If i know the extract strucute how to know the DS name

Hi All,
If i know the extract structure name how to find the DS name?
Regards
Kiran

If it is for LO extractors we can identify the datasource based on the extract structure.
say if the extract structure name is MC11VA0HDR , 11 will be the application component, VA is the event for salesorder , HDR gives the level of the data it is extracting .So in this case the data source name will be 2LIS_11_VAHDR.
For MC12VC0ITM the data source will be 2LIS_12_VCITM(12 is the application for delivery ,VC the event for delivery)
But for generic and other extractors it is not possible to know the datasource name by seeing the extractstructure. We will have all the datasources information in the roosurce table. Here we can check the datasource which is having that extract structure.

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Import From Folder: How to Extract the File Name in a Custom Column.

Hello All
Here´s what we´re trying to do:
We have a folder with csv files named like this:
Sales_2013-02-05.csv
Sales_2013-02-04.csv
Sales_2013-02-03.csv
Sales_2013-02-02.csv
Sales_2013-02-01.csv
And in the csv files there are the sales columns but not the date column.
So we want to extract the date from the file name.
I´ve tried entering = Source[Name] in a custom column, but it adds a "LIST" link, and on a click on expand, it adds ALL file names from the folder in each row, instead of just the needed one.
If we could get the proper file name in each row (from where they got extracted), we could split the column and get the date from there. But I don´t know how put the filename there properly.
Can you help?

This isn't entirely straightforward, but it's definitely possible. What you need to do is to apply all of your transforms to each individual file instead of the combined files. I do that as follows:
1) Use Folder.Files as generated by the GUI to look at the list of my files.
2) Pick one file and do all the transformations to it that I want to apply to all of the files. Sometimes, this just amounts to letting the autodetection figure out the column names and types.
3) Go into the advanced editor and edit my code so that the transformations from step 2 are applied to all files. This involves creating a new function and then applying that function to the content in each row.
4) Expand the tables created in step 3.
As an example, I have some files with names that match the ones you suggested. After steps 1 + 2, my query looks like the following:
let
    Source = Folder.Files("d:\testdata\files"),
    #"d:\testdata\files\_Sales_2013-02-01 csv" = Source{[#"Folder Path"="d:\testdata\files\",Name="Sales_2013-02-01.csv"]}[Content],
    #"Imported CSV" = Csv.Document(#"d:\testdata\files\_Sales_2013-02-01 csv",null,",",null,1252),
    #"First Row as Header" = Table.PromoteHeaders(#"Imported CSV"),
    #"Changed Type" = Table.TransformColumnTypes(#"First Row as Header",{{"One", Int64.Type}, {"Two", type text}, {"Three", type text}})
in
    #"Changed Type"
For step 3, I need to take steps 3-5 of my query and convert them into a function. As a check, I can apply that function to the same file that I chose in step 2. The result looks like this:
let
    Source = Folder.Files("d:\testdata\files"),
    Loader = (file) =>
        let
            #"Imported CSV" = Csv.Document(file,null,",",null,1252),
            #"First Row as Header" = Table.PromoteHeaders(#"Imported CSV"),
            #"Changed Type" = Table.TransformColumnTypes(#"First Row as Header",{{"One", Int64.Type}, {"Two", type text}, {"Three", type text}})
        in
            #"Changed Type",
    #"d:\testdata\files\_Sales_2013-02-01 csv" = Source{[#"Folder Path"="d:\testdata\files\",Name="Sales_2013-02-01.csv"]}[Content],
    Loaded = Loader(#"d:\testdata\files\_Sales_2013-02-01 csv")
in
    Loaded
Now I apply the same function to all of the rows, transforming the existing "Content" column into a new value:
let
    Source = Folder.Files("d:\testdata\files"),
    Loader = (file) =>
        let
            #"Imported CSV" = Csv.Document(file,null,",",null,1252),
            #"First Row as Header" = Table.PromoteHeaders(#"Imported CSV"),
            #"Changed Type" = Table.TransformColumnTypes(#"First Row as Header",{{"One", Int64.Type}, {"Two", type text}, {"Three", type text}})
        in
            #"Changed Type",
    Transformed = Table.TransformColumns(Source, {"Content", Loader})
in
    Transformed
Finally, I need to expand out the columns in the table, which I can do by clicking on the expand icon next to the Content column header. The resulting query looks like this:
let
    Source = Folder.Files("d:\testdata\files"),
    Loader = (file) =>
        let
            #"Imported CSV" = Csv.Document(file,null,",",null,1252),
            #"First Row as Header" = Table.PromoteHeaders(#"Imported CSV"),
            #"Changed Type" = Table.TransformColumnTypes(#"First Row as Header",{{"One", Int64.Type}, {"Two", type text}, {"Three", type text}})
        in
            #"Changed Type",
    Transformed = Table.TransformColumns(Source, {"Content", Loader}),
    #"Expand Content" = Table.ExpandTableColumn(Transformed, "Content", {"One", "Two", "Three"}, {"Content.One", "Content.Two", "Content.Three"})
in
    #"Expand Content"
From here, you should be able to get to what you want.

Does anyone know how to use pages so you can export pdfs from the internet and automatically drag words from the document into the file name of the pdf (i.e., author, title of a scientific paper)

Does anyone know how to use pages so you can export pdfs from the internet and automatically drag words from the document into the file name of the pdf (i.e., author, title of a scientific paper). For example, if I am downloading a paper by smith called "Surgery" that was published in 2002, it will automatically set the file name in the download to smith- surgery 2002. I have heard pages is smart enough to do this.
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Pages can export only its own documents. They may be exported as PDF, MS Word, RTF or Text files.
Pages can import (ie. Open a file as, or Insert a file into, a Pages document) documents in several formats, but won't rename the document as you describe. Documents that can be Opened (eg. Text, AppleWorks 6 WP, MS Word files) are converted to Pages documents, and retain their original names, with .pages replacing the original file extension. Files that can be Inserted (generally .jpg, .pdf and other image files) become part of the existing Pages file and lose their names.
It may be possible, using AppleScript, to extract the text you want and to Save a Pages file using that text as the filename, but that would depend in part on being able to identify which text is wanted and which is not.
How will the script determine where the author's name begins and where it ends?
How will the script recognize the beginning and of the title, an decide how much of the title to use in the filename?
How will the script recognize the year of publication?
For papers published in a specific journal, with a strict format for placing each of these pieces on information, or containing the needed information as searchable meta data in the file, this might be possible. But it would require knowledge of the structure of these files, and would probably handle only papers published in a specific journal or set of journals.
Outside my field of knowledge, but there are some talented scripters around here who might want to take a closer look.
Best of luck.
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How to extract the element name of an XML Document

This is how my xml file looks like:
<?xml version="1.0" encoding="UTF-8" ?>
- <nsiData>
- <instance timestamp="2011-05-25 19:01:00">
<AECI>47.00</AECI>
<EEI>-553.00</EEI>
<EES>-91.00</EES>
<EKPC>-22.00</EKPC>
<LGEE>-140.00</LGEE>
<MHEB>-1376.00</MHEB>
<MISO>-4725.00</MISO>
<MOWR>55.00</MOWR>
<ONT>-872.00</ONT>
<OVEC>-144.00</OVEC>
<PJM>-1438.00</PJM>
<SPA>-55.00</SPA>
<SPC>20.00</SPC>
<SWPP>69.00</SWPP>
<TVA>-69.00</TVA>
<WAUE>-158.00</WAUE>
</instance>
- <instance timestamp="2011-05-25 19:02:00">
<AECI>47.00</AECI>
<EEI>-555.00</EEI>
<EES>-91.00</EES>
<EKPC>-22.00</EKPC>
<LGEE>-148.00</LGEE>
<MHEB>-1375.00</MHEB>
<MISO>-4709.00</MISO>
<MOWR>55.00</MOWR>
<ONT>-871.00</ONT>
<OVEC>-144.00</OVEC>
<PJM>-1426.00</PJM>
<SPA>-55.00</SPA>
<SPC>20.00</SPC>
<SWPP>82.00</SWPP>
<TVA>-69.00</TVA>
<WAUE>-158.00</WAUE>
</instance>
</nsiData>
I want to extract the element name and the element value from this file. I was trying to do it this way:
SELECT datetime,
loc.aeci_value,
loc.eei_value
FROM temp_xmltype txml,
XMLTABLE ('/nsiData' PASSING xmldata) misolmp,
XMLTABLE ('/nsiData/instance' PASSING misolmp.object_value
COLUMNS
datetime VARCHAR2(100) PATH '/instance/@timestamp') misodt,
XMLTABLE ('/nsiData/instance' PASSING misolmp.object_value
COLUMNS
aeci_value VARCHAR2(100) PATH '/instance/AECI',
eei_value VARCHAR2(100) PATH '/instance/EEI') loc
WHERE txml.feed_id = 127
But doing it this way does not get me AECI as a column value. Is there any way to get the element name as a column value.
I am on 11gR2

The SQL statement you wrote returns 4 rows and there is only two AECI values in there. The corrected version of what you wrote should really be
SELECT loc.datetime,
       loc.aeci_value,
       loc.eei_value
FROM temp_xmltype txml,
       XMLTABLE ('/nsiData/instance' PASSING txml.xmldata
                 COLUMNS
                 datetime   VARCHAR2(100) PATH '@timestamp',
                 aeci_value VARCHAR2(100) PATH 'AECI',
                 eei_value VARCHAR2(100) PATH 'EEI') loc
WHERE txml.feed_id = 127;If you know the element name and want it returned as a column name, why not just hard code it in the SQL statement, such as
SELECT loc.datetime,
       'AECI' as AECI,
       loc.aeci_value,
       'EEI' AS EEI,
       loc.eei_value
FROM temp_xmltype txml,
       XMLTABLE ('/nsiData/instance' PASSING txml.xmldata
                 COLUMNS
                 datetime   VARCHAR2(100) PATH '@timestamp',
                 aeci_value VARCHAR2(100) PATH 'AECI',
                 eei_value VARCHAR2(100) PATH 'EEI') loc
WHERE txml.feed_id = 127;I suspect you are really looking for something like {message:id=9535532}
Note: See the FAQ (under your sign-in name) for how to use the code tag to format code as shown above.

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Thanks
Message was edited by: Kevin Smith

hi kevin
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If i know the extract strucute how to know the DS name

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