Joining three tables to get totals on three columns.

Question

hi gurus,
i have spent hours and hours to get the desired result with this join query. 98% of the query bring results according to my expectations but for some reasons few results are duplicating. let me give you the structure of my tables than my query and than what i expect it to bring. here we go;
There are three tables
*1. SENDER*
Name Null? Type
SNAME VARCHAR2(50)
SPHONE1 NOT NULL VARCHAR2(15)
SPHONE2 VARCHAR2(15)
SPHONE3 VARCHAR2(15)
SCITY VARCHAR2(25)
SREMARKS VARCHAR2(200)
IDENTIFICATION VARCHAR2(20)
ADD1 VARCHAR2(30)
ADD2 VARCHAR2(30)
*2. TRANSACTION*
Name Null? Type
T_ID NOT NULL NUMBER
SPHONE1 VARCHAR2(15)
R_ID NUMBER
RB_ID VARCHAR2(10)
TRANSFER_TO VARCHAR2(25)
TDATE DATE
SOURCE VARCHAR2(20)
CURR VARCHAR2(10)
PAID VARCHAR2(10)
MOP VARCHAR2(10)
DOLLAR NUMBER
RATE NUMBER(5,2)
RUPPEE NUMBER
TREM1 VARCHAR2(200)
TREM2 VARCHAR2(100)
PPAYMENT VARCHAR2(10)
PROMISE VARCHAR2(50)
BALANCE NUMBER
DOLLAR2 NUMBER
*3. PAYMENTS*
Name Null? Type
PAYMENT_ID NOT NULL NUMBER
PDATE DATE
SPHONE1 VARCHAR2(15)
AMT_PAID NUMBER
BALANCE NUMBER
T_ID NUMBER
QUERY_
select a.sname, a.sphone1, nvl(sum(b.dollar),0) ORD, nvl(sum(b.dollar2),0) ADV,
nvl(sum(c.amt_paid),0) Paid
from sender a, transaction b, payments c
where a.sphone1 = b.sphone1
and b.t_id = c.t_id(+)
and b.paid in ('N','B')
group by a.sname, a.sphone1
order by 1
HERE IS THE RESULT OF THIS QUERY:_
SNAME SPHONE1 ORD ADV PAID
Muhammad Atif Ishtiaq 778 889 7195 2150 635 45
BRIEF DESCRIPTION:*
We have sender info in SENDER table, when they place order it goes to TRANSACTION table and when they pay it goes into PAYMENTS. some times they make payments in installment of a single order. which i record them in payments with their T_ID (Transaction ID) and this is the problem what i research until now. many customers place multiple orders over a period of time but dont pay and some times pay the orders in installment. i just want to present the whole story in one single row, as i mentioned above under query result. in this example the actual ORD suppose to be $2050 instead and ADV $605. PAID is OK.
SQL> select t_id, dollar, dollar2 from transaction where paid = 'B' and sphone1 = '778 889 7195';
T_ID DOLLAR DOLLAR2
18274 450
18278 1000 500
18263 100 30
18265 100
18266 100
18268 100 25
18269 200 50
SQL> select t_id, amt_paid from payments
where t_id in (select t_id from transaction
where paid = 'B' and sphone1 = '778 889 7195')
T_ID AMT_PAID
18263 20
18263 25
AND in the end i would like to calculate balance of the columns ((ORD+ADV) - (PAID))
Any help would be appreciated.
best regards.
NOTE: i am running oracle 8 and developer 6i

Answer 1

try this:
WITH TRANSACTION AS (select 18274 t_id, 450 dollar, NULL dollar2, '778 889 7195' sphone1 FROM DUAL
                     UNION ALL
                     select 18278 t_id, 1000 dollar, 500 dollar2, '778 889 7195' sphone1 FROM DUAL
                     UNION ALL
                     select 18263 t_id, 100 dollar, 30 dollar2, '778 889 7195' sphone1 FROM DUAL
                     UNION ALL
                     select 18265 t_id, 100 dollar, NULL dollar2, '778 889 7195' sphone1 FROM DUAL
                     UNION ALL
                     select 18266 t_id, 100 dollar, NULL dollar2, '778 889 7195' sphone1 FROM DUAL
                     UNION ALL
                     select 18268 t_id, 100 dollar, 25 dollar2, '778 889 7195' sphone1 FROM DUAL
                     UNION ALL
                     select 18269 t_id, 200 dollar, 50 dollar2, '778 889 7195' sphone1 FROM DUAL
     PAYMENTS AS    (select 18263 t_id, 20 amt_paid FROM DUAL
                     UNION ALL
                     select 18263 t_id, 25 amt_paid FROM DUAL
     SENDER AS      (SELECT 'Muhammad Atif Ishtiaq' SNAME, '778 889 7195' SPHONE1 FROM DUAL
select a.sname,
       a.sphone1,
       nvl(ORD,0) ORD,
       nvl(ADV,0) ADV,
       nvl(amt_paid,0) Paid
  from sender a,
       (SELECT sphone1,
               sum(dollar) ord,
               sum(dollar2) adv
          from transaction b
        GROUP BY sphone1) b,
       (SELECT sphone1,
               SUM(amt_paid) amt_paid
          FROM payments p,
               transaction t
         where p.t_id=t.t_id
         GROUP BY sphone1) c
where a.sphone1 = b.sphone1
and b.sphone1=c.sphone1(+);