How to run servlet in java webserver2.0
how to configure java webserver2.0 and how to run servlet in that
Hi Friend,
Try changing the servlet code to this and just tell wat happens after this.
and wat can you see on your Browser Screen.
import java.io.*;
import javax.servlet.*;
import javax.servlet.http.*;
import java.sql.*;
public class login extends HttpServlet {
public void doGet(HttpServletRequest req,HttpServletResponse res) throws ServletException,IOException
if (req.getParameter("t1") == null || req.getParameter("t2") == null)
out.println("Enter User Name And Password");
String uid=req.getParameter("t1");
String pwd=req.getParameter("t2");
res.setContentType("text/html");
PrintWriter out=res.getWriter();
out.println("<html>"); out.println("<head>");
out.println("<title>Login</title>"); out.println("</head>");
out.println("<body>");
try { Class.forName("sun.jdbc.odbc.JdbcOdbcDriver");
catch(ClassNotFoundException e)
out.println("<h3>"+e+"</h3>");
try{
Connection con=DriverManager.getConnection("jdbc:odbc:ms","scott","tiger");
PreparedStatement psm=con.prepareStatement("select * from reg where uid1=? and pwd=?");
psm.setString(1,uid);
psm.setString(1,pwd);
ResultSet rs=psm.executeQuery();
if(rs.next())
{ out.println("<html><head><title>WELCOME</title></head>");
out.println("<body><b><i>Hello user "+uid+"</b></i>");
out.println("</body></html>"); }
else
res.sendRedirect("http://localhost:8080/login.html");
} catch(SQLException e)
{ e.printStackTrace();}
rs.close();
con.close();
out.close();
After this try creating a odbc for oracle database at control panel with the name ms.
Please inform me wat happens after this and friend do give some information about wat kind of web-server are you using.Because calling of your servlets differs the way your configure your web-server and the default configurations differ from web-server to web-server.
Regards,
RAHUL
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0xee2fa2f8:class(sun.servlet.http.HttpServer)
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> run
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Thread-105[1]
We can use the list command to work out where jdb has stopped in the source.
Thread-105[1] list
41 throws ServletException, IOException
42 {
43 PrintWriter out;
44
45 => res.setContentType("text/html");
46 out = res.getWriter ();
47
48 out.println("<html>");
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Thread-105[1]
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Thread-105[1] cont
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Before:
exec $JAVA $THREADS $JITCOMPILER $COMPILER $MS $MX \
After:
exec $JAVA -debug $THREADS $JITCOMPILER
$COMPILER $MS $MX \
Here is how to remotely connect to the Java Web Server. The agent password is generated on the standard output from the Java Web Server so it can be redirected into a file
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jdb -host localhost -password <the agent password>
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method of this servlet, which is the main processing method of this servlet.
The Java Web Server standard output produces this message, which lets you proceed with the remote jdb session:
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Initializing jdb...
> stop in jdc.WebServer.PasswordServlet:service
Breakpoint set in jdc.WebServer.PasswordServlet.service
> stop
Current breakpoints set:
jdc.WebServer.PasswordServlet:111
The second stop lists the current breakpoints in this session and shows the line number where the breakpoint is set. You can now call the servlet through your HTML page. In
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<INPUT TYPE=TEXT SIZE=15 Name="user" Value="">
<INPUT TYPE=SUBMIT Name="Submit" Value="Submit">
</FORM>
You get control of the Java Web Server thread when the breakpoint is reached, and you can continue debugging using the same techniques as used in the Remote Debugging
section.
Breakpoint hit: jdc.WebServer.PasswordServlet.service
(PasswordServlet:111) webpageservice Handler[1] where
[1] jdc.WebServer.PasswordServlet.service
(PasswordServlet:111)
[2] javax.servlet.http.HttpServlet.service
(HttpServlet:588)
[3] com.sun.server.ServletState.callService
(ServletState:204)
[4] com.sun.server.ServletManager.callServletService
(ServletManager:940)
[5] com.sun.server.http.InvokerServlet.service
(InvokerServlet:101)
A common problem when using the Java WebServer and other servlet environments is that Exceptions are thrown but are caught and handled outside the scope of your servlet.
The catch command allows you to trap all these exceptions.
webpageservice Handler[1] catch java.io.IOException
webpageservice Handler[1]
Exception: java.io.FileNotFoundException
at com.sun.server.http.FileServlet.sendResponse(
FileServlet.java:153)
at com.sun.server.http.FileServlet.service(
FileServlet.java:114)
at com.sun.server.webserver.FileServlet.service(
FileServlet.java:202)
at javax.servlet.http.HttpServlet.service(
HttpServlet.java:588)
at com.sun.server.ServletManager.callServletService(
ServletManager.java:936)
at com.sun.server.webserver.HttpServiceHandler
.handleRequest(HttpServiceHandler.java:416)
at com.sun.server.webserver.HttpServiceHandler
.handleRequest(HttpServiceHandler.java:246)
at com.sun.server.HandlerThread.run(
HandlerThread.java:154)
This simple example was generated when the file was not found, but this technique can be used for problems with posted data. Remember to use cont to allow the web server
to proceed. To clear this trap use the ignore command.
webpageservice Handler[1] ignore java.io.IOException
webpageservice Handler[1] catch
webpageservice Handler[1]
I hope this will help you.
Thanks
Bakrudeen -
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