How to remove a node from a target xml payload in reciever file channel

i have a scenario where i have to remove a node from my target xml file in receiver file channel and want xml as the output file. I don't want a fixed length file. How to do that in receiver channel? Do we need to use file content conversion for that?

that will result in giving you a fixed file or a separator defined file.
it will not give you an XML file.
In case you want a XML file, instead of using variable substitution, use Dynamic configuration and adapter specific properties.
Some ref:
/people/michal.krawczyk2/blog/2005/11/10/xi-the-same-filename-from-a-sender-to-a-receiver-file-adapter--sp14
http://help.sap.com/saphelp_nw04/helpdata/en/43/03612cdecc6e76e10000000a422035/frameset.htm

Similar Messages

How to remove a node from nlb at runtime?

hello,
i need to temporally exclude a node from an nlb.
May happen that a server is up and working but the web application i'm balancing is out of sinch with the same application in the others nodes.
Eg. some static variables are not the same of the same static variables of other nodes, because of a timeout, a write error and so on but the server is still working.
in this case i need to stop the server from nlb because the information in the web application is not in sinch with other nodes.
I need to prevent users from being serverd from this out to date server, untill it will became updated, but i need to do this programmatically
how can i do it?

"DuoMi" <[email protected]> wrote in message
news:gnojbf$2sg$[email protected]..
> How to remove a node from XMLList
>
> I want remove the first node from XMLList
>
>
> and how to get the combobox all values string:
>
> <data>
> <value>2</value>
> </date>
> <data>
> <value>5</value>
> </date>
> <data>
> <value>8</value>
> </date>
>
> I need a string whit value "2,5,8"
>
> thkan you.~
I think something like
comboBox.dataProvider..value.toString()
will work.

How to remove a node from XMLList

How to remove a node from XMLList
I want remove the first node from XMLList
and how to get the combobox all values string:
<data>
<value>2</value>
</date>
<data>
<value>5</value>
</date>
<data>
<value>8</value>
</date>
I need a string whit value "2,5,8"
thkan you.~

"DuoMi" <[email protected]> wrote in message
news:gnojbf$2sg$[email protected]..
> How to remove a node from XMLList
>
> I want remove the first node from XMLList
>
>
> and how to get the combobox all values string:
>
> <data>
> <value>2</value>
> </date>
> <data>
> <value>5</value>
> </date>
> <data>
> <value>8</value>
> </date>
>
> I need a string whit value "2,5,8"
>
> thkan you.~
I think something like
comboBox.dataProvider..value.toString()
will work.

[svn:bz-trunk] 21260: Update the qa-frameworks. zip to remove all comments from the base xml when merging config files.

Revision: 21260
Revision: 21260
Author:   [email protected]
Date:     2011-05-16 07:46:54 -0700 (Mon, 16 May 2011)
Log Message:
Update the qa-frameworks.zip to remove all comments from the base xml when merging config files.
Modified Paths:
    blazeds/trunk/qa/resources/frameworks/qa-frameworks.zip

Try options=('!makeflags') in PKGBUILD.

How to remove a node from a xml

Hi All,
I want to remove a node from my xml output. Can anyone suggest me how to get that? I want to implement this by using the ASSIGN activity.
My sample output is
<env:Envelope xmlns:env="http://schemas.xmlsoap.org/soap/envelope/" xmlns:wsa="http://www.w3.org/2005/08/addressing">
     <env:Header>
          <wsa:MessageID>urn:4EF1A350677C11E1BFA7794ED76B03EF</wsa:MessageID>
          <wsa:ReplyTo>
               <wsa:Address>http://www.w3.org/2005/08/addressing/anonymous</wsa:Address>
          </wsa:ReplyTo>
     </env:Header>
     <env:Body>
          <SiebelOrderQueryByExample_Output xmlns="http://siebel.com/asi/">
               <ListOfOrderInterface xmlns="http://www.siebel.com/xml/Siebel%20Order">
                    <Orders>
                         <Id>1-15IXJ</Id>
                         <AccountId>1-2EE</AccountId>
                         <OrderNumber>1012-1234</OrderNumber>
                         <ListOfLineItems>
                              <LineItems>
                                   <Id>1-15IYN</Id>
                                   <LineNumber>303</LineNumber>
                                   <OrderNumber>1012-1234</OrderNumber>
                                   <OrderHeaderId>1-15IXJ</OrderHeaderId>
                         </LineItems>
                              </ListOfLineItems>
                         </Orders>
</ListOfOrderInterface>
          </SiebelOrderQueryByExample_Output>
     </env:Body>
</env:Envelope>
I want to delete the <ListOfLineItems>node from the xml above so that my resultant would be,
     <env:Envelope xmlns:env="http://schemas.xmlsoap.org/soap/envelope/" xmlns:wsa="http://www.w3.org/2005/08/addressing">
     <env:Header>
          <wsa:MessageID>urn:4EF1A350677C11E1BFA7794ED76B03EF</wsa:MessageID>
          <wsa:ReplyTo>
               <wsa:Address>http://www.w3.org/2005/08/addressing/anonymous</wsa:Address>
          </wsa:ReplyTo>
     </env:Header>
     <env:Body>
          <SiebelOrderQueryByExample_Output xmlns="http://siebel.com/asi/">
               <ListOfOrderInterface xmlns="http://www.siebel.com/xml/Siebel%20Order">
                    <Orders>
                         <Id>1-15IXJ</Id>
                         <AccountId>1-2EE</AccountId>
                         <OrderNumber>1012-1234</OrderNumber>
     </Orders>
</ListOfOrderInterface>
          </SiebelOrderQueryByExample_Output>
     </env:Body>
</env:Envelope>
Please suggest something Its urgent.
Thanks in Advance.

It goes something like this, taken from the above blog entry:
Removing a node from node-list
With the bpelx: extensions in BPEL you are able to insert and update nodes in a node list. A node-list is an XML message that contains a set of records. In this article I use the following example:
<BookList xmlns="http://message.vijfhuizen.com">
<Book>
<title>The Lord Of The Rings</title>
<author>J.R.R. Tolkien</author>
</Book>
<Book>
<title>Harry Potter</title>
<author>J.R.R. Tolkien</author>
</Book>
<Book>
<title>The Hobbit</title>
<author>J.R.R. Tolkien</author>
</Book>
<Book>
<title>Storm; Chronicals of Pandarve</title>
<author>Don Lawrence</author>
</Book>
</BookList>
For creating and updating node lists the bpelx: functions are enough to handle this. But when you want to remove a particular node, you can use the bpelx:remove function. But this function can only remove a node from a particular position. For example removing the second node you code:
<bpel:assign>
<bpelx:remove>
<bpelx:target variable="VarBookList" query="/Booklist/Book[2]" />
</bpelx:append>
</bpel:assign>
It is hard to code the bpelx:remove to create a xpath to dynamicly remove node. You would like to remove the second node based on the xpath:
/Booklist/Book[title="Harry Potter" and author="J.R.R. Tolkien"]
You can add the above xpath in the bpelx:remove, but you are not able to make this dynamically.
There is a solution. The trick is to create a stylesheet that copies the data into a new message, but removing that particular records. Create a stylesheet that does the normal copy of the XML message. Then add a <choose> element in the stylsheet to filter that particular record.
<xsl:template match="/">
<BookList>
<xsl:for-each select="/BookList/Book">
<xsl:choose>
<xsl:when test="title='Harry Potter' and author='J.R.R. Tolkien'"/>
<xsl:otherwise>
<Book>
<title>
<xsl:value-of select="title"/>
</title>
<author>
<xsl:value-of select="author"/>
</author>
</Book>
</xsl:otherwise>
</xsl:choose>
</xsl:for-each>
</BookList>
Now we have a XSL stylesheet that removes a particular record, but this is not variable. This can be done via XSLT parameters.
<xsl:param name="pTitle"/>
<xsl:param name="pAuthor"/>
<xsl:template match="/">
<BookList>
<xsl:for-each select="/BookList/Book">
<xsl:choose>
<xsl:when test="title=$pTitle and author=$pAuthor"/>
<xsl:otherwise>
<Book>
<title>
<xsl:value-of select="title"/>
</title>
<author>
<xsl:value-of select="author"/>
</author>
</Book>
</xsl:otherwise>
</xsl:choose>
</xsl:for-each>
</BookList>
</xsl:template>
Now we are able to use this stylesheet in BPEL. In general BPEL create the following code:
<assign name="Transform">
<bpelx:annotation>
<bpelx:pattern>transformation</bpelx:pattern>
</bpelx:annotation>
<copy>
<from expression="ora:processXSLT('RemoveNode.xsl'
, bpws:getVariableData('Variable_BookList','payload')" />
<to variable="Variable_BookListTemp" part="payload"/>
</copy>
</assign>
But this code does not pass parameters to the stylesheet. The ora:processXSLT() can do this it has an additional parameter in this function:
<assign name="Transform">
<bpelx:annotation>
<bpelx:pattern>transformation</bpelx:pattern>
</bpelx:annotation>
<copy>
<from expression="ora:processXSLT('RemoveNode.xsl'
, bpws:getVariableData('Variable_BookList','payload')" />
, bpws:getVariableData('BPELxslparameters'))"/>
<to variable="Variable_BookListTemp" part="payload"/>
</copy>
</assign>
Now only you have to create the BPELxslparameters variable and assign it with the correct name/value pairs. The structure of the this variable is as follows:
<?xml version="1.0" encoding="windows-1252" ?>
<xsd:schema xmlns:xsd="http://www.w3.org/2001/XMLSchema"
xmlns="http://schemas.oracle.com/service/bpel/common"
targetNamespace="http://schemas.oracle.com/service/bpel/common"
elementFormDefault="qualified">
<xsd:element name="parameters">
<xsd:complexType>
<xsd:sequence>
<xsd:element name="item" minOccurs="1" maxOccurs="unbounded">
<xsd:complexType>
<xsd:sequence>
<xsd:element name="name" type="xsd:string"/>
<xsd:element name="value" type="xsd:string"/>
</xsd:sequence>
</xsd:complexType>
</xsd:element>
</xsd:sequence>
</xsd:complexType>
</xsd:element>
</xsd:schema>
Create in BPEL the variable BPELxslparameters and let it point to this strucure:
<process ....
xmlns:common="http://schemas.oracle.com/service/bpel/common"
.../>
<variable name="BPELparameters" element="common:parameters"/>
Now we can in BPEL create an empty XML message, based on this strcuture and assign the values to these parameters and then call the processXSLT function.
<bpelx:assign name="Assign_GenerateEmptyParameterSet">
<copy>
<from>
<parameters xmlns="http://schemas.oracle.com/service/bpel/common">
<item>
<name>pTitle</name>
<value/>
</item>
<item>
<name>pAutor</name>
<value/>
</item>
</parameters>
</from>
<to variable="BPELparameters" query="/common:parameters"/>
</copy>
</bpelx:assign>
<assign name="Assign_setXSLTParameters">
<copy>
<from expression="'Harry Potter'"/>
<to variable="BPELparameters" query="/common:parameters/common:item[1]/common:value"/>
</copy>
<copy>
<from expression="'J.R.R. Tolkien'"/>
<to variable="BPELparameters" query="/common:parameters/common:item[1]/common:value"/>
</copy>
</assign>
Posted by Marc Kelderman SOA Blog at 1/16/2008 09:20:00 PM

How To Remove Empty Node From Source XML

Hi,
How can I remove an empty node from the source xml in a XSLT mapping.
For e.g. If the source xml is like:
<SRC>
<Node1>SAP</Node2>
<Node2/>
<Node3>XI</Node3>
</SRC>
Then the xml should become:
<SRC>
<Node1>SAP</Node2>
<Node3>XI</Node3>
</SRC>
I need to do this because the output of my XSLT mapping is showing blank spaces for each blank node.
Thanks,
Abhishek.

Use <xsl:if>
Or else you may find different options here
http://www.dpawson.co.uk/xsl/sect2/N3328.html#d4804e304
Regards,
Prateek

How to remove a node from 4 node sun cluster 3.1

Dear All,
We are having a four nodes in a cluster.
Could any one please guide me, how to remove a single node from a 4 node cluster.
what are the procedure and step's I have to follow.
Thanks in advance.
Veera.

Google is pretty good at finding the right pages in our docs quickly. I tried >how to remove a node Solaris Cluster< and it came up with
http://docs.sun.com/app/docs/doc/819-2971/gcfso?a=view
Tim
---

How to Remove a Node from JTree?

I want to remove a node from a JTree but the node may or maynot be visible.
My method takes a String which is the name of the node.
The nodes im using are DefaultMutableTreeNode
This is my code so far but it doesnt work.
public void removePerson(String pName)
          TreePath node = tree.getNextMatch(pName,0,Position.Bias.Forward);
          tree.expandPath(node);
          tree.removeSelectionPath(node);
}Any Suggestions or ways which i could achive this?
Thank you,

I don't think removeSelectionPath is what you want to use.
These should help:
[http://java.sun.com/j2se/1.4.2/docs/api/javax/swing/tree/DefaultTreeModel.html#removeNodeFromParent(javax.swing.tree.MutableTreeNode)|http://java.sun.com/j2se/1.4.2/docs/api/javax/swing/tree/DefaultTreeModel.html#removeNodeFromParent(javax.swing.tree.MutableTreeNode)]
[http://www.roseindia.net/java/example/java/swing/RemoveNodes.shtml|http://www.roseindia.net/java/example/java/swing/RemoveNodes.shtml]

How to remove a node from a Jtree?

I tried giving this to move a node from one parent node to other parent node.
IconNodeClass userObject = (IconNodeClass)tr.getTransferData(TransferableDataItem.Image_Tree_Node_Flavor);
IconNodeClass node = (IconNodeClass)path.getLastPathComponent();
IconNodeClass newNode = new IconNodeClass(userObject);
DefaultTreeModel model = (DefaultTreeModel)getModel();
IconNodeClass oldParentNode = (IconNodeClass)userObject.getParent();
Object oldParent = oldParentNode.getUserObject();
Object newParent = node.getUserObject();
if(oldParent.equals(newParent)) {
model.insertNodeInto(newNode, node, 0);
if(oldParentNode != null) {
oldParentNode.remove(newNode);
model.reload(oldParentNode);
}

what happened next ?????

How to remove namespace link from the output XML

i have to remove 'xmlns:xdoxslt="http://www.oracle.com/XSL/Transform/java/oracle.apps.xdo.template.rtf.XSLTFunctions"' (namespace) from the output xml file which is generated from the BIP. I need my output XML file without that namespace link, this namespace link is coming for each element.
Anybody know how to do that please help.
output xml file
<?xml version="1.0" encoding="UTF-8" ?>
<Reports version="2.00">
<deliveryNote xmlns:xdoxslt="http://www.oracle.com/XSL/Transform/java/oracle.apps.xdo.template.rtf.XSLTFunctions">
<subjectId />
</deliveryNote>
<deliveredReports xmlns:xdoxslt="http://www.oracle.com/XSL/Transform/java/oracle.apps.xdo.template.rtf.XSLTFunctions">
<referDate>[Delivery note->H4]</referDate>
</deliveredReports>
<simpleReports xmlns:xdoxslt="http://www.oracle.com/XSL/Transform/java/oracle.apps.xdo.template.rtf.XSLTFunctions">
<numberOfReports>2</numberOfReports>
<nReport>
<reportName>Xyz</reportName>
<reportVersion>1.0</reportVersion>
<observations>
<numberOfObservations>15</numberOfObservations>
<columnObservation>
<y>9</y>
<rO>
<x>14</x>
<o>11</o>
<o>21</o>
<o>121</o>
</rO>
</columnObservation>
</observations>
</nReport>
</simpleReports>
</Reports>
my xslt file
<?xml version="1.0" encoding="ISO-8859-1"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:xdoxslt="http://www.oracle.com/XSL/Transform/java/oracle.apps.xdo.template.rtf.XSLTFunctions" >
<xsl:output method="xml" encoding="UTF-8"/>
<xsl:template match="/">
     <xsl:element name="Reports">
          <xsl:attribute name="version">2.00</xsl:attribute>
               <deliveryNote>
                    <subjectId></subjectId>
                    </deliveryNote>
               <deliveredReports>
                    <referDate>[Delivery note->H4]</referDate>
               </deliveredReports>
               <simpleReports>
                    <numberOfReports>2</numberOfReports>
                    <nReport>
                              <reportName>Xyz</reportName>
                              <reportVersion>1.0</reportVersion>
                                   <observations>
                                   <numberOfObservations>15</numberOfObservations>
                                   <columnObservation>
                                        <y>9</y>
                                        <rO>
                                             <x>14</x>
                                                  <xsl:for-each select="TEST_XML/LIST_R1/R1">
                                                       <o><xsl:value-of select="xdoxslt:lpad(COL1,10,' ')"/></o>
                                                  </xsl:for-each>
                                        </rO>
                                   </columnObservation>
                                   </observations>
                         </nReport>
                    </simpleReports>
          </xsl:element>
</xsl:template>
</xsl:stylesheet>

Please post the same in BI Publisher forum
BI Publisher
Thanks,
Vino

How to remove parent nodes in an output XML?

Hi! I'm having a problem as to removing a parent node in an xml output. The scenario goes like this, I have a source IDOC and two target External Definitions. When I have declared the two External Definitions, XI inserted a structure in the output xml as shown below:
Messages        (1..1)
          Message1       (1..1)
             Message1Header    (0..1)
          Message2       (1..1)
             Message2Header    (0..1)
Is there anyway to have an output that looks just like this (without their respective parent nodes)?
a.) Message1Header (0..1)
or
b.) Message2Header (0..1)
Please help
Regards,
Mark

Since you have two External Definitions and you are using both in on mapping hence your scenario becomes 1:N mapping scenario and this is the reason you are getting the additional nodes in your mapping.
so if your requirement is 1:N then whatever you are getting is correct, you can refer the below mentioned blog for help on this, But if you don't want the additonal nodes then you have to create TWO different mappings and used the external definitions seprately in each mapping.
/people/jin.shin/blog/2006/02/07/multi-mapping-without-bpm--yes-it146s-possible
I hope it helps...

How do I remove a node from Always on Availability Group in SQL 2012

Hello I was wondering if anyone could tell me to remove a node from an AOG group in SQL 2012. We currently have a two node Always on availability group and I need to replace one of the servers. My plan is to bring the
new server on to the group then remove the old server and I am having issues finding documentation on this. Could someone explain how to do this or if it is even possible.
Thanks

After the new server is added to the cluster and the AG, remove the old one by first
ALTER AVAILABILITY GROUP [YourAG]
REMOVE REPLICA ON N'OldServer';
Remove a Secondary Replica from an Availability Group
Then evict the old server from the cluster with the cluster administrator or
Remove-ClusterNode OldServer
Remember to verify the quorum configuration after adding the new server and removing the old server.
David
David http://blogs.msdn.com/b/dbrowne/

How to remove empty lines from xml files after removing nodes from document

<pre>
Hi
<b>i have xml document, which is shown below
after removing some nodes from the document ,i am getting empty lines in place of removed nodes,how to resolve this and get the proper xml document without any errors</b>
<?xml version="1.0" encoding="UTF-8" standalone="no"?>
<!DOCTYPE Message SYSTEM "TRD01.dtd">
<Message>
<Header>
<CounterPartyType>CLIENT</CounterPartyType>
<CreationTime>20134455</CreationTime>
<ErrorCode>363 </ErrorCode>
<ErrorEnterPriseId>N</ErrorEnterPriseId>
<ErrorStatus>1</ErrorStatus>
<ErrorSystemId>STL</ErrorSystemId>
<ErrorTimes>31</ErrorTimes>
<MessageType>T</MessageType>
<RecipientEnterpriseId>N</RecipientEnterpriseId>
<RecipentSystemId>EXM</RecipentSystemId>
<Remarks>REMARSK</Remarks>
<SenderEnterpriseId>N</SenderEnterpriseId>
<SenderSystemId>TR</SenderSystemId>
</Header>
</Message>
<ErrorCode>363 </ErrorCode>
<ErrorEnterPriseId>NIHK</ErrorEnterPriseId>
<ErrorStatus>1</ErrorStatus>
<ErrorSystemId>STL</ErrorSystemId>
<ErrorTimes>31</ErrorTimes>
XPathExpression expression5 = xpath.compile(xmlpath5);
Object result5 = expression5.evaluate(doc, XPathConstants.NODE);
Node node5 = (Node) result5;
node5.getParentNode().removeChild(node5);
XPathExpression expression6 = xpath.compile(xmlpath6);
Object result6 = expression6.evaluate(doc, XPathConstants.NODE);
Node node6=(Node) result6;
node6.getParentNode().removeChild(node6);
XPathExpression expression7 = xpath.compile(xmlpath7);
Object result7 = expression7.evaluate(doc, XPathConstants.NODE);
Node node7=(Node) result7;
node7.getParentNode().removeChild(node7);
doc.normalize();
doc.normalizeDocument();
TransformerFactory tf = TransformerFactory.newInstance();
Transformer t = tf.newTransformer();
t.setOutputProperty(OutputKeys.INDENT, "yes");
t.setOutputProperty("{http://xml.apache.org/xslt}indent-amount", "4");
t.setOutputProperty(OutputKeys.METHOD,"xml");
t.setOutputProperty(OutputKeys.ENCODING, "UTF-8");
the xml output i am getting is
<?xml version="1.0" encoding="UTF-8" standalone="no"?>
<Message>
<Header>
<CounterPartyType>CLIENT</CounterPartyType>
<CreationTime>20134455</CreationTime>
<MessageType>TRD01</MessageType>
<RecipientEnterpriseId>N</RecipientEnterpriseId>
<RecipentSystemId>STL</RecipentSystemId>
<Remarks>REMARSK</Remarks>
<SenderEnterpriseId>N</SenderEnterpriseId>
<SenderSystemId>T</SenderSystemId>
</Header>
</Message>
<b>could you please let me know how to avoid empty lines in the xml doucment output</b>
this is the method i am using to get the result
public void ValidateRecord(String xml){
try{
DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance();
DocumentBuilder db = factory.newDocumentBuilder();
//parse file into DOM
/*DOMParser parser = new DOMParser();
parser.setErrorStream(System.err);
parser.setValidationMode(DTD_validation);
parser.showWarnings(true);*/
System.out.println ("HI THIS xml is validation "+xml);
Resolver res = new Resolver();
db.setEntityResolver(res);
Document doc = db.parse(new InputSource(new StringReader(xml)));
XPathFactory xpf = XPathFactory.newInstance();
XPath xpath = xpf.newXPath();
// XPathExpression expression = xpath.compile("//A/B[C/E/text()=13]");
String xmlpath="/Message/Header/CounterPartyType/text()";
String xmlpath1="/Message/Header/RecipentSystemId/text()";
String xmlpath2="/Message/Header/ErrorSystemId/text()";
XPathExpression expression = xpath.compile(xmlpath);
XPathExpression expression1 = xpath.compile(xmlpath2);
Object result = expression.evaluate(doc, XPathConstants.NODE);
Object result1 = expression1.evaluate(doc, XPathConstants.NODE);
Node node = (Node) result;
Node node1 = (Node) result1;
System.out.println("the values of the string is " +node.getNodeValue());
System.out.println("the values of the string is " +node1.getNodeValue());
// for (int i = 0; i < nodes.getLength(); i++) {
//System.out.println(nodes.item(i).getNodeValue());
// CAHNGING THE RECEIPENT NODE
XPathExpression expression2 = xpath.compile(xmlpath1);
Object result2 = expression2.evaluate(doc, XPathConstants.NODE);
Node node2 = (Node) result2;
System.out.println(node2);
node2.setNodeValue(node1.getNodeValue());
System.out.println(node2);
//removing the nodes from document
String xmlpath3="/Message/Header/ErrorCode";
String xmlpath4="/Message/Header/ErrorEnterPriseId";
String xmlpath5="/Message/Header/ErrorStatus";
String xmlpath6="/Message/Header/ErrorSystemId";
String xmlpath7="/Message/Header/ErrorTimes";
XPathExpression expression3 = xpath.compile(xmlpath3);
Object result3 = expression3.evaluate(doc, XPathConstants.NODE);
Node node3 = (Node) result3;
node3.getParentNode().removeChild(node3);
XPathExpression expression4 = xpath.compile(xmlpath4);
Object result4 = expression4.evaluate(doc, XPathConstants.NODE);
Node node4 = (Node) result4;
System.out.println("node value");
System.out.println(node4.getParentNode().getNodeName());
node4.getParentNode().removeChild(node4);
XPathExpression expression5 = xpath.compile(xmlpath5);
Object result5 = expression5.evaluate(doc, XPathConstants.NODE);
Node node5 = (Node) result5;
node5.getParentNode().removeChild(node5);
XPathExpression expression6 = xpath.compile(xmlpath6);
Object result6 = expression6.evaluate(doc, XPathConstants.NODE);
Node node6=(Node) result6;
node6.getParentNode().removeChild(node6);
XPathExpression expression7 = xpath.compile(xmlpath7);
Object result7 = expression7.evaluate(doc, XPathConstants.NODE);
Node node7=(Node) result7;
node7.getParentNode().removeChild(node7);
// Node b13Node = (Node) expression.evaluate(doc, XPathConstants.NODE);
//b13Node.getParentNode().removeChild(b13Node);
doc.normalize();
doc.normalizeDocument();
TransformerFactory tf = TransformerFactory.newInstance();
Transformer t = tf.newTransformer();
t.setOutputProperty(OutputKeys.INDENT, "yes");
t.setOutputProperty("{http://xml.apache.org/xslt}indent-amount", "4");
t.setOutputProperty(OutputKeys.METHOD,"xml");
t.setOutputProperty(OutputKeys.ENCODING, "UTF-8");
t.transform(new DOMSource(doc), new StreamResult(System.out));
catch (Exception e) {
e.printStackTrace();
System.out.println(e.getMessage());
</pre>
Edited by: user12185243 on Apr 6, 2013 6:38 AM
Edited by: user12185243 on Apr 6, 2013 6:41 AM
Edited by: user12185243 on Apr 6, 2013 6:43 AM
Edited by: user12185243 on Apr 6, 2013 6:45 AM
Edited by: user12185243 on Apr 6, 2013 9:00 AM

either this way we can do this
1)
DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance();
<b> factory.setIgnoringElementContentWhitespace(true); </b>
DocumentBuilder db = factory.newDocumentBuilder();
or
2)
java.io.StringWriter sw = new java.io.StringWriter();
StreamResult sr = new StreamResult(sw);
t.transform(new DOMSource(doc), sr);
String xml1 = sw.toString().trim();
<b> xml1=xml1.replaceAll("\\s",""); </b>
System.out.println(xml1.trim());

How to remove all nodes (except root node)from a Jtree?

How to remove all nodes (except the root node)from a Jtree?

Either:
- remove all children of root.
- save the root node, throws away the tree model, build a new TreeModel with the saved root, set the new TreeModel in the JTree.
- implement your own TreeModel, which would support an emptyExceptRoot() method.
IMHO, using the DefautlTreeModel and DefaultMutableTreeNode does lead to all sorts of small problems when the app evolves, and implementing your own TreeNode and TreeModel is not that hard and much more efficient.

How can I remove child node from JTree???

Hi,
I would like to remove all the child node of my jtree. For instance I would like to remove the c, d, and e nodes. It's possible to remove all the child node or to remove by her name ("c", "d", and "e"). If yes what is the method that it permit to do.
A-----
|
b-------c
|
|--------d
|
---------e
I use the model : DefaultMutableTreeNode
Thanks

There are a couple of ways it can be done. If your tree uses DefaultTreeModel as its TreeModel, you can use removeNodeFromParent(). This will remove the node from its parent and effectively remove its children, too. All nodes removed will be garbage-collected if there are no other references to them.
If your tree model is not the default tree model, but still uses MutableTreeNode, you can use either remove() or removeFromParent() on the node itself, depending on whether you want to remove the node itself or one of its children.
On the other hand, your tree may use a model that simply "mirrors" another data structure, in which case you would have to remove the node from the other data structure and have it reflected in the model.

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