How to test if a number is prime?

Hi, I'm doing an exercise. I'm iterating through numbers from 2 to 100 (since 1 is not a prime number) and I need to test if the current number is a prime, if it is print it out. But I can't figure out the condition, how to test if a number is prime? So far I got this, but it prints all subsequent numbers, which is now obvious to me, but how to test for primes?
public class Main {
    public static void main(String[] args) {
        for (int i = 2; i <= 100; i++) {
            //Test if a number is a prime, if it is print it
            // The (i + 1) is because I want to divide i by any other number, so I thought i + 1
            if (((i % i) == 0) && ((i % 1) == 0) && ((i % (i + 1)) > 0)) {
                System.out.println(i);
}

Aardenon wrote:
I understand your point. But it seems unsafe to assume a number from which the checks are unnecessary. That could lead to an error. I'm sure it is mathematically provable somehow, but I'm not that good in Math. I mean to write a safe (and optimized) version of the code, I would still have to go through all uneven numbers and 2.Nope. In fact, for an optimized version, definitely not; however, I wouldn't worry too much about optimization at the moment.
One little tip I remember from school, back in the dark ages, is that all prime numbers other than 2 and 3 have the form 6k ± 1. That is NOT to say that all such numbers are prime, but it does eliminate a lot of the ones you need to check.
You might also want to check out the [url http://en.wikipedia.org/wiki/Prime_number#Verifying_primality]Wikipedia page on prime numbers; it's very good.
Winston

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