Match Regular Expression Function input string format

Hi,
I am new to labview and was having some difficulties using the Match Regular Experssion Function.
I am using labview to communicate with a sensor. I have installed the NI device driver to do so. The output of my sensor is in the format,
X20
R40 P20 A123. The numbers in this case are arbitrary. I am trying to use Match Regular Expression Function to display and perform mathematical operations on the numbers. I am having difficulties formatting the input string on the Match Regular Expression Function. Could you please give me some tips on how to format the example I provided.
Thank

MoAgha wrote:
Hi,
I am new to labview and was having some difficulties using the Match Regular Experssion Function.
I am using labview to communicate with a sensor. I have installed the NI device driver to do so. The output of my sensor is in the format,
X20
R40 P20 A123. The numbers in this case are arbitrary. I am trying to use Match Regular Expression Function to display and perform mathematical operations on the numbers. I am having difficulties formatting the input string on the Match Regular Expression Function. Could you please give me some tips on how to format the example I provided.
Thank
Here is a way to do it if the format is constant (X R P A followed by a positive integer number).
Ben64

Similar Messages

Match Regular Expression Function

Hi guys, using this pattern I got this error:
-4600 Error occurred during regular expression match.
I have attached the VI.
can you help me?thank you
Solved!
Go to Solution.
Attachments:
Untitled 2.vi ‏30 KB

inuyasha84 wrote:
hi well i want to save (create) a file and do a check to see if the new file that I want to create already exist or not. so the idea was to see if the path of the new file is equal to the old path
Why not just use "Check if file or folder exists"? (File I/O -> Adv File Funcs)
Cameron
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"Match Regular Expression" and "Match Pattern" vi's behave differently

Hi,
I have a simple string matching need and by experimenting found that the "Match Regular Expression" and "Match Pattern" vi's behave somewhat differently. I'd assume that the regular expression inputs on both would behave the same. A difference I've discovered is that the "|" character (the "vertical bar" character, commonly used as an "or" operator) is recognized as such in the Match Regular Expression vi, but not in the Match Pattern vi (where it is taken literally). Furthermore, I cannot find any documentation in Help (on-line or in LabVIEW) about the "|" character usage in regular expressions. Is this documented anywhere?
For example, suppose I want to match any of the following 4 words: "The" or "quick" or "brown" or "fox". The regular expression "The|quick|brown|fox" (without the quotes) works for the Match Regular Expression vi but not the Match Pattern vi. Below is a picture of the block diagram and the front panel results:
The Help says that the Match Regular Expression vi performs somewhat slower than the Match Pattern vi, so I started with the latter. But since it doesn't work for me, I'll use the former. But does anyone have any idea of the speed difference? I'd assume it is negligible in such a simple example.
Thanks!
Solved!
Go to Solution.

Yep-
You hit a point that's frustrated me a time or two as well (and incidentally, caused some hair-pulling that I can ill afford)
The hint is in the help file:
for Match regular expression "The Match Regular Expression function gives you more options for matching
strings but performs more slowly than the Match Pattern function....Use regular
expressions in this function to refine searches....
Characters to Find
Regular Expression
VOLTS
VOLTS
A plus sign or a minus sign
[+-]
A sequence of one or more digits
[0-9]+
Zero or more spaces
\s* or * (that is, a space followed by an asterisk)
One or more spaces, tabs, new lines, or carriage returns
[\t \r \n \s]+
One or more characters other than digits
[^0-9]+
The word Level only if it
appears at the beginning of the string
^Level
The word Volts only if it
appears at the end of the string
Volts$
The longest string within parentheses
The first string within parentheses but not containing any
parentheses within it
$[^()]*$
A left bracket
A right bracket
cat, cag, cot, cog, dat, dag, dot, and dag
[cd][ao][tg]
cat or dog
cat|dog
dog, cat
dog, cat cat dog,cat
cat cat dog, and so on
((cat )*dog)
One or more of the letter a
followed by a space and the same number of the letter a, that is, a a, aa aa, aaa aaa, and so
on
(a+) \1
For Match Pattern "This function is similar to the Search and Replace
Pattern VI. The Match Pattern function gives you fewer options for matching
strings but performs more quickly than the Match Regular Expression
function. For example, the Match Pattern function does not support the
parenthesis or vertical bar (|) characters.
Characters to Find
Regular Expression
VOLTS
VOLTS
All uppercase and lowercase versions of volts, that is, VOLTS, Volts, volts, and so on
[Vv][Oo][Ll][Tt][Ss]
A space, a plus sign, or a minus sign
[+-]
A sequence of one or more digits
[0-9]+
Zero or more spaces
\s* or * (that is, a space followed by an asterisk)
One or more spaces, tabs, new lines, or carriage returns
[\t \r \n \s]+
One or more characters other than digits
[~0-9]+
The word Level only if it begins
at the offset position in the string
^Level
The word Volts only if it
appears at the end of the string
Volts$
The longest string within parentheses
The longest string within parentheses but not containing any
parentheses within it
([~()]*)
A left bracket
A right bracket
cat, dog, cot, dot, cog, and so on.
[cd][ao][tg]
Frustrating- but still managable.
Jeff

Parse Mac Address with match regular expression

Hi Everyone,
I have a problem with the Match Regular Expression function,
I am trying to parse the response two a arp -a 192.168.0.15 request in order to extract MAC address of this remote IP, I used the following RegEx: ^([0-9a-fA-F]{2}[:-]){5}([0-9a-fA-F]{2})$
I am wondering why do I need to do a string subset first to extract only the MAC Address part. Isn't Match Regular Expression function capable of recognizing the RegEx directly in the middle of a string?
I only works when I extract the right tring subset as in the picture bellow.
Thanks for your answers.
Solved!
Go to Solution.
Attachments:
Mac Address.JPG ‏40 KB

Get rid of the "^" in the beginning of your regular expression. You are instructing it to find the pattern at the beginning of the string.
Mark Yedinak
"Does anyone know where the love of God goes when the waves turn the minutes to hours?"
Wreck of the Edmund Fitzgerald - Gordon Lightfoot

Multi-line String - Match Regular Expression

I am trying to figure out the format of a regular expression in order to pull select lines out of a multi-line string and populate those lines as individual elements of a string array while using Match Regular Expression. The overall length of the multi-line string can vary as well as the text contained within the string. The string can contain letters, numbers, and special characters. I have attached an example VI. Within the example VI I only want to return the lines beginning with "Device #" into the array. The number of lines beginning with "Device #" can vary but I want to capture them all.
Or is there a better function to use instead of Match Regular Expression that will give me the desired outcome?
Solved!
Go to Solution.
Attachments:
MultiLine Regular Expression.vi ‏22 KB

aaronb wrote:
I am trying to figure out the format of a regular expression in order to pull select lines out of a multi-line string and populate those lines as individual elements of a string array while using Match Regular Expression. The overall length of the multi-line string can vary as well as the text contained within the string. The string can contain letters, numbers, and special characters. I have attached an example VI. Within the example VI I only want to return the lines beginning with "Device #" into the array. The number of lines beginning with "Device #" can vary but I want to capture them all.
Or is there a better function to use instead of Match Regular Expression that will give me the desired outcome?
Match Regular Expression works well for this.
Ben64

Match Regular Expression not returning submatches.

I am having an issue with Match Regular Expression not returning the appropriate number of submatches. My string is as follows:
DATAM 995000 1.75 0.007 -67.47 24.493 99.072
The spaces are tabs and the length is not fixed so simple string manipulation is out of the question. The regular expression I was trying is as follows:
(?<=\t)[0-9\.\-]*(?=(\t|$))
It successfully returns Whole Match as the first number but no submatches are returned. I've tried simpler expressions which work in Matlab and EditPad Pro such as [0-9.-]* but never got the same answer in Labview.
What is going on?

Here is an image of the VI. The top portion is the input from our Licor 7000. The bottom portion is the bit of code I'm having problems with.
Attachments:
matchregularexpression.jpg ‏336 KB

Matching Regular Expressions in OBPM 10GR3

Hi all,
How do I match Regular expressions like" Wait For Response" in Strings using OBPM?
Any idea?
Is there any exact syntax?
Because I tried doing this:-
for( int i=0; i < testGroup.length(); i++)
if(testGroup.reason.match(regexp : "Wait For Response"))
logMessage("--Test Group Matched--");
But it does not work..
Any idea?

String myVar = "has matching_char_set";
if ( myVar.match(regexp : '/matching_char_set/') ) {
logMessage("matched...yep");
Try like this ..should work.
Rgds,
Biltu

Match Regular Expression does not match what Match Pattern does

I have read through a lot of posts about how Match Pattern does not match what Match Regular Expression will due to not processing some characters.
However, I found a problem with the other way. A simple Reg-Ex that works in Match Pattern but not Match Regular Expression.
What I have here is just an example. I want to use Match Regular Expression so I can specify some sub-matches.
The reg-ex is for: one or more non-numeric characters, a space, one or more numeric characters. At the start of the string.
How can I get this working in Match Regular Expression? I am working in LabVIEW 2010f2 32 bit. Here is the code snippet and the results:
Rob
Solved!
Go to Solution.

Robert Cole wrote:
I think I prefer the ~ for negation since ^ is also used for beginning of the string. But we work with what we have.
Let me offer you a tip and perhaps defend the honor of the regex a little bit. One of my favorite features of regexes is the ability to specify character classes (and their negation). One of the reasons I have to think about the ~ versus ^ is that I rarely use ^ in a regex alternative.
Some examples:
[0-9] = \d (digit)
[^0-9] = \D (not a digit)
The equivalent regex for your case is: \D+ \d+

Remove regular expression from a string

Hello,
I have a string like this
@1test;'"{input+
Please help me to remove special characters from the string.

A: remove regular expression from a string

Hi Krishna,
DATA : str TYPE STRING VALUE '@1test;"{}]input+',
            char,
            length TYPE i,
            index TYPE i.
length = STRLEN( str ).
WHILE length > index.
char = str+index(1).
WRITE char.
if char CA '+-*/!`@#$%^&()_=[]{};'.               " Add/Remove here to include numbers
    REPLACE ALL OCCURRENCES OF char in str WITH ''.
    REPLACE ALL OCCURRENCES OF '"' in str WITH ''. " characters "{}[] are not comparable
    REPLACE ALL OCCURRENCES OF '{' in str WITH ''.
    REPLACE ALL OCCURRENCES OF '}' in str WITH ''.
    REPLACE ALL OCCURRENCES OF '[' in str WITH ''.
    REPLACE ALL OCCURRENCES OF ']' in str WITH ''.
    length = STRLEN( str ).
    ENDIF.
add 1 to index.
ENDWHILE.
WRITE str.
Add or remove special char from '+-*/!`@#$%^&()_=[]{};' in if part as per your requirement.
Hope it meets your requirement.
Do not forget to mark helpful/correct if ma answer is useful .
Thanks,
Karthik

Question about match regular expression

Colleagues,
Very stupid question. I would like to get substring between "..." symbols. For example, string 02 July from Explosion occurred on "02 July", 2008.
How to do this with single Match Regular Expression?
For example such expression ".*" will give me "02 July":
But I would like to get it without " symbols!
I tried this "[~"]*" and this "[~"].*", then read this and this , and all without success... But I'm sure it should be possible. Can you help me?
Andrey.
PS
This regular expression should give exactly the same output as following construction:

I'm only using 7.0 now, but you can do this with Scan from String...
%[^"]"%[^"]"%[^"]
Message Edited by Phillip Brooks on 07-02-2008 02:47 PM
Now is the right time to use %^<%Y-%m-%dT%H:%M:%S%3uZ>T
If you don't hate time zones, you're not a real programmer.
"You are what you don't automate"
Inplaceness is synonymous with insidiousness
Attachments:
NotPCRE.png ‏20 KB

Regular Expression functions not supported in Interactive report filters ??

I'm using APEX 4.0.2 and I'm trying to create a row filter in an interactive report which uses regexp_instr and regexp_replace functions and I'm getting the message:
Invalid filter expression. regexp_instr
The code runs fine in SQL Workshop
select cytogenetics from z_patient
where regexp_instr(regexp_replace(cytogenetics,'(\,+|\"+|\s)',''),'(^46XX$|^46XY$|^46XX\[..\]$|^46XY\[..\]$)')=1
CYTOGENETICS
"46,XX [20]"
"46,XY[20]"
"46,XX"
"46,XY[20]"
"46,XY[30]"
"46,XY[26]"
"46,XY [33]"
"46,XX[32]
etc...
my filter is just the where clause above i.e.
regexp_instr(regexp_replace(cytogenetics,'(\,+|\"+|\s)',''),'(^46XX$|^46XY$|^46XX\[..\]$|^46XY\[..\]$)')=1
*Are regular expression functions just not supported in interactive report filters?*
thanks in advance
Paul P

Hi Paul,
regular expression functions are supported in interactive report filters, but it looks like that REGEXP_INSTR hasn't been added as valid command. Only REGEXP_SUBSTR and REGEXP_REPLACE are valid commands for computation expressions and REGEXP_SUBSTR, REGEXP_REPLACE and REGEXP_LIKE for row level filters.
I have filed bug# 12926266 to fix this issue. Sorry for the inconvenience.
Regards
Patrick
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Email Regular Expression with a String.Match()

I'm currently using a RichTextEditor for a user to build HTML
for a site. However, I want the application to scan for emails and
encode them so they are protected from spam bots when they go to
the live site. I've written a regular expression to find an email
and it seems to work, but it only returns one email at a time from
the string. I have had to revert to a while loop to traverse the
string until I'm satisfied. I don't particularly like that method
and would like to just do one String.match() query to retrieve all
of the emails. Can anyone see something here that I'm missing?

Try adding the global flag (g):
var emailPattern:RegExp =
/[a-z][\w.-]+@\w[\w.-]+\.[\w.-]*[a-z][a-z]+/g;
TS

Regular expressions and input streams

Hello,
I am trying to find a way to read characters from a stream and find matches in them with regular expressions. The problem is that the stream may contain a big amount of characters, so I can't read all of them, keep them in a big string, and then perform the searches. Is there a way to perform searches while I read the characters? I scanned the documentation of Pattern and Matcher and found nothing that can help.
Any ideas?
Thanks.

Looking at the method
public Matcher Pattern.matcher(CharSequence input);
one could be excused for assuming that one could turn an InputStream into a CharSequence object since a 'stream' implies sequencial access and CharSequence sounds like it provides sequential access.
This would just require the implementation of 4 method of which two (toString() and subSequence()) could probably be ignored BUT the method you wouild have to implement are charAt() and length() which imply random access rather than sequencial access!
Using the built in regex your problem looks difficult. If you are just looking for 'equality' matches (simple searching) then you could use Knuth-Morris-Pratt algorithm or the Boyer-Moore algorithm.

Regular expression - find if string does NOT contain text....

I have a string that I want to tokenize. The string can contain basically anything. I want to produce tokens for each "word" found, and for each "<=" or "," found. There does not need to be whitespace around a "<=" or a "," to consider it a token. So for example:
joe schmoe<=jack, jane
should become
joe
schmoe
<=
jack
jane
As a constraint, I do not want to use StringTokenizer at all, as "its use is discouraged in new code". http://java.sun.com/j2se/1.4.2/docs/api/java/util/StringTokenizer.html
Here's the code I plan on using for this:
    public String[] getWords(String input) {
        Matcher matcher = WORD_PATTERN.matcher(input);
        ArrayList<String> words = new ArrayList<String>();
        while (matcher.find()) {
            words.add(matcher.group());
        return (String[]) words.toArray(new String[0]);
    }The trick, though, is coming up with a working regular expression. The closest I've found yet is:
([^\s]|^(,)|^(<=))+|,|<=
but that produces the following:
joe
schmoe<=jack,
jane
I think what I need is to be able to find if a string does not contain the substring "<=" or "," using a regular expression. Anyone know how to do this, or another way to do this using regular expressions?

Try:
* Tokenizer.java
* version 1.0
* 01/06/2005
package samples;
import java.util.regex.Matcher;
import java.util.regex.Pattern;
* @author notivago
public class StrangeTokenizer {
    public static void main(String[] args) {
        String text = "joe schmoe<=jack, jane";
        Pattern pattern = Pattern.compile( "((?:<=)|(?:,)|(?:\\w+))");
        Matcher matcher = pattern.matcher(text);
        while( matcher.find() ) {
            System.out.println( "Item: " + matcher.group(1) );
}May the code be with you.

Regular expression with delimited string

Hi,
I'm trying extract all characters in a string (as word or words) which is delimited by ' -- '
Been playing around with regular expression and got as far as this;
with t_vw
as (select 'hello -- world' txt from dual
union all
select 'hello-world' from dual
union all
select 'hello' from dual
union all
select 'hello -- world -- bye' from dual
union all
select 'hello--worldbye' from dual
select txt, regexp_substr(txt,'[^ -- ]+',1,1) word1,
regexp_substr(txt,'[^ -- ]+',1,2) word2,
regexp_substr(txt,'[^ -- ]+',1,3) word3
from t_vw;
It's returning;
"TXT","WORD1","WORD2","WORD3"
"hello -- world" "hello","world",""
"hello-world"          "hello","world",""
"hello"               "hello","",""
"hello -- world -- bye"     "hello","world","bye"
"hello--worldbye"      "hello","worldbye",""
So it seems to work in all cases apart from when there are no spaces before/after "--".
Any ideas?

Please enclose your code in *{noformat}{noformat}* tags to preserve your formatting and to prevent the forum software from mangling your regular expressions.
Also, you've given your input and show the output that you are getting, but I don't know what your issue is. If you could include the desired output and explain how it differs from what you are getting so far that would help.

Match Regular Expression Function input string format

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