How to run multiple java files concurrently using command line?

Hi,
I have to write a script to run multiple java files and c files concurrently. Say, A and C are java files and B is another binary executable file, I have to make sure they are run in the order A-B-C, then I was trying to run by using
java A & ./B & java C
But it turned out that B could run before A started... Is there any way that I can ensure that A runs before B, and B runs before C by using the command line?
Thanks a lot.

GKY wrote:
Sorry, I didn't make my question clear enough...
A has to give some output files that B needs to get started,Then B can start at any time--even before A--and just wait for those files to be written. For instance, A could write to a temp file, then rename it to the real name. However, if there are multiple files, and they all have to exist, even this won't necessarily work. There are other approaches that will though.
although writing the output takes very short time,Depends on when the OS decides to give A CPU time, what else is going on on that disk controller and/or network, etc.
B could still run before A finishes the writing, As it can if you sleep for 1, or 10, or 1,000,000 seconds before starting B.
if B can't find the info it wants, it fails to move on. That's why I need to make sure A starts before B.No, you need to make sure A's data is there before B tries to use that data.
Edited by: jverd on Jul 29, 2008 1:06 PM

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