How to read date and time with Oracle_Loader (10g)
ip pc username date time
1.1.1.1 WS1 test 2000/01/01 01:01:01
I am trying to read the date and time from data formatted as above from a .txt file.
create TABLE test (IP char(20), OCID char(15), ID char(30), date_logon date, time_logon date)
ORGANIZATION EXTERNAL (TYPE ORACLE_loader DEFAULT DIRECTORY phonebook
ACCESS PARAMETERS (FIELDS TERMINATED BY WHITESPACE
(IP char(20),
OCID char(15),
ID char(30),
date_logon char(30) DATE_FORMAT DATE MASK "yyyy/mm/dd",
time_logon char(30) date_FORMAT date MASK "hh24:mi:ss"))
LOCATION ('test.log'));
However, my external table returns a date (2007-05-01) AND the time for the time_logon column (e.g. 2007-05-01 01:01:01) . I just want the time (e.g. 01:01:01).
What am I doing wrong?
*I tried: date_logon char(30) DATE_FORMAT DATE MASK "yyyy/mm/dd hh24:mi:ss", reading both the date and time at the same time, but it doesn't work.
Thanks.
Justin, thank you so much for your help.
When I try:
SELECT a.ip, a.ocid, a.id, TO_CHAR( a.date_logon, 'DD-MON-YYYY HH24:MI:SS' )
FROM test a
date_logon entries are all dd-mon-yyyy and 00:00:00 (i.e. no time was stored).
I don't have control over the text file, so I don't think I can make any changes to the formatting.
I tried to declare the column as 'timestamp':
date_logon char(60) DATE_FORMAT timestamp MASK "yyyy/mm/dd hh24:mi:ss",
but time is still displayed as 00:00:00:000.... which leads me to suspect that the culprit is the space between date and time in the text file.
Say if I have 2007/05/25 and 2007/05/01 16:19:23 in two separate date columns. Is it possible to grab the time from the second column and append it to the first column (while still retaining the DATE property, i.e. 2007/05/25 16:19:23).
Thanks!
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