Indesign CS3: How to get the current document name?

Hallo!
How do I get the name of the current document loaded in Indesign?
Thanks,
Alois Blaimer

...Plese Ignore the last post... docRef is the UIDRef of the document. Plese consider the following code IDocument *docFrom = Utils<ILayoutUIUtils>()->GetFrontDocument(); if (docFrom == NULL ) break; UIDRef docRef = GetUIDRef(docFrom )); InterfacePtr<IDocument> iDocument (docRef, IID_IDOCUMENT); if(iDocument == nil) break; PMString docName; iDocument->GetName(docName);

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How to get the current schema name

Hi,
Can anybody please tell me how to get the current schema name, there is some inbuilt function for this,but i am not getting that. Please help me.
Thanks
Jogesh

ok folks, I found the answer at Tom's as usual.
http://asktom.oracle.com/tkyte/who_called_me/index.html
I rewrote it into a function for kicks. just pass the results of DBMS_UTILITY.FORMAT_CALL_STACK to this function and you will get back the owner of the code making the call as well some extra goodies like the name of the code and the type of code depending on the parameter. This ignores the AUTHID CURRENT_USER issues which muddles the schemaid. Quick question, does the average user always have access to DBMS_UTILITY.FORMAT_CALL_STACK or does this get locked down on some systems?
cheers,
paul
create or replace
FUNCTION SELF_EXAM (
   p_call_stack VARCHAR2,
   p_type VARCHAR2 DEFAULT 'SCHEMA'
) RETURN VARCHAR2
AS
   str_stack   VARCHAR2(4000);
   int_n       PLS_INTEGER;
   str_line    VARCHAR2(255);
   found_stack BOOLEAN DEFAULT FALSE;
   int_cnt     PLS_INTEGER := 0;
   str_caller VARCHAR2(30);
   str_name    VARCHAR2(30);
   str_owner   VARCHAR2(30);
   str_type    VARCHAR2(30);
BEGIN
   str_stack := p_call_stack;
   -- Loop through each line of the call stack
   LOOP
     int_n := INSTR( str_stack, chr(10) );
     EXIT WHEN int_cnt = 3 OR int_n IS NULL OR int_n = 0;
     -- get the line
     str_line := SUBSTR( str_stack, 1, int_n - 1 );
     -- remove the line from the stack str
     str_stack := substr( str_stack, int_n + 1 );
     IF NOT found_stack
     THEN
        IF str_line like '%handle%number%name%'
        THEN
           found_stack := TRUE;
        END IF;
     ELSE
        int_cnt := int_cnt + 1;
         -- cnt = 1 is ME
         -- cnt = 2 is MY Caller
         -- cnt = 3 is Their Caller
         IF int_cnt = 1
         THEN
            str_line := SUBSTR( str_line, 22 );
            dbms_output.put_line('->' || str_line);
            IF str_line LIKE 'pr%'
            THEN
               int_n := LENGTH('procedure ');
            ELSIF str_line LIKE 'fun%'
            THEN
               int_n := LENGTH('function ');
            ELSIF str_line LIKE 'package body%'
            THEN
               int_n := LENGTH('package body ');
            ELSIF str_line LIKE 'pack%'
            THEN
               int_n := LENGTH('package ');
            ELSIF str_line LIKE 'anonymous%'
            THEN
               int_n := LENGTH('anonymous block ');
            ELSE
               int_n := null;
            END IF;
            IF int_n IS NOT NULL
            THEN
               str_type := LTRIM(RTRIM(UPPER(SUBSTR( str_line, 1, int_n - 1 ))));
             ELSE
               str_type := 'TRIGGER';
             END IF;
             str_line := SUBSTR( str_line, NVL(int_n,1) );
             int_n     := INSTR( str_line, '.' );
             str_owner := LTRIM(RTRIM(SUBSTR( str_line, 1, int_n - 1 )));
             str_name := LTRIM(RTRIM(SUBSTR( str_line, int_n + 1 )));
          END IF;
       END IF;
   END LOOP;
   IF UPPER(p_type) = 'NAME'
   THEN
      RETURN str_name;
   ELSIF UPPER(p_type) = 'SCHEMA.NAME'
   OR    UPPER(p_type) = 'OWNER.NAME'
   THEN
      RETURN str_owner || '.' || str_name;
   ELSIF UPPER(p_type) = 'TYPE'
   THEN
      RETURN str_type;
   ELSE
      RETURN str_owner;
   END IF;
END SELF_EXAM;

How to get the current function name in java

How to get the current function name in java.
In c it is done as
printf("%s",__func__);
Thanx in advance.

j0o wrote:
System.out.println("Class Name: " + new Exception().getStackTrace()[0].getClassName() +
"/n Method Name : " + new Exception().getStackTrace()[0].getMethodName() +
"/n Line number : " + new Exception().getStackTrace()[0].getLineNumber());
I pointed the OP at this approach yesterday in one of his multi-posts. I still have not been given my Dukes!

How to get the current class name in static method?

Hi,
I'd like to get the current class name in a static method. This class is intended to be extended. So I would expect that the subclass need not to override this method and at the runtime, the method can get the subclass name.
getClass() doesn't work, because it is not a static method.
I would suggest Java to make getClass() static. It makes sense.
But in the mean time, does anybody give an idea to work around it?
Thank you,
Bill

Why not create an instance in a static method and use getClass() of the instance?
public class Test {
public static Class getClassName() {
return new Test().getClass();

Indesign CS3: How to get the number of the current layer?

Hallo!
How to get the number of the current layer in a page?
Thanks,
Alois Blaimer

InterfacePtr<ILayerList> layerList(documentUIDRef, UseDefaultIID()); int32 layerCount = layerList->GetCount(); To findout layer name use IDocumentLayer* documentLayer = layerList->QueryLayer(layerIndex); PMString layer=documentLayer->GetName();

How to get the current user name of the host who is occupying a specific VM?

I'm developing a winform app with c# code to manage Hyper-V. I need to remind someone if he/she would take a VM which has already been occupied by others.
Is there any powershell cmd or WMI interface to get the current user of a specific VM?
Thanks!

Hiya,
from cmd there are quser(Query user) and qwinsta(Query Session)
which should give you that. Don't know how you can incoorperate that in C#, but that should give you something to work with :)
https://technet.microsoft.com/en-us/library/cc785434.aspx
https://technet.microsoft.com/en-us/library/cc788125.aspx

Uix frameset - how to get the current frame name?

I have a frameset with 3 different frames in it. a top, center and bottom.
There is a menu in the top frame that changes the contents of the center or bottom frame.
How can I get the value of the frame name for the current frame into a bound value like a httpsession or page?
for example if I change the center frame to "listadmin.uix" how can I load a bound value with the frames new source?
Is there a way to pass javascript to a boundvalue? I could get the frames new properties from javascript

In Jdev 9.0.3 you could do something like this:<frameBorderLayout>
<start>
 <frame name="sideFrame">
 <boundAttribute name="source">
 <ctrl:pageURL name="sideFramePage">
 <ctrl:properties>
 <ctrl:property key="currentFrame"
 value="sideFrame"/>
 </
 </
 </
 </
</
</then in startFramePage.uix you can access the current frame name by doing:<styledText data:text="currentFrame@ctrl:page"/>

How to get the current user name in Provider hosted app using appOnlyAccessToken

Hi,
Please help me, how to get the HostWeb UserName in Provider Hosted App
i have Provider hosted App, and Anonymous Authentication is enabled on AppWeb, using appOnlyAccessToken
Below code does not return current user who Log in in hostweb, it is returning
SharePoint App (app@sharepoint)
Web web = clientContext.Web;
clientContext.Load(web);
clientContext.ExecuteQuery();
clientContext.Load(web.CurrentUser);
clientContext.ExecuteQuery();
clientContext.Web.CurrentUser.LoginName;
Below code gives a blank name when Anonymous Authentication is enabled, if Anonymous Authentication is disabled
app prompts for credentials
HttpContext.Current.User.Identity.Name
Thanks
Ram

Hi,
Since you are using a provider Hosted app if you want to get the current logged in name than do not use AppOnlyAccessToken else use AccessToken which is App + user Context AccessToken.
then
Web web = clientContext.Web;
clientContext.Load(web);
clientContext.ExecuteQuery();
clientContext.Load(web.CurrentUser);
clientContext.ExecuteQuery();
clientContext.Web.CurrentUser.LoginName;will return proper user Name.
HttpContext.Current.User.Identity.Name will never return the user as this object is related to IIS server of your App Server not sharepoint.you should set this as Anonymous in case of provider hosted app.you can download the below sample which uses the AccessToken which has user name in it.https://code.msdn.microsoft.com/Working-provider-hosted-8fdf2d95
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Indesign CS3: How to get the UID of the selected object?

Hello,
How can I get the UID of the selected object in an document?
Thanks,
Alois Blaimer

Hello!
I do not get it. Please give me some more hints.
I only want to know if the selected object is a square and then the UID of the selected square.
Thanks,
Alois Blaimer

How to get the current view name is displaying?

Hi Experts,
I have a requirement that I have to know the current view is displaying. At the header of the page, there is a component (BTCHIST) which is fix and common for the all others. It has a button called Finish. When the user clicks on it, it has a different behavior depending on the current view.
Does anyone know any method in order to get this information? I searched up in CRM_UI_FRAME, however I didnu2019t find anything.
Regards,
André

Hi,
You need to redefine the method IF_BSP_WD_HISTORY_STATE_DESCR~GET_STATE_DESCRIPTION of the controller class to change the view description. Unfortunately, the effort is huge and we cannot do it dynamically and needs to be done for each view in question.
Regards
Prasenjit

How to get the Current Document Library View Name from Code - C#

Hi,
I have a requirement where i have a doc lib - doclib and two view view1 and view2.The columns vary for the two views.
Now a user can select and of the two views and do a particular operation.
I need to programatically find out which view the user is currently at.Now i know that just by picking the URL i can understand if its doclib/view1.aspx or doclib/view2.aspx. But this is not possible as my scenario
because of an architecture limitation of my project.
Is there any way to find out the view like libraray.currentview or using spview.
I need to make so column updates based on the view selected.
Please help.

Try below code as you in the SharePoint context.
Guid siteId = SPContext.Current.Site.ID;
Guid webId = SPContext.Current.Web.ID;
SPSecurity.RunWithElevatedPrivileges(delegate()
    using (SPSite site = new SPSite(siteId))
        using (SPWeb web = site.OpenWeb(webId))
            // Your code here
Hope this will helps you
Senthilrajan Kaliyaperumal

How to get the current use name edited the page

Hi All,
I have a table which contains set of users,
namely
A
B
C
When the user A changes a particular pages and in that page i have a page item named LAST REVIEWED BY its Display only column and i need to Auto Populated the user Name A
How to do this ?
Thanks & Regards
Srikkanth.M

Put a Trigger on your Table which fills the column using
NEW.LAST_REVIEWED_BY := v('APP_USER');
...brgds,
Peter
Blog: http://www.oracle-and-apex.com
ApexLib: http://apexlib.oracleapex.info
BuilderPlugin: http://builderplugin.oracleapex.info
Work: http://www.click-click.at

How to get the current EAR name in a servlet ?

Greetings,
In a servlet, I need to retrive the EAR name. Using the ServerRuntimeMBean I can retrieve the list of the applications via the ApplicationsRuntime attribute. But I don't find any CurrentApplicationRuntime attribute or something similar. Many thanks in advance for any help.
Kind regards,
Nicolas

j0o wrote:
System.out.println("Class Name: " + new Exception().getStackTrace()[0].getClassName() +
"/n Method Name : " + new Exception().getStackTrace()[0].getMethodName() +
"/n Line number : " + new Exception().getStackTrace()[0].getLineNumber());
I pointed the OP at this approach yesterday in one of his multi-posts. I still have not been given my Dukes!

How to get the Current User on the UI page?

All,
Could you please let me know how to get the Current user on the UI input page , i need to display the current user ID when some one clicks the submit button, i want o get the current user to display in the javascript alert box.
Edited by: 951930 on Oct 24, 2012 12:21 PM

lucky,
my schema has already defined for
<user mapField="USER_ID" default="%CurrentUser"/>
and in my UI page
<td oraLabel="user"></td><td oraField="user" id="userId" ></td>
and my javascript
function showUserId () {
var curUser = document.getElementById('userId').value;
alert(curUser);
and i have called this function on my submit button, but i am not able to get Current Logged User ID value to show in the alert nor able to show the current logged user on the UI page.
my requirement is on custom UI page i need to show Current Logged User in one corner of the page and also need to show the same user in alert when he submits the button.
Appreciate for the help.
Edited by: 951930 on Oct 25, 2012 8:42 AM
Edited by: 951930 on Oct 25, 2012 9:06 AM

How to get the current slide Index or Id?

I can get the selected slide of presentation use blow method.
Office.context.document.getSelectedDataAsync(Office.CoercionType.SlideRange, function (asyncResult) {
if (asyncResult.status == Office.AsyncResultStatus.Failed) {
write('Action failed. Error: ' + asyncResult.error.message);
else {
write('Selected slides: ' + JSON.stringify(asyncResult.value.slides));
But, How can I get the executor slide?

Hi,
>> How to get the current slide Index or Id?
In my option, when you select a slide, it change to current slide. So, you could use the getSelectedDataAsync method to get the current slide, and then get the index or id by using the Slice object. You could refer the link below for Slice Object.
# Slice.index property (JavaScript API for Office)https://msdn.microsoft.com/EN-US/library/office/jj715285.aspx?f=255&MSPPError=-2147217396
Some key code as below:
<script>
function getText() {
Office.context.document.getSelectedDataAsync(Office.CoercionType.SlideRange,
{ valueFormat: "unformatted", filterType: "all" },
function (asyncResult) {
var error = asyncResult.error;
if (asyncResult.status === Office.AsyncResultStatus.Failed) {
write(error.name + ": " + error.message);
else {
// Get selected data.
var dataValue = asyncResult.value;
write('Selected data is ' + dataValue.slides[0].index);
// Function that writes to a div with id='message' on the page.
function write(message) {
document.getElementById('message').innerText += message;
</script>
>> How can I get the executor slide?
What do you mean by this? Is this a new issue which is different from the above issue? If so, I will recommend you post a new thread for this issue and share us more information about this.
Best Regards,
Edward
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Indesign CS3: How to get the current document name?

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