How to know the all user name from system/system login
hi all,
i want to know the all user names from system login who are the existing user like
regards
srinivas
Hello,
Using DBA_USERS will give more details
select * from dba_users;Regards
Similar Messages
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How to retrieve the all user name from system domain(including login user)?
Hi, I am trying to get the system domain all users name. But I unable to get the all user name except domain login user name. I used the below code. What I want to do to get the all user name from system domain. Kindly any one help me.
Properties envVars = new Properties();
Runtime r = Runtime.getRuntime();
String OS = System.getProperty("os.name").toLowerCase();
if ((OS.indexOf("nt") > -1) || (OS.indexOf("windows 2000") > -1 ) || (OS.indexOf("windows xp") > -1) )
p = r.exec( "cmd.exe /c set" );
BufferedReader br = new BufferedReader ( new InputStreamReader( p.getInputStream() ) );
String line;
while( (line = br.readLine()) != null )
int idx = line.indexOf( '=' );
String key = line.substring( 0, idx );
String value = line.substring( idx+1 );
envVars.setProperty( key, value );
String domainDNSName = envVars.getProperty("USERDNSDOMAIN");
String userName = envVars.getProperty("USERNAME");
System.out.println("\n\n\n DOMAIN NAME == "+domainDNSName +" USERNAME == "+userName);
Thanks & Regards
PalaniThanks kajbj,
I don't know, How many users in domain. I neet to get all the user names from my domain. User like A, B,C,D, E,F. I need to get this users name.
public class Env {
public static void main(String[] args) {
System.out.println("USERDOMAIN: " + System.getenv("USERDOMAIN"));
System.out.println("USERNAME: " + System.getenv("USERNAME"));
Here , I am getting the login user name only. So i needs all user name. How to retrive or get this.
Regards
Palani -
Is there any query to know the multiple users name from their ids?
is there any query to know the multiple users name from their ids?
Hi,
Goto TCode SUIM Select Users Select Users by Address Data
It will give you the users list
Regards,
Sankaran -
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How can I transfer two user names from an iMac to a new macbook?
got a new laptop and need to transfer two usernames to it, complete with all documents help?Assuming you haven't already set up a user, the easiest way is to use the Setup Assistant during first boot of the new Mac, with the two Macs connected by firewire.
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Apparently you can get the page id and work it out from there, but my calls to get the page id are not returning any values anyway.
My code for attempting to get the page id is below.
<oracle>
declare
v_pageid varchar2(30);
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</oracle>
Ideally I'd actually just like to get the page name. Is there a straightforward way to do this?
Thanks in advance!
SarahFew clarifications -
1. wwpro_api_parameters cannot be used to get default portal
page parameters such as '_pageid', '_dad', '_schema' etc.,
2. Page information can be obtained through any components which
are available in that particular page. For example, in case of
dynamic page, we need to publish it as a portlet and add it to the
page. This process creates necessary packages in the DB, but we
will not have access to the portlet methods.
So, I would prefer creating a simple DB provider & portlet and access
page title from its show method as follows -
//Declare local variable l_page_id, l_page_title as varchar2
select page_id into l_page_id from wwpob_portlet_instance$ where
portlet_id = p_portlet_record.portlet_id and
provider_id = p_portlet_record.provider_id;
select name into l_page_title from wwpob_page$ where id=l_page_id;
More information on DB provider can be found at
http://portalstudio.oracle.com/pls/ops/docs/FOLDER/COMMUNITY/PDK/articles/understanding.database.providers.html
Secondly, usage of wwpro_api_parameters.get_value method is
incorrect. This method expects two arguments -
<ul>
<li><b>p_name : </b> The name of the parameter to be returned.</li>
<li><b>p_reference_path : </b> An unique identifier for a portlet instance on the current page.</li>
</ul>
p_reference_path would be something like 99_SNOOP_PORTLET_76535103 and not some type of path as its name suggests.
The following code fragment fetches all parameters available
for a portlet.
Note : Copy this code into 'show' method of your portlet.
//Declare l_names, l_values as owa.vc_arr
* Retreive all of the names of parameters for this portlet
l_names := wwpro_api_parameters.get_names(
p_reference_path=>p_portlet_record.reference_path);
* Retreive all of the values of parameters for this portlet
l_values := wwpro_api_parameters.get_values(p_names=>l_names,
p_reference_path=>p_portlet_record.reference_path);
//Loop through these arrays to get parameter information
htp.p('<center><table BORDER COLS=2 WIDTH="90%" >');
htp.p('<tr ALIGN=LEFT VALIGN=TOP>');
htp.tableData(wwui_api_portlet.portlet_heading('Name',1));
htp.tableData(wwui_api_portlet.portlet_heading('Value',1));
htp.tableRowClose;
if l_names.count = 0 then
htp.p('<tr ALIGN=LEFT VALIGN=TOP>');
htp.p('<td COLSPAN="2">'
||wwui_api_portlet.portlet_text(
'No portlet parameters were passed on the URL.',1)
||'</td>');
htp.tableRowClose;
else
for i in 1..l_names.count loop
htp.p('<tr ALIGN=LEFT VALIGN=TOP>');
htp.tableData(l_names(i));
htp.tableData(l_values(i));
htp.tableRowClose;
end loop;
end if;
htp.p('</table></center>');
Hope it helps...
-aMJAD. -
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public ObservableCollection<CellVM> PlateCells
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bool _isSelected;
public bool IsSelected
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when a cell is selected, the cell will be highlight in both DataGrid and ListBox.
We also implement SelectAll button for both DataGrid and ListBox.
And SelectAll is ToggleButton. First time click is select All cells and second time click, it will unselect All cells.
What we notice when SelectAll button is click, all cells in both DataGrid and List box are highlight.
After that click on a grid any cell, all cells becomes unselected in both DataGrid and ListBox.
We assume this the behavior from DataGrid, after click SelectAll and click any cell in DataGrid will remove all selection and only highlight one cell in the datagrid.
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It depends on where in the code you want to be able to determine this. In the view model class you cannot really know if the user clicked in the ListBox or in the DataGrid because the view model knows nothing (and shouldn't know either) about any of these
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<i:Interaction.Triggers>
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<i:InvokeCommandAction Command="{Binding YourCommand}" />
</i:EventTrigger>
</i:Interaction.Triggers>
</DataGrid>
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Anyway, as mentioned, handling the GotFocus event seems like a good idea here since you cannot determine which control that was clicked in the setter of the source property in the view model class.
Hope that helps.
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package com.yourcompany.jmx;
import javax.management.MBeanServer;
import javax.management.ObjectName;
import javax.naming.InitialContext;
public class JMXWrapper {
private static JMXWrapper instance = new JMXWrapper();
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private String managedServerName;
private JMXWrapper() {
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if (domainName == null) {
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System.out.println("Caught Exception: " + ex);
ex.printStackTrace();
return domainName;
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if (managedServerName == null) {
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managedServerName = (String) getMBeanServer().getAttribute(getRuntimeService(), "ServerName");
} catch (Exception ex) {
System.out.println("Caught Exception: " + ex);
ex.printStackTrace();
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} catch (Exception dontCare) {
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try {
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} catch (Exception ex) {
System.out.println("Caught Exception: " + ex);
ex.printStackTrace();
return retval;
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<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN"
"http://www.w3.org/TR/html4/loose.dtd">
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%>
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<head>
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<title>JMX Wrapper Test</title>
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Hi and a warm welcome to the forums!
I think we'd be better off figuring out how to install it for the other User, but...
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Hi there,
I am trying to download data from an URL and save the content in a file that have the same name as the file on the server. In some way, what I want to do is pretty similar to what you can do when you do a right click on a link in Internet Explorer (or any other web browser) and choose "save target as".
If the URL is a direct link to the file (for example: http://java.sun.com/images/e8_java_logo_red.jpg ), I do not have any problem:
URL url = new URL("http://java.sun.com/images/e8_java_logo_red.jpg");
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InputStream is = url.openStream();
FileOutputStream fos=null;
String fileName = null;
StringTokenizer st=new StringTokenizer(url.getFile(), "/");
while (st.hasMoreTokens())
fileName=st.nextToken();
System.out.println("The file name will be: " + fileName);
File localFile= new File(System.getProperty("user.dir"), fileName);
fos = new FileOutputStream(localFile);
try {
byte[] buf = new byte[1024];
int i = 0;
while ((i = is.read(buf)) != -1) {
fos.write(buf, 0, i);
} catch (Throwable e) {
e.printStackTrace();
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if (is != null)
is.close();
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However, if the URL is an indirect link to the file (for example: http://javadl.sun.com/webapps/download/AutoDL?BundleId=37719 , which link to a file named JavaSetup6u18-rv.exe ), the similar code return AutoDL?BundleId=37719 as file name, when I would like to have JavaSetup6u18-rv.exe .
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try {
byte[] buf = new byte[1024];
int i = 0;
while ((i = is.read(buf)) != -1) {
fos.write(buf, 0, i);
} catch (Throwable e) {
e.printStackTrace();
} finally {
if (is != null)
is.close();
if (fos != null)
fos.close();
}Do you know how I can do that.
Thanks for your help
// JB
Edited by: jb-from-sydney on Feb 9, 2010 10:37 PMThanks for your answer.
By following your idea, I found out that one of the header ( content-disposition ) can contain the name to be used if the file is downloaded. Here is the full code that allow you to download locally a file on the Internet:
* Download locally a file from a given URL.
* @param url - the url.
* @param destinationFolder - The destination folder.
* @return the file
* @throws IOException Signals that an I/O exception has occurred.
public static final File downloadFile(URL url, File destinationFolder) throws IOException {
URLConnection urlC = url.openConnection();
InputStream is = urlC.getInputStream();
FileOutputStream fos = null;
String fileName = getFileName(urlC);
destinationFolder.mkdirs();
File localFile = new File(destinationFolder, fileName);
fos = new FileOutputStream(localFile);
try {
byte[] buf = new byte[1024];
int i = 0;
while ((i = is.read(buf)) != -1) {
fos.write(buf, 0, i);
} finally {
if (is != null)
is.close();
if (fos != null)
fos.close();
return localFile;
* Returns the file name associated to an url connection.<br />
* The result is not a path but just a file name.
* @param urlC - the url connection
* @return the file name
* @throws IOException Signals that an I/O exception has occurred.
private static final String getFileName(URLConnection urlC) throws IOException {
String fileName = null;
String contentDisposition = urlC.getHeaderField("content-disposition");
if (contentDisposition != null) {
fileName = extractFileNameFromContentDisposition(contentDisposition);
// if the file name cannot be extracted from the content-disposition
// header, using the url.getFilename() method
if (fileName == null) {
StringTokenizer st = new StringTokenizer(urlC.getURL().getFile(), "/");
while (st.hasMoreTokens())
fileName = st.nextToken();
return fileName;
* Extract the file name from the content disposition header.
* <p>
* See <a
* href="http://www.w3.org/Protocols/rfc2616/rfc2616-sec19.html">http:
* //www.w3.org/Protocols/rfc2616/rfc2616-sec19.html</a> for detailled
* information regarding the headers in HTML.
* @param contentDisposition - the content-disposition header. Cannot be
* <code>null>/code>.
* @return the file name, or <code>null</code> if the content-disposition
* header does not contain the filename attribute.
private static final String extractFileNameFromContentDisposition(
String contentDisposition) {
String[] attributes = contentDisposition.split(";");
for (String a : attributes) {
if (a.toLowerCase().contains("filename")) {
// The attribute is the file name. The filename is between
// quotes.
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// not found
return null;
} -
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Sathish. RHi ,
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If you have such requirement, you can create one custom table with fields :
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whenever you run ur program update this table ,
with system fields . spono , sy-repid , sy-datum and sy-uzeit .
Thaks .
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