How to retrieve value from xml file

Question

hi all,
can somebody pls tell me how to retrieve value from xml file using SAXParser.
I want to retrieve value of only one tag and have to perform some validation with that value.
it's urgent .
pls help me out
thnx in adv.
ritu

Answer 1

hi shanu,
the pbm is solved, now i m able to access XXX no. in action class & i m able to validate it. The only thing which i want to know is it ok to declare static ArrayList as i have done in this code. i mean will it affect the performance or functionality of the system.
pls have a look at the following code snippet.
public class XMLValidator {
static ArrayList strXXX = new ArrayList();
public void validate(){
factory.setValidating(true);
parser = factory.newSAXParser();
//all factory code is here only
parser.parse(xmlURI, new XMLErrorHandler());     
public void setXXX(String pstrXXX){          
strUpn.add(pstrXXX);
public ArrayList getXXX(){
return strXXX;
class XMLErrorHandler extends DefaultHandler {
String tagName = "";
String tagValue = "";
String applicationRefNo = "";
String XXXValue ="";
String XXXNo = "";          
XMLValidator objXmlValidator = new XMLValidator();
public void startElement(String uri, String name, String qName, Attributes atts) {
tagName = qName;
public void characters(char ch[], int start, int length) {
if ("Reference".equals(tagName)) {
tagValue = new String(ch, start, length).trim();
if (tagValue.length() > 0) {
RefNo = new String(ch, start, length);
if ("XXX".equals(tagName)) {
XXXValue = new String(ch, start, length).trim();
if (XXXValue.length() > 0) {
XXXNo = new String(ch, start, length);
public void endElement(String uri, String localName, String qName) throws SAXException {                    
if(qName.equalsIgnoreCase("XXX")) {     
objXmlValidator.setXXX(XXXNo);
thnx & Regards,
ritu