How to split a string into tokens and iterate through the tokens

Guys,
I want to split a string like 'Value1#Value2' using the delimiter #.
I want the tokens to be populated in a array-like (or any other convenient structure) so that I can iterate through them in a stored procedure. (and not just print them out)
I got a function on this link,
http://www.orafaq.com/forum/t/11692/0/
which returns a VARRAY. Can anybody help me how to iterate over the VARRAY, or suggest a different alternative to the split please ?
Thanks.

RTFM: http://download-uk.oracle.com/docs/cd/B19306_01/appdev.102/b14261/collections.htm#sthref1146
or
http://www.oracle-base.com/articles/8i/Collections8i.php

Similar Messages

How to split this string into 4 sections to a max 35 characters

Hello,
Does anyone have an idea how I can acheive this please.
I have this string
Expense_Inv_8- ExpenseInv_7- Exp001- Expense_Inv_6- Expense_Inv_5- Expense_Inv_4- Expense_Inv_3- Expense_Inv_2- Expense_inv1
and I need to display them in sections seperated by ';' as explained below
Section 1 Section 2 Section 3 Section 4
Expense_Inv_8- ExpenseInv_7- Exp001;Expense_Inv_6- Expense_Inv_5;Expense_Inv_4- Expense_Inv_3;Expense_Inv_2;
need to split this string into 4 sections seperated by ';' and each section should be of no more than 35 characters, if null should end ;;;
Section 1, 35 Character ended by;
Section 2, broken off after Expense_Inv_5 because Expense_Inv_4 will take it over 35 chracters)
Section 3, should only take Expense_Inv_4- Expense_Inv_3, because adding Expense_Inv_2 will take it over 35
characters, each record in the string is seperated by '-'
Section 4, dispays the reminder of the string
regards
Ade

Hi,
Welcome to the forum!
Whenever you ask a question, it helps if you post a little sample data (CREATE TABLE and INSERT statements, relevant columns only) and the results you want from that data.
I think I understand the problemk well enough to attempt a solution, but if the query below isn't right, please post that information.
WITH     cntr     AS
     SELECT     LEVEL     AS n
     FROM     dual
     CONNECT BY     LEVEL     <= ( SELECT MAX (LENGTH (txt))
                         FROM    table_x
,     got_best_path     AS
     SELECT     id
     ,     txt
     ,     MAX ( SYS_CONNECT_BY_PATH ( TO_CHAR (c.n, '99')
                  ) AS best_path
     FROM     cntr     c
     JOIN     table_x     x     ON     c.n <= LENGTH (x.txt)
     START WITH     c.n     = 1
     CONNECT BY     c.n - PRIOR c.n     BETWEEN 1
                             AND      :section_length
          AND     x.id          = PRIOR     x.id
          AND     SUBSTR ( x.txt
                             , c.n
                             , 1
                             )     = '-'
     AND     LEVEL          <= :section_cnt
     GROUP BY id
     ,            txt
,     got_pos     AS
     SELECT     id
     ,     REPLACE ( txt
               ) || ';'                         AS txt
     ,     best_path
     ,     TO_NUMBER (REGEXP_SUBSTR (best_path, '[0-9]+', 1, 2))     AS pos_2
     ,     TO_NUMBER (REGEXP_SUBSTR (best_path, '[0-9]+', 1, 3))     AS pos_3
     ,     TO_NUMBER (REGEXP_SUBSTR (best_path, '[0-9]+', 1, 4))     AS pos_4
     FROM     got_best_path
SELECT id
,     SUBSTR (txt,     1    , NVL ( pos_2         , :section_length))     AS section_1
,     SUBSTR (txt, pos_2 + 1, NVL ((pos_3 - pos_2), :section_length))     AS section_2
,     SUBSTR (txt, pos_3 + 1, NVL ((pos_4 - pos_3), :section_length))     AS section_3
,     SUBSTR (txt, pos_4 + 1,                        :section_length )     AS section_4
FROM     got_pos
;As written, this requires SQL*Plus 9 (or higher). You can have multiple versions or SQL*Plus on the same client, if you really need to keep the older version.
:section_length is the maximum length of each section (35, as you stated the problem).
:section_cnt is the number of sections. In the query above, this is 4. If you change it, you not only have to change the bind variable, but you have to change the hard-coded SELECT clauses of the main query and the last sub-query (that is, got_pos).
MODEL or PL/SQL would probably be better ways to solve this problem.

I have taken pictures of items that are linked to a database that I am building. How can I bypass importing into iPhoto and simply downloading the images as "files" not "photos" so I can access them with my database? thanx.

I have taken pictures with both my Sony camera and my iPhone of items that are linked to a database that I am building, as well as my website. How can I bypass importing the images into iPhoto and simply downloading the images as "files" not "photos" so I can access them with my database? thanx.

If your Sony has a removable memory card you can use a card reader to copy the image files from to a folder on your Desktop and then move them anywhere you'd like.
Since the iPhone doesn't have a removable memory card you can try using Image Capture to see if you can manually upload the files to a folder on the Desktop.
If you have to import the photos, which are image files, into iPhoto you can then export them out of iPhoto to the Desktop and go from there to your database. Just because they are in iPhoto doesn't prevent you from using them elsewhere.
OT

Easy Question: How to split concatenated string into multiple rows?

Hi folks,
this might be an easy question.
How can I split a concatenated string into multiple rows using SQL query?
INPUT:
select 'AAA,BBB,CC,DDDD' as data from dualDelimiter = ','
Expected output:
data
AAA
BBB
CCC
DDDDI'm looking for something kind of "an opposite for 'sys_connect_by_path'" function.
Thanks,
Tomas

Here is the SUBSTR/INSTR version of the solution:
SQL> WITH test_data AS
2 (
3          SELECT ',' || 'AAA,BBB,CC,DDDD' || ',' AS DATA FROM DUAL
4 )
5 SELECT SUBSTR
6          (
7                  DATA
8          ,       INSTR
9                  (
10                          DATA
11                  ,       ','
12                  ,       1
13                  ,       LEVEL
14                  ) + 1
15          ,       INSTR
16                  (
17                          DATA
18                  ,       ','
19                  ,       1
20                  ,       LEVEL + 1
21                  ) -
22                  INSTR
23                  (
24                          DATA
25                  ,       ','
26                  ,       1
27                  ,       LEVEL
28                  ) - 1
29          )       AS NEW_STRING
30 FROM    test_data
31 CONNECT BY LEVEL <= LENGTH(REGEXP_REPLACE(DATA,'[^,]','')) - 1
32 /
NEW_STRING
AAA
BBB
CC
DDDD

How to split a string into alfa-numerics and numerics ?

Thru I/O Assistant.vi I queried a GPIB frequency synthesizer and get a string " FRq99999.999999Hz " ( this is a micro Herz synthesizer and the query shows the correct value ).
The "9"'s are alfanumerics as well as the " FRq " and the " Hz ".
Thru a string indicator I can see this complete value on the front panel.
So far so good.
But now :
1.
How could I separate the numerics ( in string format ) out of this string and convert them into numerics in order to have them displayed in some numerics graph form ?
2.
How could I delete the " FRq " and the " Hz " out of the string, so that the " 9 " 's remain and could be converted into numerics ?
This result wil be the same as my question #1 but now ther
e will be no A/N remainder.
Thanks for any help.

reteb wrote:
> Thru I/O Assistant.vi I queried a GPIB frequency synthesizer and get a
> string " FRq99999.999999Hz " ( this is a micro Herz synthesizer and
> the query shows the correct value ).
> The "9"'s are alfanumerics as well as the " FRq " and the " Hz ".
>
> 2.
> How could I delete the " FRq " and the " Hz " out of the string, so
> that the " 9 " 's remain and could be converted into numerics ?
> This result wil be the same as my question #1 but now there will be no
> A/N remainder.
Scan From String with a format string of "%.;%[^0-9]%f"
Explanation:
%.; : use point as decimal comma
%[0-9] : scan all characters not equal to 0 up to 9
%f : scan for floating point number using the decimal comma
indicated at the beginning.
Rolf Kal
bermatter
Rolf Kalbermatter
CIT Engineering Netherlands
a division of Test & Measurement Solutions

How to split a string into columns

Hello to all ,
Having a strings like this, where pipe(|) is his delimiter
10:00 | x1 | 2 | RO | P | Con ausilio | y1
10:10 | x2 | 1 | RO | | | y2
10:20 |x3 | 3 | | | | y3
10:30 |x4 | 3 | RO | N | Con aiuto | y4
10:40 |x5 | 1 | RO | | | y5
how can I break it up into columns, for example, the first char(before first pipe) insert in first variable,
then, after first pipe, second characters in a other column ans so on
col1 := '10:00';
col2 := 'x1';
col3 := '2';
col4:= 'RO';
col5 := 'P';
col6 := ' Con ausilio ';
col7 := 'y1';
col1 := '10:10';
col2 := 'x2';
.. and so on
thanks in advance

Hi,
check this:
WITH mydata(txt) AS
   SELECT '10:00 | x1 | 2 | RO | P | Con ausilio | y1' FROM DUAL UNION ALL
   SELECT '10:10 | x2 | 1 | RO | | | y2'              FROM DUAL UNION ALL
   SELECT '10:20 |x3 | 3 | | | | y3'                 FROM DUAL UNION ALL
   SELECT '10:30 |x4 | 3 | RO | N | Con aiuto | y4'    FROM DUAL UNION ALL
   SELECT '10:40 |x5 | 1 | RO | | | y5'               FROM DUAL
SELECT TRIM(REGEXP_SUBSTR(txt,'[^|]+',1,1)) col1
     , TRIM(REGEXP_SUBSTR(txt,'[^|]+',1,2)) col2
     , TRIM(REGEXP_SUBSTR(txt,'[^|]+',1,3)) col3
     , TRIM(REGEXP_SUBSTR(txt,'[^|]+',1,4)) col4
     , TRIM(REGEXP_SUBSTR(txt,'[^|]+',1,5)) col5
     , TRIM(REGEXP_SUBSTR(txt,'[^|]+',1,6)) col6
     , TRIM(REGEXP_SUBSTR(txt,'[^|]+',1,7)) col7
FROM mydata;
COL1   COL2   COL3   COL4   COL5   COL6            COL7
10:00 x1     2      RO     P      Con ausilio     y1
10:10 x2     1      RO                            y2
10:20 x3     3                                    y3
10:30 x4     3      RO     N      Con aiuto       y4
10:40 x5     1      RO                            y5    Regards.
Al

How to split audio tracks into left and right channels as we do in FCP or Avid needed for dubbing?

We are recording in two languages, one in left and the other in right channel. However, in Adobe Premiere Pro we are not able to split the track when we take up for rought cut. Both the tracks are found mixed. Pl help. Since we need to maintian the split track to dubb into other languages.

You need to do this before adding the footage to the sequence:
Select the clip (or multiple clips) in the bin
Menu > Clip > Modify > Audio Channels (Shift G)
Change 'Number of Audio Tracks' to 2
Change 'Channel Format' to Mono
Dismiss the info message.
When you place the clip in a sequence it will now drop L and R into separate tracks (assuming your sequence allows that audio model).

How to split a string using IndexOf?

How would you split a string using indexOf and not using the .split method?
Any help is appreciated :D
Message was edited by:
billiejoe

would it be better to use the first or the second?
int indexOf(int ch)
Returns the index within this string of the first occurrence of the specified character.
int indexOf(int ch, int fromIndex)
Returns the index within this string of the first occurrence of the specified character, starting the search at the specified index.
I think the second would be helpful. so how do i read it?

How to split this string(char1)char2(char3)char4 into (char1)char2 , .. etc

how to split this string (char1)char2(char3)char4 into (char1)char2 , (char3)char4?
String[] result = "(char1)char2(char3)char4".split("\\(");I want :
result[0] = "(char1)char2" and
result[0] = "(char3)char4"
acutally char1,char2,char3, char4 ... is in the form of the below.
(any charactors except round brace)any charactors except round brace(any charactors except round brace)any charactors except round brace
I prefer String.split and Pattern.compile().split.
Edited by: iamjhkang on Feb 5, 2009 3:37 PM
Edited by: iamjhkang on Feb 5, 2009 3:41 PM

iamjhkang wrote:
especially on
?= and ?<
Thanks.The following:
(?=...) // positive look ahead
(?!...) // negative look ahead
(?<=...) // positive look behind
(?<!...) // negative look behindare all "look-arounds". See: [http://www.regular-expressions.info/lookaround.html]

OR ('|') in regular expressions (e.g. split a String into lines)

Which match gets used when you use OR ('|') to specify multiple possible matches in a regex, and there are multiple matches among the supplied patterns? The first one (in the order written) which matches? Or the one which matches the most characters?
To make this concrete, suppose that you want to split a String into lines, where the line delimiters are the same as the [line terminators used by Java regex|http://java.sun.com/javase/6/docs/api/java/util/regex/Pattern.html#lt] :
     A newline (line feed) character ('\n'),
     A carriage-return character followed immediately by a newline character ("\r\n"),
     A standalone carriage-return character ('\r'),
     A next-line character ('\u0085'),
     A line-separator character ('\u2028'), or
     A paragraph-separator character ('\u2029)
This problem has [been considered before|http://forums.sun.com/thread.jspa?forumID=4&threadID=464846] .
If we ignore the idiotic microsoft two char \r\n sequence, then no problem; the Java code would be:
String[] lines = s.split("[\\n\\r\\u0085\\u2028\\u2029]");How do we add support for \r\n? If we try
String[] lines = s.split("[\\n\\r\\u0085\\u2028\\u2029]|\\r\\n");which pattern of the compound (OR) regex gets used if both match? The
[\\n\\r\\u0085\\u2028\\u2029]or the
\\r\\n?
For instance, if the above code is called when
s = "a\r\nb";and if the first pattern
[\\n\\r\\u0085\\u2028\\u2029]is used for the match when the \r is encountered, then the tokens will be
"a", "", "b"
because there is an empty String between the \r and following \n. On the other hand, if the rule is use the pattern which matches the most characters, then the
\\r\\n
pattern will match that entire \r\n and the tokens will be
"a", "b"
which is what you want.
On my particular box, using jdk 1.6.0_17, if I run this code
String s = "a\r\nb";
String[] lines = s.split("[\\n\\r\\u0085\\u2028\\u2029]|\\r\\n");
System.out.print(lines.length + " lines: ");
for (String line : lines) System.out.print(" \"" + line + "\"");
System.out.println();
if (true) return;the answer that I get is
3 lines: "a" "" "b"So it seems like the first listed pattern is used, if it matches.
Therefore, to get the desired behavior, it seems like I should use
"\\r\\n|[\\n\\r\\u0085\\u2028\\u2029]"instead as the pattern, since that will ensure that the 2 char sequence is first tried for matches. Indeed, if change the above code to use this pattern, it generates the desired output
2 lines: "a" "b"But what has me worried is that I cannot find any documentation concerning this "first pattern of an OR" rule. This means that maybe the Java regex engine could change in the future, which is worrisome.
The only bulletproof way that I know of to do line splitting is the complicated regex
"(?:(?<=\\r)\\n)" + "|" + "(?:\\r(?!\\n))" + "|" + "(?:\\r\\n)" + "|" + "\\u0085" + "|" + "\\u2028" + "|" + "\\u2029"Here, I use negative lookbehind and lookahead in the first two patterns to guarantee that they never match on the end or start of a \r\n, but only on isolated \n and \r chars. Thus, no matter which order the patterns above are applied by the regex engine, it will work correctly. I also used non-capturing groups
(?:X)
to avoid memory wastage (since I am only interested in grouping, and not capturing).
Is the above complicated regex the only reliable way to do line splitting?

bbatman wrote:
Which match gets used when you use OR ('|') to specify multiple possible matches in a regex, and there are multiple matches among the supplied patterns? The first one (in the order written) which matches? Or the one which matches the most characters?
The longest match wins, normally. Except for alternation (or) as can be read from the innocent sentence
The Pattern engine performs traditional NFA-based matching with ordered alternation as occurs in Perl 5.
in the javadocs. More information can be found in Friedl's book, the relevant page of which google books shows at
[http://books.google.de/books?id=GX3w_18-JegC&pg=PA175&lpg=PA175&dq=regular+expression+%22ordered+alternation%22&source=bl&ots=PHqgNmlnM-&sig=OcDjANZKl0VpJY0igVxkQ3LXplg&hl=de&ei=Dcg7S43NIcSi_AbX-83EDQ&sa=X&oi=book_result&ct=result&resnum=1&ved=0CA0Q6AEwAA#v=onepage&q=&f=false|http://books.google.de/books?id=GX3w_18-JegC&pg=PA175&lpg=PA175&dq=regular+expression+%22ordered+alternation%22&source=bl&ots=PHqgNmlnM-&sig=OcDjANZKl0VpJY0igVxkQ3LXplg&hl=de&ei=Dcg7S43NIcSi_AbX-83EDQ&sa=X&oi=book_result&ct=result&resnum=1&ved=0CA0Q6AEwAA#v=onepage&q=&f=false]
If this link does not survive, search google for
regular expression "ordered alternation"
My first hit went right into Friedl's book.
Harald.

Crystal report - how to split a field into more fields

Hello,
I`m new to Crystal reports and I`ve got a trouble. I have field which contains an address - street, city, zip code. The example is:
STEHLIKOVA 977 165 00 PRAHA 620 - SUCHDOL 165 00.
What I need to achieve is to split this string into three separated fields. I`ve trouhg a couple of forums but haven`t been able to find a proper answer. The problem is that the addresses differ so I can`t use an absolute defining of a start position. Looking at the DB (HEXA code) the parts in the string are divided by two dots:
STEHLIKOVA 977..165 00 PRAHA 620 - SUCHDOL..165 00
I`ve been able to work out this solution:
stringVar array x := split({cparty.STREET_ADD},"..");
Local numberVar i;
Local stringVar outputString := "";
For i:=1 to Count(x) do
outputString := outputString + x[i] + Chr(10)
outputString;
It splits the string into three rows:
STEHLIKOVA 977
165 00 PRAHA 620 - SUCHDOL
165 00
And I don`t know how to find the end of each row so to be able to separate the strings and report them as three different fields.
Would be anyone so kind and help me out with this?
Thank you.
Petr

Hi
Actually using a for loop is not necessary here. All you need to do is to add several formula fields: one for street, one for city and one for zipcode. In @street field you add formula:
stringVar array x := split({cparty.STREET_ADD},Chr(13));
x[1];
Then you drag such formula field to details section of your report and watch preview to check if everything looks alright. Repeat for every formula field that you'd like see in your report.
In @city you add almost identical formula but you change index, i. e. instead of x[1] you need to use x[2]. Then for @zip x[3].
You may need to check if your address has all three parts - for example if you want to use formula in the second part of your address field you may need check first if there are at least two parts after split:
stringVar array := split({cparty.STREET_ADD},Chr(13));
numbervar c;
c := count(x);
if 2 <= c then
x[c];
Var 'c' is used to store the number of elements in array after split. Then I'd like to check if the part (second) actually exists. So I try to check if number of part that I want to refer to is not bigger than the number of elements in array after split (here stored in var 'c').
Actually the code presented above is not enough since you have no guarantee that you'll always get address structured in the very same way. For example in demo PL database I have zip code and city in the same row after split with Chr(13) as delimiter.
You'll need to experiment or ask someone to prepare correctly structured data coming from B1 to your report.
Kind regards,
Radek

How to split a string which contents 2byte character

hi all,
i wanna split a string into substrings five bits a time
the problem is the original string may contents 2byte characters
and if the split bit is a 2byte character we only take the first four bits.
the 2byte character is used for the next five bits.
so could you tell how carry is out.
thanks in advance

hi all,
i wanna split a string into substrings five bits a time
the problem is the original string may contents 2byte characters
and if the split bit is a 2byte character we only take the first four bits.
the 2byte character is used for the next five bits.
so could you tell how carry is out.
thanks in advance

How to split a string with a space in between?

Hi ABAP Guru's,
Can you please help me out? How can I split a string into two which has a space in between?
For example: lets suppose the string is 'LA CA USA'. How can I split this string? I have to dynamically determine the number of characters before the space therefore I cannot use number constant such as 2 or 3.
With best regards,
Ketan

Hi
Try like this
DATA : opbal TYPE p DECIMALS 2 VALUE 0.
    SELECT * FROM zs_mkpf_mseg
                    into corresponding fields of table it_opbal
                    WHERE werks = itmat-werks
                    AND matnr = itmat-matnr
                    AND budat = s_budat-low.
* sort it_opbal by budat.
loop at it_opbal.
read table it_opbal.
      IF it_opbal-shkzg = 'S'.
        opbal = opbal + it_opbal-menge.
      ELSEIF it_opbal-shkzg = 'H'.
        opbal = opbal + it_opbal-menge * -1.
      ENDIF.
endloop.
    append opbal TO itab-opbal.
ENDFORM.                    " opbal_data
you can also use thi s
DATA: NAMES(30)    TYPE C VALUE 'Charly, John , Peter',
      NAMES2       TYPE STRING,
      ONE(10)      TYPE C,
      TWO(10)      TYPE C,
      THREE        TYPE STRING,
      FOUR(4)      TYPE C VALUE 'FOUR',
      DELIMITER(2) VALUE ','.
SPLIT NAMES AT DELIMITER INTO ONE TWO.
*     ONE contains 'Charly' and TWO contains 'John , Pet'.
*     SY-SUBRC is 4, because TWO was not large enough to
*     accommodate the whole of the remaining string
SPLIT NAMES AT ',' INTO ONE TWO THREE.
*     ONE contains 'Charly', TWO contains ' John',
*     THREE contains ' Peter'.
SPLIT NAMES AT ', ' INTO ONE THREE TWO.
*     ONE contains 'Charly', THREE contains 'John',
*     TWO contains 'Peter'.
CONCATENATE NAMES '' INTO NAMES2 SEPARATED BY SPACE.
SPLIT NAMES2 AT DELIMITER INTO ONE TWO THREE FOUR.
*     ONE contains 'Charly', TWO contains 'John',
*     THREE contains 'Peter ', FOUR is empty.
SPLIT NAMES2 AT DELIMITER INTO ONE FOUR THREE.
*     ONE contains 'Charly', FOUR contains 'John',
*     THREE contains 'Peter', SY-SUBRC is 4, since
*     FOUR was not large enough (spaces are significant
*     characters!)
Reward all helpfull answers
Regards
Pavan

How to split one page into different frames in ADF?

Hi,
Can any one please guide me how to split a jspx into different frames.
i.e., left frame contains <af:panelSideBar> which contains multiple <af:commandMenuItem> s. And whenver we click on the one <af:commandMenuItem>, it has to show the corresponing page inside center frame in this page itself. Is it possible in ADF? Which component we need to use?
Can anyone guide me on this?
Thanks in advance,
Regards,
Suresh Kethireddy

You can use a combination of the ADF Faces 10.1.3 components like:
af:panelPage
af:panelSideBar
af:panelHorizontal
af:panelGroup
to organize the screen layout, but it is not the interactive splitter that the 11g product provides.
You can all all the 10.1.3 ADF Faces Components here:
http://www.oracle.com/technology/products/jdev/htdocs/partners/addins/exchange/jsf/doc/tagdoc/core/imageIndex.html

Splitting a string into 4 equal parts

Hi All,
I have a string with maximum no of characters as 100,
I want to split this string into 4 equal parts.
Any help will be appreciated.
Regards

Hi Rajeev,
Use this sample code
class SplitString {
       public static void main(String[] arguments) {
          StringTokenizer ex1, ex2; // Declare StringTokenizer Objects
          int count = 0;
          String strOne = "one two three      four   five";
          ex1 = new StringTokenizer(strOne); //Split on Space (default)
          while (ex1.hasMoreTokens()) {
              count++;
              wdComponentAPI.getMessageManager().reportSuccess("Token " + count + " is" +    ex1.nextToken() );
          count = 0; // Reset counter
          String strTwo = "item one,item two,item three,item four"; // Comma Separated
          ex2 = new StringTokenizer(strTwo, ","); //Split on comma
          while (ex2.hasMoreTokens()) {
              count++;
              wdComponentAPI.getMessageManager().reportSuccess("Token " + count + " is "+ ex2.nextToken() );
Thanks
Anup
Edited by: Anup Bharti on Oct 27, 2008 12:36 PM

How to split a string into tokens and iterate through the tokens

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