How to retrieve 2 values from a table in a LOV

Question

Hi
I'm pretty new to APEX. I try to retrieve two values from a table using a LOV. I have a table named DEBIT with then columns SITE, NAME and KEY
I want to display NAME to the user in a list. When the user select an item from the list, I want to retrieve the data of the SITE and KEY column of this item in order to launch an SQL command based on this two values.
How to retrieve thes two values whant the user chooses an item from the list ?
I apologize for my english, being french.
Regards.
Christian

Answer 1

Christian,
From what I understood about your requirement, you want a 'select list with submit' which displays "NAME" and based on the value selected, you want to get the corresponding values for "SITE" and "KEY" from the table.
<b>Step 1: Create a select list with submit, say P1_MYSELECT </b><br><br>
Use something like this in the dynamic list of values for the select list: <br>
SELECT NAME display_value, NAME return_value
FROM DEBIT<br><br>
<b>Step 2: Create a page process of type PL/SQL block. Also create 2 hidden items P1_KEY and P1_SITE. </b><br><br>
In the PL/sQL, write something like:
DECLARE
  v_key DEBIT.KEY%TYPE;
  v_site DEBIT.SITE%TYPE;
  CURSOR v_cur_myvals IS
          SELECT KEY, SITE
          FROM DEBIT
          WHERE NAME = :P1_MYSELECT;
BEGIN
  OPEN v_cur_myvals;
  LOOP
          FETCH v_cur_myvals
          INTO  v_key,v_site;
          EXIT WHEN v_cur_myvals%NOTFOUND;
:P1_KEY := v_key;   
:P1_SITE := v_site; 
  END LOOP;
  CLOSE v_cur_myvals;
END; <br><br>
Then you can use these values for whatever purpose you need to.
Hope this helps.