How to select all columns in a trigger?

Question

I add a "before delete" trigger on a table, in order to insert the records to a backup table before they are deleted.
but I cannot write like this : insert into t_backup select * from :old;
The table has more than 30 columns so I don't want to select them one by one, how can I select all columns?

Answer 1

Yes, it is possible by writing something like this :
where col1 = :old.col1; But it is not directly supported. First, we need a package to remember all the OLD records:.... and please see below link for complete code in action :
http://www.dbforums.com/oracle/925729-trigger-back-up-data.html
What I am doing here, just copying the code and replacing "emp" with "test" (The table name on which I am going to apply this using notepad find and replace):
SQL> select * from test_backup;
no rows selected
SQL> select * from test;
         A
         1
         2
         4
         5
SQL> select * from test_backup;
no rows selected
SQL>
create or replace package test_trg_pkg as
  type test_type is table of test%ROWTYPE index by binary_integer;
  test_tab test_type;
end;
create or replace trigger test_bds before delete on test
begin
  test_trg_pkg.test_tab.delete;
end;
create or replace trigger test_adr after delete on test
for each row
declare
  -- To allow us to select the old values
  pragma autonomous_transaction;
begin
  select *
  into   test_trg_pkg.test_tab(test_trg_pkg.test_tab.COUNT+1)
  from   test
  where  a = :old.a;  <----- Here you have to give your column name.
end;
create or replace trigger test_ads after delete on test
begin
  for i in 1..test_trg_pkg.test_tab.COUNT loop
    insert into test_backup values test_trg_pkg.test_tab(i);
  end loop;
end;
SQL> delete from test where a=1;
1 row deleted.
SQL> select * from test_backup;
         A
         1
SQL> delete from test where a=2;
1 row deleted.
SQL> select * from test_backup;
         A
         1
         2
SQL>Regards
Girish Sharma