowrap;">
</div>
<div style="position:absolute;top:542px;left:625px;font-family:'Times New Roman';font-size:11pt;white-space:nowrap;">1.53%
</div>
<div style="position:absolute;top:542px;left:663px;font-family:'Times New Roman';font-size:11pt;white-space:nowrap;">
</div>
<div style="position:absolute;top:575px;left:161px;font-family:'Times New Roman';font-size:11pt;white-space:nowrap;">Bond Street Custodians Limited - A/C
</div>
<div style="position:absolute;top:590px;left:161px;font-family:'Times New Roman';font-size:11pt;white-space:nowrap;">Institutional
</div>
<div style="position:absolute;top:583px;left:472px;font-family:'Times New Roman';font-size:11pt;white-space:nowrap;">2,750,000
</div>
<div style="position:absolute;top:583px;left:531px;font-family:'Times New Roman';font-size:11pt;white-space:nowrap;">
</div>
<div style="position:absolute;top:583px;left:625px;font-family:'Times New Roman';font-size:11pt;white-space:nowrap;">1.01%
</div>
<div style="position:absolute;top:583px;left:663px;font-family:'Times New Roman';font-size:11pt;white-space:nowrap;">
</div>
<div style="position:absolute;top:623px;left:161px;font-family:'Times New Roman';font-size:11pt;white-space:nowrap;">Cogent Investment Operations Pty Ltd 2,599,321
</div>
<div style="position:absolute;top:623px;left:531px;font-family:'Times New Roman';font-size:11pt;white-space:nowrap;">
</div>
<div style="position:absolute;top:623px;left:625px;font-family:'Times New Roman';font-size:11pt;white-space:nowrap;">0.96%
</div>
<div style="position:absolute;top:623px;left:663px;font-family:'Times New Roman';font-size:11pt;white-space:nowrap;">
</div>
<div style="position:absolute;top:663px;left:161px;font-family:'Times New Roman';font-size:11pt;white-space:nowrap;">Skeet Nominees Pty Ltd 2,276,736
</div>
<div style="position:absolute;top:663px;left:531px;font-family:'Times New Roman';font-size:11pt;white-space:nowrap;">
</div>
<div style="position:absolute;top:663px;left:625px;font-family:'Times New Roman';font-size:11pt;white-space:nowrap;">0.84%
</div>
<div style="position:absolute;top:663px;left:663px;font-family:'Times New Roman';font-size:11pt;white-space:nowrap;">
</div>
<div style="position:absolute;top:704px;left:161px;font-family:'Times New Roman';font-size:11pt;white-space:nowrap;">Diederik de Boer 1,917,561
</div>
<div style="position:absolute;top:704px;left:531px;font-family:'Times New Roman';font-size:11pt;white-space:nowrap;">
</div>
<div style="position:absolute;top:704px;left:625px;font-family:'Times New Roman';font-size:11pt;white-space:nowrap;">0.71%
</div>
<div style="position:absolute;top:704px;left:663px;font-family:'Times New Roman';font-size:11pt;white-space:nowrap;">
</div>
<div style="position:absolute;top:744px;left:161px;font-family:'Times New Roman';font-size:11pt;white-space:nowrap;">Ecapital Nominees Pty Limited 1,594,736
</div>
<div style="position:absolute;top:744px;left:531px;font-family:'Times New Roman';font-size:11pt;white-space:nowrap;">
</div>
<div style="position:absolute;top:744px;left:625px;font-family:'Times New Roman';font-size:11pt;white-space:nowrap;">0.59%
</div>
<div style="position:absolute;top:744px;left:663px;font-family:'Times New Roman';font-size:11pt;white-space:nowrap;">
</div>
<div style="position:absolute;top:777px;left:161px;font-family:'Times New Roman';font-size:11pt;white-space:nowrap;">Neweconomy Com Au Nominees Pty 9
</div>
<div style="position:absolute;top:792px;left:161px;font-family:'Times New Roman';font-size:11pt;white-space:nowrap;">Limited <900 Account>
</div>
<div style="position:absolute;top:784px;left:472px;font-family:'Times New Roman';font-size:11pt;white-space:nowrap;">1,594,7360
</div>
<div style="position:absolute;top:784px;left:531px;font-family:'Times New Roman';font-size:11pt;white-space:nowrap;">
</div>
<div style="position:absolute;top:784px;left:625px;font-family:'Times New Roman';font-size:11pt;white-space:nowrap;">0.59%
</div>
<div style="position:absolute;top:784px;left:663px;font-family:'Times New Roman';font-size:11pt;white-space:nowrap;">
</div>
<div style="position:absolute;top:825px;left:161px;font-family:'Times New Roman';font-size:11pt;white-space:nowrap;">Sonray Capital Markets Pty Ltd 1,236,842
</div>
<div style="position:absolute;top:825px;left:531px;font-family:'Times New Roman';font-size:11pt;white-space:nowrap;">
</div>
<div style="position:absolute;top:825px;left:625px;font-family:'Times New Roman';font-size:11pt;white-space:nowrap;">0.46%
</div>
<div style="position:absolute;top:825px;left:663px;font-family:'Times New Roman';font-size:11pt;white-space:nowrap;">
</div>
<div style="position:absolute;top:865px;left:161px;font-family:'Times New Roman';font-size:11pt;white-space:nowrap;">Argo Investments Limited 1,050,000
</div>
<div style="position:absolute;top:865px;left:531px;font-family:'Times New Roman';font-size:11pt;white-space:nowrap;">
</div>
<div style="position:absolute;top:865px;left:625px;font-family:'Times New Roman';font-size:11pt;white-space:nowrap;">0.39%
</div>
<div style="position:absolute;top:865px;left:663px;font-family:'Times New Roman';font-size:11pt;white-space:nowrap;">
</div>
<div style="position:absolute;top:905px;left:161px;font-family:'Times New Roman';font-size:11pt;white-space:nowrap;">Idameno (No 79) Nominees Pty Limited 724,210</div>
<div style="position:absolute;top:1103px;">
</body></html>
Thanks..........................

How to copy one column BLOB value into another column of another database.

How to copy one column BLOB value into another column of another database.
BLOB value contains word document.
I thought of copy the BLOB value into a text file and then update the new column value by the same text in textfile. Will this work?
Is there any other better way to do this?

You're welcome
BLOB fields contains binary data. I don't think you can do this
Also if I view the BLOB as text. Can I copy it and insert into the new database.
I think your options are as I said. Datapump or CTAS
Best Regards

How to insert various number of values into a table

Similar Messages

Maybe you are looking for